How to count by three from the number given by the user? - c++

Question

I have to create a program using a for loop that will count by 3 from the given number from the user 20 times. So far this is what i have.
#include <iostream>
using namespace std;
int main(){
int num, newNum, add;
cout << "Enter a number: ";
cin >> num;
for(int count = 0; count < 20; count++){
for(int sum = 0; sum <= count; sum++){
newNum = num * (count +1);
}
cout << num << " ";
}
}
I have no idea where to go from here. I know that i would have to put the number given into a variable like i do with num and i know i would somehow have to store the new number in another variable like i do with newNum. Any help would be appreciated! Also this is what the output should look like in case i did not explain it good enough.
Enter a number: 3
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60.
And bonus points if you can have the last number end with a period instead of a comma :)

Answer 1

This should work:
int main(){
int num, currentNum, add, newNum;
std::cout << "Enter a number: ";
std::cin >> num;
std::cout << num
for(int count = 0; count < 20; count++){
num += 3;
std::cout << ", " << num;
}
std::cout << " ." << std::endl;
}
Also try to not use using namespace std. It clutters the namespace.

Answer 2

You can add 3 to the number either inside the loop's third statement (you can also have multiple conditions etc.)
for(int count = 0; count <= 20; count++, num+=3){
// ...
}
or inside the loop's code block
for(int count = 0; count <= 20; count++){
num += 3;
}
As for the comma you just need to add it to the output:
cout << num << ", ";
Since you want a dot at the end you need to handle this in an if-else case
if (count < 20)
cout << num << ", ";
else
cout << num << ".";
or a ternary operator:
cout << num << (num < 20) ? ", " : ".";
Bonus points: don't expose the complete namespace (here: std). While in such a small example it's not an issue it may lead to hard to detect bugs later on if you happen to use one or multiple namespaces that offer the same functionality.

Answer 3

OK, we have so far an answer explaining pretty well and another one optimising the if inside the loop away. We still can optimise away one addition, if you count up the num variable directly:
for(auto end = num + 57; num < end; num += 3)
// ^ still one number less, last one follows the loop!
{
std::cout << num << ", ";
}
std::cout << num << '.' << std::endl;
// ^ ^ not much difference, but just outputting a single character
// is more efficient, no need to iterate to find the
// trailing null character...
std::endl not only adds a newline, but flushes the stream immediately (i. e. the so far possibly buffered output is forced to be printed to console). This is especially useful if there's more output to follow, but possibly quite a while later (without flushing, user might see incomplete last line). Admitted, in given case not necessary, as std::cout's destructor will flush anyway, so you could go, too, with the slightly simpler std::cout << num << ".\n"...

Answer 4

Without using the extra variables.
#include
using namespace std;
int main(){
int num, currentNum, add, newNum;
cout << "Enter a nummber: ";
cin >> num;
for(int count = 0; count <= 20; count++){
cout << (num + count * 3);
if(count == 20)cout<<".\n";
else cout<<", ";
}
}
More general solution would be:
#include <iostream>
using namespace std;
int main(){
int num, currentNum, add;
cout << "Enter a nummber: ";
cin >> num;
add = 3;
currentNum = num;
for(int count = 0; count <= 20; count++){
cout << (currentNum); //Print current number
currentNum = currentNum + add; // increase the number
if(count == 20)cout<<".\n"; //if the last one print dot
else cout<<", "; //else place comma
}
}