XSLT manipulate string, move last word - xslt

Question

I would like to ask if it is possible to swap the last word with the one in front of it, if ends with 27.5 or 29:
<item>
<code>1</code>
<title><![CDATA[Test 30 S 27.5]]></title>
</item>
<item>
<code>2</code>
<title><![CDATA[Test 20 Orange XL 29]]></title>
</item>
<item>
<code>3</code>
<title><![CDATA[Test 30 XS 29]]></title>
</item>
<item>
<code>4</code>
<title><![CDATA[Test 60 27.5 XS]]></title>
</item>
Example output:
<item>
<code>1</code>
<title><![CDATA[Test 30 27.5 S]]></title>
</item>
<item>
<code>2</code>
<title><![CDATA[Test 20 Orange 29 XL]]></title>
</item>
<item>
<code>3</code>
<title><![CDATA[Test 30 29 XS]]></title>
</item>
<item>
<code>4</code>
<title><![CDATA[Test 60 27.5 XS]]></title>
</item>

Answer 1

Use tokenize or analyze-string and then reorder the sequence you get from tokenize or process the result of analyze-string:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:output cdata-section-elements="title"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="title[ends-with(., '27.5') or ends-with(., '29')]">
<xsl:copy>
<xsl:value-of select="let $words := tokenize(., '\s+')
return (subsequence($words, 1, count($words) - 2), $words[last()], $words[last() - 1])"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
https://xsltfiddle.liberty-development.net/3NSSEuS/1