I am trying to figure out how to include a cout with a for loop that leaves off part of the cout on the last iteration. I want to have a multiplication sign (*) after each number (nFact) EXCEPT the last number in the loop.
Current output: 5*4*3*2*1*
Ideal output: 5*4*3*2*1
'''
for (unsigned int i = 0; i < n; i++)
{
nFact = nFact*(n-i);
cout << (n - i)<<"*";
}
'''
for (unsigned int i = 0; i < n; i++)
{
nFact = nFact*(n-i);
if(i!=n-1)
cout << (n - i)<<"*";
else cout << (n - i);
}
You might do:
const char* sep = "";
for (unsigned int i = 0; i < n; i++)
{
nFact *= n - i;
std::cout << sep << n - i;
sep = "*";
}
Demo
Related
so i want output like this
1
123
12345
123
1
i already make the program but it only output these, and im confused how to output the bottom triangle
1
123
12345
here's my program
#include <iostream>
using namespace std;
int main() {
int n = 3 ;
int i, j, k;
for (i = 1; i <= n; i++) {
for (j = n; j > i; j--) {
cout << " ";
}
for (k = 1; k <= (2 * i - 1); k++) {
cout << k;
}
cout <<endl;
}
return 0;
}
#Mojtaba's answer is a perffect extension to your approach.
However, I wanted to provide another method that is generally used in creating such strings that are formatted in a particular manner. It is common to create the entire pattern line by line and then print to the console all at once.
I have appropriately commented the code for your reference and it should be easy to understand:
#include <iostream>
#include <vector>
void pattern(int n) {
std::vector<std::string> lines; // store the first n lines to print later
int length = 2*n - 1; // length of each line
for(int i = 0; i < n; i++) {
std::string str = std::string(length, ' ');
for(int j = 1; j <= 2*i + 1; j++) {
str[n - i + j - 2] = j + '0';
// indexing can be figured by observing the pattern
}
lines.emplace_back(str);
}
for(int i = 0; i < n; i++) {
std::cout << lines[i] << std::endl;
}
for(int i = n-2; i >= 0; i--) {
std::cout << lines[i] << std::endl;
}
return;
}
int main() {
int n;
std::cin >> n;
pattern(n);
}
I added another for loop exactly like yours with different order from n-1. I modified your code to this:
int main() {
int n = 3 ;
int i, j, k;
for (i = 1; i <= n; i++) {
for (j = n; j > i; j--) {
cout << " ";
}
for (k = 1; k <= (2 * i - 1); k++) {
cout << k;
}
cout <<endl;
}
for (i = n - 1; i >= 1; i--) {
for (j = n; j > i; j--) {
cout << " ";
}
for (k = 1; k <= (2 * i - 1); k++) {
cout << k;
}
cout <<endl;
}
return 0;
}
Now it returns:
1
123
12345
123
1
I have a line of code that when inputted 3, the result will print out a series of dashes and asterisks to form a diamond:
Expected Input:
3
Expected Output:
--*--
-***-
*****
-***-
--*--
what i have so far is the triangle but I can' seem to get rid of the middle line to make it a full diamond shape. Also "-" is not printing on the right side of the bottom half
this is the code I have made
int n;
cin >> n;
for (int left_stars = 0; left_stars < n; left_stars++) {
for (int column = 0; column < 2 * n - 1; column++) {
int first_star = n - 1 - left_stars;
int last_star = n - 1 + left_stars;
if (column < first_star || column > last_star) {
cout << "-";
} else {
cout << "*";
}
}
cout << endl;
}
for(int i = n; i >= 1; --i) {
for(int space = 0; space < n-i; ++space) {
cout << "-";
}
for(int j = i; j <= 2*i-1; ++j) {
cout << "*";
}
for(int j = 0; j < i-1; ++j) {
cout << "*";
}
cout << endl;
}
return 0;
For removing the double full star line use following code line
for (int i = n-1; i >= 1; --i) {
instead of
for(int i = n; i >= 1; --i) {
(side note: maybe you want to check as suggested by yaodav if you could not write the second part like the first part).
I need a Number pyramid identical to this one:
1
121
12321
1234321
123454321
12345654321
I am new to programming and if anyone would't mine running through the code and telling me how each line is being understood by the compiler.
I heard there was a way to do this with embedded while loops. If anyone knows how to do that and can show me, that would be great.
The code I have is partially from the internet and not solely mine.
for (int i = 1; i <= rows; ++i)
{
for (int space = 1; space <= rows - i; ++space)
{
cout << " ";
++count;
}
while (k != 2 * i - 1)
{
if (count <= rows - 1)
{
cout << i << " ";
++count;
}
else
{
++count1;
cout << i + k - 2 * count1 << " ";
}
++k;
}
count1 = count = k = 0;
cout << endl;
}
cout << "\n\n\n";
system("PAUSE");
Try this code:
int main(void) {
int i, j, k, l, n = 6;
for (i = 1; i <= n; i++) {
for (j = 1; j <= n - i; j++) {
cout << " ";
}
for (k = 1; k <= i; k++) {
cout << k;
}
for (l = i - 1; l >= 1; l--) {
cout << l;
}
cout << "\n";
}
return 0;
}
If I enter an array , at first the code finds the minimums then I want to put zeroes after all the minimums . For example
given an array = 1,1,3,1,1
As we see 1s are the minimum so the result should be = 1,0,1,0,3,1,0,1,0
CODE
#include <pch.h>
#include <iostream>
int main()
{
int min = 10000;
int n;
std::cout << "Enter the number of elements (n): "; //no of elements in the
std::cin >> n; //array
int *array = new int[2 * n];
std::cout << "Enter the elements" << std::endl;
for (int i = 0; i < n; i++) {
std::cin >> array[i];
if (array[i] > min)
min = array[i];
}
for (int i = 0; i < n; i++) {
if (array[i] == min) { // Not very clear about this
for (int k = n; k > i; k--) // part of the code, my teacher
array[k] = array[k - 1]; //explained it to me , but i
array[i + 1] = 0; // didn't understand (from the
i++; // `for loop k` to be precise)
n++;
}
std::cout << array[i] << ", 0";
}
return 0;
}
But my answer doen't put zeroes exactly after minimums
There are few issues in your code, first of all your min is wrong. I have fixed your code with comments on fixes I have made. Please take a look :
#include "stdafx.h"
#include <iostream>
int main()
{
int min = 10000;
bool found = 0;
int n;
std::cout << "Enter the number of elements (n): "; //no of elements in the
std::cin >> n; //array
int *array = new int[2 * n];
std::cout << "Enter the elements" << std::endl;
for (int i = 0; i < n; i++) {
std::cin >> array[i];
if (array[i] < min) //< instead of >
min = array[i];
}
for (int i = 0; i < n; i++) {
if (array[i] == min)
{
for (int k = n; k > i; k--)
{
array[k] = array[k - 1];
}
array[i + 1] = 0;
i++; //increment i here because you don't want to consider 0 that you have just added above.
n++; //since total number of elements in the array has increased by one (because of 0 that we added), we need to increment n
}
}
//print the array separately
for (int i = 0; i < n; i++)
{
std::cout << array[i];
if (i != n - 1)
{
std::cout << ",";
}
}
return 0;
}
The first issue was in the calculation of min: < instead of >.
Another problem if that you are modifyng the paramers iand ninside the loop. This is rather dangerous and implies to be very cautious.
Another issue was that it should be i++; n++; instead of i--,n--;
Here is the code:
// #include <pch.h>
#include <iostream>
int main()
{
int min = 1000000;
int n;
std::cout << "Enter the number of elements (n): "; //no of elements in the
std::cin >> n; //array
int *array = new int[2 * n];
std::cout << "Enter the elements" << std::endl;
for (int i = 0; i < n; i++) {
std::cin >> array[i];
if (array[i] < min)
min = array[i];
}
for (int i = 0; i < n; i++) {
if (array[i] == min) { // Not very clear about this
for (int k = n; k > i; k--) // part of the code, my teacher
array[k] = array[k - 1]; //explained it to me , but i
array[i + 1] = 0; // didn't understand (from the)
i++;
n++;
}
}
for (int i = 0; i < n; i++) {
std::cout << array[i] << " ";
}
std::cout << "\n";
return 0;
}
in this program i am separating integers from a character array which consists of a space between them
#include<iostream>
#include<stdio.h>
#include<conio.h>
using namespace std;
int main()
{
int i = 0, t, l = 0, j, c, k, q = 0, num = 0;
char ch[10][10];
int ach[10][1];
cout << "enter the number of test cases";
cin >> t;
for (i = 0; i < t; i++)
{
fflush(stdin);
cin.getline(ch[i], 9);
}
for (i = 0; i < t; i++)
{
num = 0;
for (j = 0; ch[i][j] != '\0'; j++) //calculating length
{
l = j;
}
l = l + 1;
for (j = 0; j < l; j++)
{
if (ch[i][j] == ' ') //finding the space
c = j;
}
for (k = 0; k < c; k++) //taking first integer out of char array
{
q = ch[i][k] - 48; //parsing char to int
num = (num * 10) + q;
}
cout << "\n previous row element " << ach[0][1] << "\n"; //checking the value
ach[i][0] = num; // this statement is updating the previous row's last element of the array
cout << "\n previous row element " << ach[0][1] << "\n"; //checking the value
cout << ach[i][0];
num = 0;
q = 0;
for (k = c + 1; k < l; k++) //taking second element out of char array
{
q = ch[i][k] - 48; //parsing char to int
num = (num * 10) + q;
}
ach[i][1] = num;
cout << ach[i][1];
}
for (i = 0; i < t; i++)
{
cout << "\n" << ach[i][0] << "\t" << ach[i][1] << "\n"; //displaying the values
}
getch();
return 0;
}
I have marked the code that is malfunctioning , it is updating the previous row's last element. please help.
Oups your code is not really optimized and is mainly C with the exception of cin.getline. But your real problem is that with int ach[10][1], ach is a 2D array of size 10x1, so ach[i][1] may not be what you expect because you should define int ach[10][2] to safely use it. The rules for array indexes computing give &(ach[i][1]) == &ach[0][0] + i*1 + 1 so you are actually accessing ach[i+1][0] with a possible past end array access if i is 9.
Moreover, at first access, ach[0][1] is used without being first initialized.
So your ach definition should be:
int ach[10][2] = {0};