My data looks like:
id state value
1 abc x
1 bcd y
1 def z
2 abc p
2 bcd q
2 def r
3 bcd m
3 def n
I am trying to vlookup the value for id 1, 2 and so on, but where the state is not abc. Excel automatically picks the first entry and I tried with if condition on the column but am unable to get it work. I even tried Index Match with an if condition inside match, but that didn't work either.
Is there a way I could do it?
Use Filter:
=index(filter(C2:C9,A2:A9=1,B2:B9<>"abc"),1)
if you want all that meet the criteria, remove the INDEX wrapper:
filter(C2:C9,A2:A9=1,B2:B9<>"abc")
try:
=FILTER(C:C, B:B<>"abc", REGEXMATCH(A:A&"", "1|2"))
or just:
=FILTER(C:C, B:B<>"abc")
for partial abc you can do:
=FILTER(C:C, NOT(REGEXMATCH(B:B, "abc")))
Related
Maybe the solution is to do it with Filter and then loop. But let's see if you guys can tell me a way to do it with GET
I have this query with GET as I need to be sure I get only one result
result = OtherModel.objects.get(months_from_the_avail__lte=self.obj.months_from_avail)
Months_from_avail is an Integer value.
Example
months_from_the_avail = 22
In the other model there's 3 lines.
A) months_from_the_avail = 0
B) months_from_the_avail = 7
C) months_from_the_avail = 13
So, when I query it returns all of them as all are less than equal the value 22 but I need to get the 13 as is the last range.
range 1 = 0-6
range 2 = 7-12
range 3 = 13 ++
Is there any way that I haven't thought to do it? Or should I change it to filter() and then loop on the results?
you can get the first() section from the query order_by months_from_the_avail
Remember that django query are lazy, it won't execute until the query if finished calling so you can still use filter:
result = OtherModel.objects.filter(months_from_the_avail__lte=self.obj.months_from_avail).order_by('-months_from_the_avail').first()
#order by descending get first object which is the largest, return None if query set empty
another suggestion from Abdul which i think it's faster and better is using latest()
OtherModel.objects.latest('-months_from_the_avail')
I have got a data frame like this:
ID A B
1 x5.11 2,34
2 x5.57 5,36
3 x6,13 0,45
I would like to remove the 'x' of all values of the column A. How might I best accomplish this in R.
Thanks!
I have found a very easy way:
data.frama$A <- gsub("x", "", data.frame$A)
I got stuck with a specific question in R around concatenating columns of a data frame by using a wildcard. Perhaps I am searching wrongly. However I could not find a matching answer yet.
Here is my question:
I have a data frame df where each column represents a user (U1, U2, U3), e.g.:
> df <-data.frame(U1=1:3, U2=4:6, U3=7:9)
> df
> U1 U2 U3
1 1 4 7
2 2 5 8
3 3 6 9
I would like to concatenate the values from all users into a single vector as one would do using the c() function, e.g.:
> c(df$U1, df$U2, df$U3)
[1] 1 2 3 4 5 6 7 8 9
However, my number of users is large and varies over time. So, I look for an elegant dynamic way of concatenating the columns such as
> c(df$U*)
Unfortunately this does not seem to work. I played around with grep and regular expressions but could not get it to work. For sure, I could use a for-loop and program my own cat function but I assume there is a better way. I just don't find it. Maybe I am just blind. Hope you can help.
sub_df <- df[, grep(pattern ='^U.*', names(df))]
stack(df)$values
Hope this works for you. You could first subset some columns according to your need.
Coerce the data frame to a matrix first:
as.vector(as.matrix(df))
Use the bracket [ to select columns whose names match a certain expression:
df[, grep("U.*", colnames(df)), drop = FALSE]
I was trying to run a loop through a variable and was unsure how to code up my thoughts. So, I have variable called newid that goes as
newid
1
1
2
2
3
3
and so on.
foreach x in newid2 {
replace switchers = 1 if doc[_n] != doc[_n+1]
}
I want to modify this code so that this code will run for each two values (in this case run for 1 and 1, 2 and 2). What would be the best way to modify this? Please help me
Something like this can be done with levelsof:
clear
input id str1 doc
1 "A"
1 "B"
2 "A"
3 "C"
3 "A"
end
gen switcher1 = 0
levelsof id
foreach i in `r(levels)' {
quietly tab doc if id==`i'
replace switcher1 = 1 if r(r)>1 & id==`i'
}
However, you there are certainly more efficient ways to accomplish your goal. Here's one example that tags ids that switch doctors:
ssc install egenmore
bysort id: egen num_docs = nvals(doc)
generate switcher2 = cond(num_docs>1,1,0)
The underlying idea is the same. You count the number of distinct values of doc for each id. If that number exceeds one, the id is tagged as a switcher. The second version is arguably more efficient since it does not involve looping over each value of id.
I have a query that's basically "count all the items of type X, and return the items that exist more than once, along with their counts". Right now I have this:
Item.objects.annotate(type_count=models.Count("type")).filter(type_count__gt=1).order_by("-type_count")
but it returns nothing (the count is 1 for all items). What am I doing wrong?
Ideally, it should get the following:
Type
----
1
1
2
3
3
3
and return:
Type, Count
-----------
1 2
3 3
In order to count the number of occurrences of each type, you have to group by the type field. In Django this is done by using values to get just that field. So, this should work:
Item.objects.values('group').annotate(
type_count=models.Count("type")
).filter(type_count__gt=1).order_by("-type_count")
It's logical error ;)
type_count__gt=1 means type_count > 1 so if the count == 1 it won't be displayed :)
use type_count__gte=1 instead - it means type_count >= 1 :)