May be a SFINAE BUG in complier when use template? - c++

Question

I want to use the standard code to write the utils like std::is_union,we know class type can not extends union type,it's error,so some code like these
#include <iostream>
template<typename T>
class class_type_can_extends :public T{
public:
using type = void;
};
template<typename T,typename U = void>
struct is_not_union:std::false_type {
};
template<typename T>
struct is_not_union < T, std::void_t<typename class_type_can_extends <T>::type >> :std::true_type {
};
class c_data{
};
union u_data{
};
int main(){
/*#1*/ std::cout<< is_not_union<c_data>::value<<std::endl; /*print true*/
/*#2*/ std::cout<< is_not_union<u_data>::value<<std::endl; /*this code make
all complier error*/
}
g++ print error:
main.cpp: In instantiation of ‘class class_type_can_extends<u_data>’:
main.cpp:26:43: recursively required by substitution of ‘template<class T> struct is_not_union<T, std::void_t<typename class_type_can_extends<T>::type> > [with T = u_data]’
main.cpp:26:43: required from here
main.cpp:3:7: error: base type ‘u_data’ fails to be a struct or class type
class class_type_can_extends :public T {
clang print error:
main.cpp:3:38: error: unions cannot be base classes
class class_type_can_extends :public T {
~~~~~~~^
main.cpp:14:47: note: in instantiation of template class 'class_type_can_extends<u_data>' requested here
struct is_not_union < T, std::void_t<typename class_type_can_extends <T>::type >> :std::true_type {
^
main.cpp:26:23: note: during template argument deduction for class template partial specialization 'is_not_union<T,
std::void_t<typename class_type_can_extends<T>::type> >' [with T = u_data]
/*#2*/ std::cout << is_not_union<u_data>::value << std::endl; /*this code make
^
main.cpp:26:23: note: in instantiation of template class 'is_not_union<u_data, void>' requested here
1 error generated.
vs:
error C2569
why #2 code make complier error,The complier would be using SFINAE rules on #2 code(substituted T by "u_data" ,then Failed ),and to chose primary template?why the sfinae not effective here,may be a bug here?

Answer 1

From cppreference:
Only the failures in the types and expressions in the immediate context of the function type or its template parameter types or its explicit specifier (since C++20) are SFINAE errors. If the evaluation of a substituted type/expression causes a side-effect such as instantiation of some template specialization, generation of an implicitly-defined member function, etc, errors in those side-effects are treated as hard errors
SFINAE applies on immediate context, here you have a hard error failure.
In typename class_type_can_extends<T>::type, SFINAE applies if type doesn't exist, not if instantiation of class_type_can_extends<T> fails.
Notice that we cannot distinguish between union and class types using only standard C++
(without std::is_union). Most compilers provide intrinsics for that.