image made from dots and letters c++ - c++

Question

very basic Q as I just started with coding but I stuck at some point and have 0 ideas what to do.
I need to write code to get diamond shape made from dots and X letters, size based on a value (n) provided by the user, (3 ≤ n ≤ 80).
for example:
As I mentioned - I have almost 0 experience so all I could get is is this shape for n=6
height is ok, same as widht but unfortunately, the amount of X's and placement isn't correct :/
my code:
int h;
cerr << "Provide size of diamond: ";
cin >> h;
for (int i = 1; i <= h; i++)
{
for (int k = 1 ; k <= h-i ; k++)
{
cout << ".";
}
for (int j = 1; j <= i ; j++)
{
cout << "X";
}
cout << endl;
Thank you all good people who will help mi with this one :)

Answer 1

I help to draw points. I hope you, looking on my change, are able to update your code further to achive the required picture.
for (int i = 1; i <= h; i++)
{
for (int k = 1 ; k <= (h-i) / 2 ; k++)
{
cout << ".";
}
for (int j = 1; j <= i ; j++)
{
cout << "X";
}
for (int k = 1 ; k <= (h-i) / 2 ; k++)
{
cout << ".";
}
cout << endl;
}

Answer 2

In this kind of problems you can divide the problems in different parts. Such as for n=6 the image can be divided in 4 mirror images:
..X
.XX
XXX
then,
X..
XX.
XXX
and upside down mirror of them.
You said that you can draw the first one. I think if you give some more time you will be able to print the full image too.
But, if you have problems, here's the code for that
for (int i = 1; i <= h; i++) {
if((h-i)%2) continue;
for (int j = 1 ; j <= (h-i) / 2 ; j++) {
cout << ".";
}
for (int j = 1; j <= i ; j++) {
cout << "X";
}
for (int j = 1 ; j <= (h-i) / 2 ; j++) {
cout << ".";
}
cout << endl;
}
for (int i = (h/2)*2; i > 0; i--) {
if((h-i)%2) continue;
for (int j = 1 ; j <= (h-i) / 2 ; j++) {
cout << ".";
}
for (int j = 1; j <= i ; j++) {
cout << "X";
}
for (int j = 1 ; j <= (h-i) / 2 ; j++) {
cout << ".";
}
cout << endl;
}

Answer 3

Since this is tagged as a c++ question let's use std::string and three loops.
#include <iostream>
#include <string>
void print_diamond(int n)
{
int np = n / 2, nm = (n - 1) / 2;
int npl = np, nml = nm;
std::string str(n, '.');
for (int i = 0; i < nm; i++)
{
str[npl++] = 'X'; str[nml--] = 'X';
std::cout << str << std::endl;
}
for (int i = nm; i <= np; i++)
{
str[npl] = 'X'; str[nml] = 'X';
std::cout << str << std::endl;
}
for (int i = np; i < n - 1; i++)
{
str[npl--] = '.'; str[nml++] = '.';
std::cout << str << std::endl;
}
std::cout << std::endl;
}
Print all diamond for a shinier world...
int main()
{
for (int n = 3; n < 81; n++)
{
print_diamond(n);
}
}