How to render template after failed form validation? - django

Question

urls.py:
urlpatterns = [
path('employee/add_employee/', views.add_employee, name='add-employee'),
path('employee/add_employee/add/', views.add_employee_action, name='add-employee-action'),
]
I have add-employee page and some forms to fill there.
views.py:
def add_employee(request):
personal_form = PersonalEmployeeForm()
history_form = EmployeeHistoryForm()
return render(
request,
'sections/add_employee.html',
context={
'personal_form': personal_form,
'history_form': history_form,
}
)
def add_employee_action(request):
if request.method == "POST":
personal_form = PersonalEmployeeForm(request.POST)
history_form = EmployeeHistoryForm(request.POST)
if personal_form.is_valid() and history_form.is_valid():
# here is some logic with models
return redirect('add-employee')
else:
personal_form = PersonalEmployeeForm()
history_form = EmployeeHistoryForm()
return render(
request,
'sections/add_employee.html',
context={
'personal_form': personal_form,
'history_form': history_form,
}
)
template:
<form id="a-submit-form" action="add/" method="POST">
{% csrf_token %}
<div class="column-wrapper">
<div class="column">
<div class="form-wrapper">
{% for field in personal_form.visible_fields %}
{% include "elements/forms/form_line.html" %}
<br>
{% endfor %}
</div>
</div>
<div class="column">
<div class="form-wrapper">
{% for field in history_form.visible_fields %}
{% include "elements/forms/form_line.html" %}
<br>
{% endfor %}
</div>
</div>
</div>
<div class="button-bar-wrapper">
<div class="button_bar">
<a class="a-button positive" id="submit">Добавить</a>
<a class="a-button" href="{% url 'employee' %}">Сотрудники</a>
<a class="a-button" href="{% url 'index' %}">На главуную</a>
</div>
</div>
</form>
Submitting by <a> element is tested and worked well with jQuery script.
The problem is after submitting invalid forms I have a page with blah-blah/employee/add_employee/add/ URL. And if I try to submit forms again I have a page with blah-blah/employee/add_employee/add/add/ URL, which is incorrect. How can I render the page with blah-blah/employee/add_employee/ URL and show all error messages?

Answer 1

This is likely because you have written a relative URL in the <form> tag of the sections/add_employee.html template. The template thus contains something like:
<form method="post" action="add/">
...
</form>
You can use a URL with the {% url … %} template tag [Django-doc]:
<form method="post" action="{% url 'add-employee-action' %}">
...
</form>
Furthermore one usually uses the same path to handle both the GET and the POST request. So in fact you might simply remove the 'add-employee' path.