How do I get the decimal values of Unicode Character such as "Ồ"
std::string a = "Ồ";
unsigned char c = a[0];
long val = long(c);
cout << val << endl;
OUTPUT
7,891;
Your question may look pretty straight-forward but as we delve into it, we'll find it isn't as simple as it might first appear.
The first problem is that std::string is defined as std::basic_string<char> which isn't really compatible with "Ồ". Thus the results you get from your code will probably depend on the compiler you use and/or the environment and OS you are running on. For example, my copy of Visual Studio treats "Ồ" as an invalid ASCII character and puts "?" (or 0x3F) in `a[0]'.
The second problem is that the character "Ồ" is more than eight bits wide, so it may not fit into the variable c. Whatever the compiler put into a[0], the variable c will only hold char bits of that value. Again, the results you get are likely to change depending on the compiler you use and/or the environment you run in.
Leaving that aside, let's start by assuming the character "Ồ" is LATIN CAPITAL LETTER O WITH CIRCUMFLEX AND GRAVE (0x1ED2). With that assumption, one might imagine that the answer we are seeking to get is 0x1ED2 right? But not necessarily.
There are several ways to encode a Unicode character. The UTF-32 encoding is 0x1ED2 (or 0x00001ED2 if we include all the leading zeros to get thirty-two bits). The UTF-8 encoding is 0xE1BB92.
So the decimal value of "Ồ" is 7,890 if it is encoded in UTF-32 or 14,793,618 if it is encoded in UTF-8 (I'm ignoring the effects of endianness to keep things simple)
The Unicode site has a FAQ on encodings and Wikipedia has a page too.
As you can see, the answer to your question (to some extent) depends on the encoding you want to use. One C++ way to deal with encodings is std::codecvt. Another solution is to just treat your string as a sequence of bytes - which your code attempts to do - but that rather depends on you knowing how your system encodes strings, what endianness you are dealing with, etc. And the code won't necessarily be portable.
Another wrinkle to consider is that - in the general case - "Ồ" might not be one character. Obviously it is one character in your code. But if you read a string in from a disk file say and when printed or displayed that file produces "Ồ" we can't assume the file contains a single "Ồ" character.
Unicode defines COMBINING CIRCUMFLEX ACCENT (0x0302) and COMBINING GRAVE ACCENT (0x0300) as separate characters which can be combined with other characters. And it defines intermediate characters like LATIN CAPITAL LETTER O WITH GRAVE and LATIN CAPITAL LETTER O WITH ACUTE so there are actually several ways you can create a string in memory (or in a disk file) that would give you the same effect as the character "Ồ".
Related
string s="x1→(y1⊕y2)∧z3";
for(auto i=s.begin(); i!=s.end();i++){
if(*i=='→'){
...
}
}
The char comparing is definitely wrong, what's the correct way to do it? I am using vs2013.
First you need some basic understanding of how programs handle Unicode. Otherwise, you should read up, I quite like this post on Joel on Software.
You actually have 2 problems here:
Problem #1: getting the string into your program
Your first problem is getting that actual string in your string s. Depending on the encoding of your source code file, MSVC may corrupt any non-ASCII characters in that string.
either save your C++ file as UTF-16 (which Windows confusingly calls Unicode), and use whcar_t and wstring (effectively encoding the expression as UTF-16). Saving as UTF-8 with BOM will also work. Any other encoding and your L"..." character literals will contain the wrong characters.
Note that other platforms may define wchar_t as 4 bytes instead of 2. So the handling of characters above U+FFFF will be non-portable.
In all other cases, you can't just write those characters in your source file. The most portable way is encoding your string literals as UTF-8, using \x escape codes for all non-ASCII characters. Like this: "x1\xe2\x86\x92a\xe2\x8a\x95" "b)" rather than "x1→(a⊕b)".
And yes, that's as unreadable and cumbersome as it gets. The root problem is MSVC doesn't really support using UTF-8. You can go through this question here for an overview: How to create a UTF-8 string literal in Visual C++ 2008 .
But, also consider how often those strings will actually show up in your source code.
Problem #2: finding the character
(If you're using UTF-16, you can just find the L'→' character, since that character is representable as one whcar_t. For characters above U+FFFF you'll have to use the wide version of the workaround below.)
It's impossible to define a char representing the arrow character. You can however with a string: "\xe2\x86\x92". (that's a string with 3 chars for the arrow, and the \0 terminator.
You can now search for this string in your expression:
s.find("\xe2\x86\x92");
The UTF-8 encoding scheme guarantees this always finds the correct character, but keep in mind this is an offset in bytes.
My comment is too large, so i am submitting it as an answer.
The problem is that everybody is concentrating on the issue of different encodings that Unicode may use (UTF-8, UTF-16, UCS2, etc). But your problems here will just begin.
There is also an issue of composite characters, which will really mess up any search that you are trying to make.
Let's say you are looking for a character 'é', you find it in Unicode as U+00E9 and do your search, but it is not guaranteed that this is the only way to represent this character. The document may also contain U+0065 U+0301 combination. Which is actually exactly the same character.
Yes, not just "character that looks the same", but it is exactly the same, so any software and even some programming libraries will freely convert from one to another without even telling you.
So if you wish to make a search, that is robust, you will need something that represents not just different encodings of Unicode, but Unicode characters themselves with equality between Composite and Ready-Made chars.
I want to add a diacritic mark to my string in c++. Assume I want to modify wordz string in a following manner:
String respj = resp[j];
std::string respjz1 = respj; // create respjz1 and respjz2
std::string respjz2 = respj;
respjz1[i] = 'ź'; // put diacritic marks
respjz2[i] = 'ż';
I keep receiving: wordş and wordĽ (instead of wordź and wordż). I tried to google it but I keep getting results related to the opposite problem - diacritic normalization to non-diacritic mark.
First, what is String? Does it support accented characters or not?
But the real issue is one of encodings. When you say "I keep
receiving", what do you mean. What the string will contain is
not a character, but a numeric value, representing a code point
of a character, in some encoding. If the encoding used by the
compiler for accented characters is the same as the encoding
used by whatever you use to visualize them, then you will get
the same character. If it isn't, you will get something
different. Thus, for example, depending on the encoding, LATIN
SMALL LETTER Z WITH DOT (what I think you're trying to assign to
respjz2[i]) can be 0xFD or 0xBF in the encoding tables I have
access to (and it's absent in most single byte encodings); in
the single byte encoding I normally use (ISO 8859-1), these code
points correspond to LATIN SMALL LETTER Y WITH ACUTE and
INVERTED QUESTION MARK, respectively.
In the end, there is no real solution. Long term, I think you
should probably move to UTF-8, and try to ensure that all of the
tools you use (and all of the tools used by your users)
understand that. Short term, it may not be that simple: for
starters, you're more or less stuck with what your compiler
provides (unless you enter the characters in the form \u00BF
or \u00FD, and even then the compiler may do some funny
mappings when it puts them into a string literal). And you may
not even know what other tools your users use.
I have an application, accepting a UTF-8 string of a maximum 255 characters.
If the characters are ASCII, (characters number == size in bytes).
If the characters are not all ASCII and contains Japanese letters for example, given the size in bytes, how can I get the number of characters in the string?
Input: char *data, int bytes_no
Output: int char_no
You can use mblen to count the length or use mbstowcs
source:
http://www.cplusplus.com/reference/cstdlib/mblen/
http://www.cl.cam.ac.uk/~mgk25/unicode.html#mod
The number of characters can be counted in C in a portable way using
mbstowcs(NULL,s,0). This works for UTF-8 like for any other supported
encoding, as long as the appropriate locale has been selected. A
hard-wired technique to count the number of characters in a UTF-8
string is to count all bytes except those in the range 0x80 – 0xBF,
because these are just continuation bytes and not characters of their
own. However, the need to count characters arises surprisingly rarely
in applications.
you can save a unicode char in a wide char wchar_t
There's no such thing as "character".
Or, more precisely, what "character" is depends on whom you ask.
If you look in the Unicode glossary you will find that the term has several not fully compatible meanings. As a smallest component of written language that has semantic value (the first meaning), á is a single character. If you take á and count basic unit of encoding for the Unicode character encoding (the third meaning) in it, you may get either one or two, depending on what exact representation (normalized or denormalized) is being used.
Or maybe not. This is a very complicated subject and nobody really knows what they are talking about.
Coming down to earth, you probably need to count code points, which is essentially the same as characters (meaning 3). mblen is one method of doing that, provided your current locale has UTF-8 encoding. Modern C++ offers more C++-ish methods, however, they are not supported on some popular implementations. Boost has something of its own and is more portable. Then there are specialized libraries like ICU which you may want to consider if your needs are much more complicated than counting characters.
I am going through one of the requirment for string implementations as part of study project.
Let us assume that the standard library did not exist and we were
foced to design our own string class. What functionality would it
support and what limitations would we improve. Let us consider
following factors.
Does binary data need to be encoded?
Is multi-byte character encoding acceptable or is unicode necessary?
Can C-style functions be used to provide some of the needed functionality?
What kind of insertion and extraction operations are required?
My question on above text
What does author mean by "Does binary data need to be encoded?". Request to explain with example and how can we implement this.
What does author mean y point 2. Request to explain with example and how can we implement this.
Thanks for your time and help.
Regarding point one, "Binary data" refers to sequences of bytes, where "bytes" almost always means eight-bit words. In the olden days, most systems were based on ASCII, which requires seven bits (or eight, depending on who you ask). There was, therefore, no need to distinguish between bytes and characters. These days, we're more friendly to non-English speakers, and so we have to deal with Unicode (among other codesets). This raises the problem that string types need to deal with the fact that bytes and characters are no longer the same thing.
This segues onto point two, which is about how you represent strings of characters in a program. UTF-8 uses a variable-length encoding, which has the remarkable property that it encodes the entire ASCII character set using exactly the same bytes that ASCII encoding uses. However, it makes it more difficult to, e.g., count the number of characters in a string. For pure ASCII, the answer is simple: characters = bytes. But if your string might have non-ASCII characters, you now have to walk the string, decoding characters, in order to find out how many there are1.
These are the kinds of issues you need to think about when designing your string class.
1This isn't as difficult as it might seem, since the first byte of each character is guaranteed not to have 10 in its two high-bits. So you can simply count the bytes that satisfy (c & 0xc0) != 0xc0. Nonetheless, it is still expensive relative to just treating the length of a string buffer as its character-count.
The question here is "can we store ANY old data in the string, or does certain byte-values need to be encoded in some special way. An example of that would be in the standard C language, if you want to use a newline character, it is "encoded" as \n to make it more readable and clear - of course, in this example I'm talking of in the source code. In the case of binary data stored in the string, how would you deal with "strange" data - e.g. what about zero bytes? Will they need special treatment?
The values guaranteed to fit in a char is ASCII characters and a few others (a total of 256 different characters in a typical implementation, but char is not GUARANTEED to be 8 bits by the standard). But if we take non-european languages, such as Chinese or Japanese, they consist of a vastly higher number than the ones available to fit in a single char. Unicode allows for several million different characters, so any character from any european, chinese, japanese, thai, arabic, mayan, and ancient hieroglyphic language can be represented in one "unit". This is done by using a wider character - for the full size, we need 32 bits. The drawback here is that most of the time, we don't actually use that many different characters, so it is a bit wasteful to use 32 bits for each character, only to have zero's in the upper 24 bits nearly all the time.
A multibyte character encoding is a compromise, where "common" characters (common in the European languages) are used as one char, but less common characters are encoded with multiple char values, using a special range of character to indicate "there is more data in the next char to combine into a single unit". (Or,one could decide to use 2, 3, or 4 char each time, to encode a single character).
Assuming a very simple program that:
ask a name.
store the name in a variable.
display the variable content on the screen.
It's so simple that is the first thing that one learns.
But my problem is that I don't know how to do the same thing if I enter the name using japanese characters.
So, if you know how to do this in C++, please show me an example (that I can compile and test)
Thanks.
user362981 : Thanks for your help. I compiled the code that you wrote without problem, them the console window appears and I cannot enter any Japanese characters on it (using IME). Also if
I change a word in your code ("hello") to one that contains Japanese characters, it also will not display these.
Svisstack : Also thanks for your help. But when I compile your code I get the following error:
warning: deprecated conversion from string constant to 'wchar_t*'
error: too few arguments to function 'int swprintf(wchar_t*, const wchar_t*, ...)'
error: at this point in file
warning: deprecated conversion from string constant to 'wchar_t*'
You're going to get a lot of answers about wide characters. Wide characters, specifically wchar_t do not equal Unicode. You can use them (with some pitfalls) to store Unicode, just as you can an unsigned char. wchar_t is extremely system-dependent. To quote the Unicode Standard, version 5.2, chapter 5:
With the wchar_t wide character type, ANSI/ISO C provides for
inclusion of fixed-width, wide characters. ANSI/ISO C leaves the semantics of the wide
character set to the specific implementation but requires that the characters from the portable C execution set correspond to their wide character equivalents by zero extension.
and that
The width of wchar_t is compiler-specific and can be as small as 8 bits. Consequently,
programs that need to be portable across any C or C++ compiler should not use wchar_t
for storing Unicode text. The wchar_t type is intended for storing compiler-defined wide
characters, which may be Unicode characters in some compilers.
So, it's implementation defined. Here's two implementations: On Linux, wchar_t is 4 bytes wide, and represents text in the UTF-32 encoding (regardless of the current locale). (Either BE or LE depending on your system, whichever is native.) Windows, however, has a 2 byte wide wchar_t, and represents UTF-16 code units with them. Completely different.
A better path: Learn about locales, as you'll need to know that. For example, because I have my environment setup to use UTF-8 (Unicode), the following program will use Unicode:
#include <iostream>
int main()
{
setlocale(LC_ALL, "");
std::cout << "What's your name? ";
std::string name;
std::getline(std::cin, name);
std::cout << "Hello there, " << name << "." << std::endl;
return 0;
}
...
$ ./uni_test
What's your name? 佐藤 幹夫
Hello there, 佐藤 幹夫.
$ echo $LANG
en_US.UTF-8
But there's nothing Unicode about it. It merely reads in characters, which come in as UTF-8 because I have my environment set that way. I could just as easily say "heck, I'm part Czech, let's use ISO-8859-2": Suddenly, the program is getting input in ISO-8859-2, but since it's just regurgitating it, it doesn't matter, the program will still perform correctly.
Now, if that example had read in my name, and then tried to write it out into an XML file, and stupidly wrote <?xml version="1.0" encoding="UTF-8" ?> at the top, it would be right when my terminal was in UTF-8, but wrong when my terminal was in ISO-8859-2. In the latter case, it would need to convert it before serializing it to the XML file. (Or, just write ISO-8859-2 as the encoding for the XML file.)
On many POSIX systems, the current locale is typically UTF-8, because it provides several advantages to the user, but this isn't guaranteed. Just outputting UTF-8 to stdout will usually be correct, but not always. Say I am using ISO-8859-2: if you mindlessly output an ISO-8859-1 "è" (0xE8) to my terminal, I'll see a "č" (0xE8). Likewise, if you output a UTF-8 "è" (0xC3 0xA8), I'll see (ISO-8859-2) "è" (0xC3 0xA8). This barfing of incorrect characters has been called Mojibake.
Often, you're just shuffling data around, and it doesn't matter much. This typically comes into play when you need to serialize data. (Many internet protocols use UTF-8 or UTF-16, for example: if you got data from an ISO-8859-2 terminal, or a text file encoded in Windows-1252, then you have to convert it, or you'll be sending Mojibake.)
Sadly, this is about the state of Unicode support, in both C and C++. You have to remember: these languages are really system-agnostic, and don't bind to any particular way of doing it. That includes character-sets. There are tons of libraries out there, however, for dealing with Unicode and other character sets.
In the end, it's not all that complicated really: Know what encoding your data is in, and know what encoding your output should be in. If they're not the same, you need to do a conversion. This applies whether you're using std::cout or std::wcout. In my examples, stdin or std::cin and stdout/std::cout were sometimes in UTF-8, sometimes ISO-8859-2.
Try replacing cout with wcout, cin with wcin, and string with wstring. Depending on your platform, this may work:
#include <iostream>
#include <string>
int main() {
std::wstring name;
std::wcout << L"Enter your name: ";
std::wcin >> name;
std::wcout << L"Hello, " << name << std::endl;
}
There are other ways, but this is sort of the "minimal change" answer.
Pre-requisite: http://www.joelonsoftware.com/articles/Unicode.html
The above article is a must read which explains what unicode is but few lingering questions remains. Yes UNICODE has a unique code point for every character in every language and furthermore they can be encoded and stored in memory potentially differently from what the actual code is. This way we can save memory by for example using UTF-8 encoding which is great if the language supported is just English and so the memory representation is essentially same as ASCII – this of course knowing the encoding itself. In theory if we know the encoding, we can store these longer UNICODE characters however we like and read it back. But real world is a little different.
How do you store a UNICODE character/string in a C++ program? Which encoding do you use? The answer is you don’t use any encoding but you directly store the UNICODE code points in a unicode character string just like you store ASCII characters in ASCII string. The question is what character size should you use since UNICODE characters has no fixed size. The simple answer is you choose character size which is wide enough to hold the highest character code point (language) that you want to support.
The theory that a UNICODE character can take 2 bytes or more still holds true and this can create some confusion. Shouldn’t we be storing code points in 3 or 4 bytes than which is really what represents all unicode characters? Why is Visual C++ storing unicode in wchar_t then which is only 2 bytes, clearly not enough to store every UNICODE code point?
The reason we store UNICODE character code point in 2 bytes in Visual C++ is actually exactly the same reason why we were storing ASCII (=English) character into one byte. At that time, we were thinking of only English so one byte was enough. Now we are thinking of most international languages out there but not all so we are using 2 bytes which is enough. Yes it’s true this representation will not allow us to represent those code points which takes 3 bytes or more but we don’t care about those yet because those folks haven’t even bought a computer yet. Yes we are not using 3 or 4 bytes because we are still stingy with memory, why store the extra 0(zero) byte with every character when we are never going to use it (that language). Again this is exactly the same reasons why ASCII was storing each character in one byte, why store a character in 2 or more bytes when English can be represented in one byte and room to spare for those extra special characters!
In theory 2 bytes are not enough to present every Unicode code point but it is enough to hold anything that we may ever care about for now. A true UNICODE string representation could store each character in 4 bytes but we just don’t care about those languages.
Imagine 1000 years from now when we find friendly aliens and in abundance and want to communicate with them incorporating their countless languages. A single unicode character size will grow further perhaps to 8 bytes to accommodate all their code points. It doesn’t mean we should start using 8 bytes for each unicode character now. Memory is limited resource, we allocate what what we need.
Can I handle UNICODE string as C Style string?
In C++ an ASCII strings could still be handled in C++ and that’s fairly common by grabbing it by its char * pointer where C functions can be applied. However applying current C style string functions on a UNICODE string will not make any sense because it could have a single NULL bytes in it which terminates a C string.
A UNICODE string is no longer a plain buffer of text, well it is but now more complicated than a stream of single byte characters terminating with a NULL byte. This buffer could be handled by its pointer even in C but it will require a UNICODE compatible calls or a C library which could than read and write those strings and perform operations.
This is made easier in C++ with a specialized class that represents a UNICODE string. This class handles complexity of the unicode string buffer and provide an easy interface. This class also decides if each character of the unicode string is 2 bytes or more – these are implementation details. Today it may use wchar_t (2 bytes) but tomorrow it may use 4 bytes for each character to support more (less known) language. This is why it is always better to use TCHAR than a fixed size which maps to the right size when implementation changes.
How do I index a UNICODE string?
It is also worth noting and particularly in C style handling of strings that they use index to traverse or find sub string in a string. This index in ASCII string directly corresponded to the position of item in that string but it has no meaning in a UNICODE string and should be avoided.
What happens to the string terminating NULL byte?
Are UNICODE strings still terminated by NULL byte? Is a single NULL byte enough to terminate the string? This is an implementation question but a NULL byte is still one unicode code point and like every other code point, it must still be of same size as any other(specially when no encoding). So the NULL character must be two bytes as well if unicode string implementation is based on wchar_t. All UNICODE code points will be represented by same size irrespective if its a null byte or any other.
Does Visual C++ Debugger shows UNICODE text?
Yes, if text buffer is type LPWSTR or any other type that supports UNICODE, Visual Studio 2005 and up support displaying the international text in debugger watch window (provided fonts and language packs are installed of course).
Summary:
C++ doesn’t use any encoding to store unicode characters but it directly stores the UNICODE code points for each character in a string. It must pick character size large enough to hold the largest character of desirable languages (loosely speaking) and that character size will be fixed and used for all characters in the string.
Right now, 2 bytes are sufficient to represent most languages that we care about, this is why 2 bytes are used to represent code point. In future if a new friendly space colony was discovered that want to communicate with them, we will have to assign new unicode code pionts to their language and use larger character size to store those strings.
You can do simple things with the generic wide character support in your OS of choice, but generally C++ doesn't have good built-in support for unicode, so you'll be better off in the long run looking into something like ICU.
#include <stdio.h>
#include <wchar.h>
int main()
{
wchar_t name[256];
wprintf(L"Type a name: ");
wscanf(L"%s", name);
wprintf(L"Typed name is: %s\n", name);
return 0;
}