How can I bundle Lua scripts to single file - build

Question

I need to create single lua file based on source ones.
i.e as input I have some project where there are several modules which use require statements. As output I need single lua file (still source file but bundled) and after that I suppose it will not have any require statements.
How can I do it ?

Answer 1

Iterate through all files and you can replace the require function to something like this:
------------------------------------------------------ HEADER
local files = {}
local globalRequire = require -- Store default require reference
local require = function(path) -- Will return saved file or attempt default lua require
return files[path] or globalRequire(path)
end
------------------------------------------------------ START FILES
files["file1"] = function(...)
------------------------------------------------------ FILE #1 CONTENTS
local hola = require("file2")
local file1 = {}
return file1
------------------------------------------------------ FILES CONTINUE
end
files["file2"] = function(...)
------------------------------------------------------ FILE #2 CONTENTS
local file2 = {}
return file2
------------------------------------------------------ FOOTER
end
------------------------------------------------------ EOF
Notice how in most lua files you return something at the EOF? This is because files in lua are technically functions, so you can do it this way. It is important to also supply the (...) three dot parameter as it also gets passed in to modules, although it usually only contains the module name.
Anyway, you can build a script that puts this together and it should work, or with a few tweaks.