I have a simple blog where the post model contains a slug field that is prefilled with the post title. I would like to know how to get this slug updated in the background when the user updates a post title in the viewUpdate:
models.py
class Post(models.Model):
title = models.CharField(max_length=150)
content = models.TextField()
date = models.DateTimeField(auto_now_add=True)
author = models.ForeignKey(
CustomUser,
on_delete=models.CASCADE
)
slug = models.SlugField(unique=True)
def get_absolute_url(self):
return reverse('post_detail', kwargs={'slug': self.slug})
def save(self, *args, **kwargs):
self.slug = self.slug or slugify(self.title)
super().save(*args, **kwargs)
urls.py
urlpatterns = [
path('post/<slug:slug>/', views.PostDetailView.as_view(), name='post_detail'),
]
views.py
class PostUpdateView(UpdateView):
model = Post
fields = ['title', 'content', 'tags']
I assume I should add something else to view.py in order to have the slug updated but after hours googling it, I could not find it.
Please let me know if you need more information. It is quite a simple question so I am not sure if I should provide anything else.
You can change the savemethod to:
class Post(models.Model):
# …
def save(self, *args, **kwargs):
self.slug = slugify(self.title)
super().save(*args, **kwargs)
That being said, it is not per se a good idea to change the slug. A slug is usually used in a URL. That thus means that if a URL for a Post is for example bookmarked by a user, and later the title changes, then that URL will no longer work. Terefore a slug is usually something that should not be modified (often). In fact in most content management systems (CMS), the slug does not change, and you can look at the URL to see the original title of the article.
Related
Hello I have a function to auto generate data for my SlugField but i dont know how to implement a save method to execute it. Ive tried calling the function from the save method but it raises an error of 'instance not defined'. Any suggestions will help. Thanks.
def ran_str_gen(size=6, chars=string.ascii_letters + string.digits):
return ''.join(secrets.choice(chars) for s in range(size))
def slug_gen(instance, new_slug=None):
if new_slug is not None:
slug=new_slug
else:
slug = slugify(instance.title)
op = instance.__class__
qs_exists = op.objects.filter(slug=slug).exists()
if not qs_exists:
new_slug = '{slug}-{ranstr}'.format(slug=slug, ranstr=ran_str_gen())
return slug_gen(instance, new_slug=new_slug)
return slug
class Item(models.Model):
title = models.CharField(max_length=100)
price = models.FloatField()
slug = models.SlugField()
def save(self, *args, **kwargs):
slug_gen()
You should pass the instance (self) to the slug_gen function, store the result in the slug field, and then make a super() call to save the model effectively, so:
class Item(models.Model):
title = models.CharField(max_length=100)
price = models.FloatField()
slug = models.SlugField()
def save(self, *args, **kwargs):
self.slug = slug_gen(self)
super().save(*args, **kwargs)
Note: You can make use of django-autoslug [GitHub] to automatically create a slug based on other field(s).
Note: Normally you should not change slugs when the related fields change. As is written in the article Cool URIs don't change [w3.org], URIs are not supposed to change, since these can be bookmarked. Therefore the slug should only be created when creating the object, not when you change any field on which the slug depends.
def save(self, *args, **kwargs):
self.slug=slug_gen()
Error with a slug in Django - template it shows all posts data in each post
when I create a new post and write my data it shows all data from other posts why is that?
and how I can fix it?
also how I can add an auto-generation slug?
models.py :
from django.urls import reverse
from django.utils.text import slugify
class Android(models.Model):
title = models.CharField(max_length=50,default="",help_text="this is title for slug not post!")
name = models.CharField(max_length=50,default="")
app_contect = models.CharField(max_length=240,default="")
app_image = models.ImageField(upload_to='images/',null=True, blank=True)
post_date = models.DateTimeField(auto_now_add=True, null=True, blank=True)
post_tag = models.CharField(max_length=50,default="",choices = BLOG_SECTION_CHOICES)
slug = models.SlugField(null=True,uniqe=True) # new
def get_absolute_url(self):
return reverse('android_posts', kwargs={'slug': self.slug}) # new
def get_image(self):
if self.app_image and hasattr(self.app_image, 'url'):
return self.app_image.url
else:
return '/path/to/default/image'
def __str__(self):
return self.name
class Meta:
ordering = ('-post_date',)
views.py :
def android_posts(request,slug):
android_posts = Android.objects.all()
context = {'android_posts':android_posts}
return render(request,'android/android_problems_fix.html', { 'android_posts': android_posts })
html page :
{% for android in android_posts %}
<h1 id="font_control_for_header_in_all_pages">{{android.name}}</h1>
<hr>
<p id="font_control_for_all_pages">{{android.app_contect}}</p>
{% endfor %}
url :
path('Android/<slug:slug>', views.android_posts, name='android_posts'),
To autogenerate your slug (and only do it on initial save, so that it remains consistent), add the generation to your model save method:
def save(self, *args, **kwargs):
super(<Model>, self).save(*args, **kwargs)
if not self.pk:
self.slug = <slugify code here>
As for your view/Template, you are specifically selecting all posts using:
android_posts = Android.objects.all()
Passing them to the template, then looping over them with the for loop to display them all.
Instead of this, select only a single object with:
android_post = Android.object.get(pk=<pk value>)
Edit after you added your urls.py:
You can get the unique object for a slug with:
android_post = get_object_or_404(Android, slug=slug)
The use of get_object_or_404 will also handle the case where that record doesn't exist.
You haven't posted your urls.py, so not sure how you're linking to this view, but if it includes the slug in the url, you will be able to get this in the view. My guess is you're not accessing via slug in the url, but via the id field.
Personally, when I slugify some text, I always include the id - it is a better way of ensuring uniqueness. By specifying unique=True on your non-pk slug field, you are likely restricting the titles people can use (2 people couldn't use the same title then!)
To give you an example, this is how I am doing it on one of my models:
def save(self, *args, **kwargs):
if not self.id or not self.slug:
super(Android, self).save(*args, **kwargs)
self.slug = slugify(f"{self.title} {str(self.id)}")
super(Android, self).save(*args, **kwargs)
This slug will always be unique because it includes id - and 2 people could have a record with the same title value without the system objecting.
I have an app that will one day allow front-end crud, which will create the slug with slugify. Right now though, all the object creation is being done in the admin area and I was wondering if there is a way to auto generate slugs while creating and saving an object from within admin?
Here is the method for slugify for the front-end; not sure if its even relevant. Thank you.
def create_slug(instance, new_slug=None):
slug = slugify(instance.title)
if new_slug is not None:
slug = new_slug
qs = Veteran.objects.filter(slug=slug).order_by('-id')
exists = qs.exists()
if exists:
new_slug = '%s-%s' % (slug, qs.first().id)
return create_slug(instance, new_slug=new_slug)
return slug
Having just used this on another answer, I have exactly the right code in my clipboard. I do exactly this for one of my models:
from django.utils.text import slugify
class Event(models.Model):
date = models.DateField()
location_title = models.TextField()
location_code = models.TextField(blank=True, null=True)
picture_url = models.URLField(blank=True, null=True, max_length=250)
event_url = models.SlugField(unique=True, max_length=250)
def __str__(self):
return self.event_url + " " + str(self.date)
def save(self, *args, **kwargs):
self.event_url = slugify(self.location_title+str(self.date))
super(Event, self).save(*args, **kwargs)
Above solutions break validation in the Django Admin interface. I suggest:
from django import forms
from django.http.request import QueryDict
from django.utils.text import slugify
from .models import Article
class ArticleForm(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(ArticleForm, self).__init__(*args, **kwargs)
# Ensure that data is a regular Python dictionary so we can
# modify it later.
if isinstance(self.data, QueryDict):
self.data = self.data.copy()
# We assume here that the slug is only generated once, when
# saving the object. Since they are used in URLs they should
# not change when valid.
if not self.instance.pk and self.data.get('title'):
self.data['slug'] = slugify(self.data['title'])
class Meta:
model = Article
exclude = []
I have been searching here and reading the documentation and experimenting in python, but I can't find a solution to my particular mess. I did the Django tutorial, but I'm still confused as to how to pass stuff thru the URL in django when starting to use foreign keys, I'm sure it's pretty simple. I'm a new django user and this is my first post. I have the models Playlist, and PlaylistEntry with mixed relationships to user and videos (not posted). I'm trying to show a detail view that uses a slug of a playlist title, to pull out entries in the playlist. Eg. In python, I can do
entries = PlaylistEntry.objects.filter(playlist__slug='django')
which returns all my entries in the playlist 'Django' correctly.
Here are my models...
class Playlist(models.Model):
class Meta:
verbose_name_plural = 'playliztz'
title = models.CharField(blank=True,
help_text=u'Title of playlist',
max_length=64,
)
user = models.ForeignKey('userprofile.UserProfile',
blank=False,
help_text=u'owns this playlist',
null=False, )
slug = models.SlugField(u'slug',
max_length=160,
blank=True,
editable=False
)
created = models.DateTimeField(editable=False)
modified = models.DateTimeField(editable=False)
def __unicode__(self):
return self.title
def get_absolute_url(self):
return reverse('playlist-detail', kwargs={'pk': self.pk})
def save(self):
self.slug = slugify(self.title)
if not self.id:
self.created = datetime.datetime.today()
self.modified = datetime.datetime.today()
super(Playlist,self).save()
class PlaylistEntry(models.Model):
class Meta:
verbose_name_plural = "playlist entries"
video = models.ForeignKey('video.Video',
blank=True,
default=None,
help_text=u'the video title',
null=True, )
playlist = models.ForeignKey('Playlist',
blank=True,
default=None,
help_text=u'Belongs to this playlist',
null=True,)
def __unicode__(self):
return self.video.video_title
My URLS looks like this...
url(r'^playlist/$', PlaylistList.as_view(), name='user_playlists'),
url(r'^playlist/(?P<slug>[0-9A-Za-z-_.//]+)/$', PlaylistDetail.as_view(), name='playlist_entries'),
And my Views.py looks like this...
class PlaylistList(LoggedInMixin, ListView): # shows a list of playlists
template_name = 'userprofile/playlist_list.html'
model = Playlist
context_object_name = 'playlist_list'
def get_queryset(self):
"""Return currently users playlists."""
return Playlist.objects.filter(user__user=self.request.user)
def get_context_data(self, **kwargs):
context = super(PlaylistList, self).get_context_data(**kwargs)
if not self.get_queryset():
context['error'] = "You don't have any playlists yet."
return context
else:
return context
class PlaylistDetail(LoggedInMixin, DetailView):
model = PlaylistEntry
template_name = 'userprofile/playlist_detail.html'
def get_queryset(self):
self.current_playlist = get_object_or_404(Playlist, slug=self.kwargs['slug'])
# CHECK - Prints out correct entries for playlist in slugfield (current_playlist)
self.entries = PlaylistEntry.objects.filter(playlist__title=self.current_playlist.title)
print self.entries
# Should expect to return the same queryset?
return PlaylistEntry.objects.filter(playlist__title=self.current_playlist.title)
def get_context_data(self, **kwargs):
context = super(PlaylistEntry, self).get_context_data(**kwargs)
context['entries'] = PlaylistEntry.objects.all()
return context
self.entries prints the correct entries for this playlist in the Check bit.
In my playlist template I am using a link sending the playlist.slug - the url looks correct like this /user/playlist/this-particular-playlist-slug.
the error is...
Cannot resolve keyword u'slug' into field. Choices are: id, playlist, video
You've made things much more complicated than they need to be.
The model for your detail view should still be Playlist, not PlaylistEntry. The reason you're getting that error is that the slug is on the Playlist model, but you've told the view to filter on PlaylistEntry.
What you actually want to to is to pass the single Playlist identified by the slug into the template. From there, you can easily iterate through the detail objects associated with that playlist via the reverse relation.
So, change that model setting, and drop both get_context_data and get_queryset from the detail view: you don't need them. Then in the template you can simply do:
{% for entry in playlist.playlistentry_set.all %}
Is it possible to Post Foreign Data in Django Rest Framework rather than the "ID" of the data? I was looking into HyperlinkedModelSerializer, however I felt that there wasn't enough documentation on the DRF website. I have two models. Showtime has a link to Cinema.
class Cinema(models.Model):
name = models.TextField("Name",)
slug = models.SlugField("Slug",blank=True)
phone = models.TextField("Phone")
phone2 = models.TextField("Secondary Phone", blank=True, null=True)
email = models.EmailField("Email")
website=models.TextField("Website")
location = models.TextField("Location")
def __unicode__(self):
name = (self.name).title()
return name
def save(self, *args, **kwargs):
self.slug = slugify(self.name)
super(Cinema, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse('Cinema:detail', kwargs = {'slug': self.slug })
class Showtime(models.Model):
cinema = models.ForeignKey(Cinema)
showDate = models.TextField("Date",)
showTime = models.TextField("Time",)
slug = models.SlugField("Slug", blank=True, unique=True)
def save(self, *args, **kwargs):
self.slug = uuid.uuid4()
super(Showtime, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse('Showtime:detail', kwargs = {'slug': self.slug})
Each model have been serialized using DRF. Is is possible to post Cinema Data via the Showtime API View rather than have to post cinema in Cinema API View first then get ID of that field then post via the Showtime View to link the data?
Basically, All I want is full writable Foreign Key support, or Does DRF support something like get_or_create() ?
You can nest serializers. See the docs at http://www.django-rest-framework.org/api-guide/serializers#dealing-with-nested-objects for an example.