Does boto3 v1.9.244 support creating an 's3' resource? - amazon-web-services

Question

I am attempting to retrieve a list of files from S3 with a specific prefix using an AWS Lambda. I bundle the Lambda with boto3-1.9.244 (the latest version). When I run the Lambda, I receive a SyntaxError on the S3 resource assignment although it could have something to do with Boto3 session.
I'm using Python 3.6 and AWS Lambda uses boto3-1.9.221 and botocore-1.12.221. When I run the code without bundling the latest version of boto3, it works. My current solution is to simply bundle boto3-1.9.221 with the lambda code rather than the latest version of boto3.
import boto3
s3 = boto3.resource('s3')
I expect it to create an s3 resource, but I get this error:
invalid syntax (_base.py, line 414): SyntaxError
Traceback (most recent call last):
File "/var/task/lambda_function.py", line 20, in lambda_handler
s3 = boto3.resource('s3')
File "/var/task/boto3/__init__.py", line 100, in resource
return _get_default_session().resource(*args, **kwargs)
File "/var/task/boto3/session.py", line 389, in resource
aws_session_token=aws_session_token, config=config)
File "/var/task/boto3/session.py", line 263, in client
aws_session_token=aws_session_token, config=config)
File "/var/task/botocore/session.py", line 839, in create_client
client_config=config, api_version=api_version)
File "/var/task/botocore/client.py", line 80, in create_client
cls = self._create_client_class(service_name, service_model)
File "/var/task/botocore/client.py", line 110, in _create_client_class
base_classes=bases)
File "/var/task/botocore/hooks.py", line 356, in emit
return self._emitter.emit(aliased_event_name, **kwargs)
File "/var/task/botocore/hooks.py", line 228, in emit
return self._emit(event_name, kwargs)
File "/var/task/botocore/hooks.py", line 211, in _emit
response = handler(**kwargs)
File "/var/task/boto3/utils.py", line 61, in _handler
module = import_module(module)
File "/var/task/boto3/utils.py", line 52, in import_module
__import__(name)
File "/var/task/boto3/s3/inject.py", line 15, in <module>
from boto3.s3.transfer import create_transfer_manager
File "/var/task/boto3/s3/transfer.py", line 127, in <module>
from s3transfer.exceptions import RetriesExceededError as \
File "/var/task/s3transfer/__init__.py", line 134, in <module>
import concurrent.futures
File "/var/task/concurrent/futures/__init__.py", line 8, in <module>
from concurrent.futures._base import (FIRST_COMPLETED,
File "/var/task/concurrent/futures/_base.py", line 414
raise exception_type, self._exception, self._traceback
^
SyntaxError: invalid syntax

Answer 1

Yes, it does support. So this issue is not related to the API version.
You can access a specific API version just by replacing latest with the version number you want in the URL.
Latest
https://boto3.amazonaws.com/v1/documentation/api/latest/reference/services/s3.html#bucket
1.9.244
https://boto3.amazonaws.com/v1/documentation/api/1.9.244/reference/services/s3.html#bucket

Answer 2

Turns out the issue was that I was installing the requirements with Python2 rather than Python3. By installing the requirements with Python3, I no longer received a syntax error.

Answer 3

It looks like your lambda function doesn't have the IAM role for S3. You may specify the Access key and Secret key to the resource directly,
resource = boto3.resource(
's3',
# Hard coded strings as credentials, not recommended.
aws_access_key_id='AKIAIO5FODNN7E******', # not real
aws_secret_access_key='ABCDEF+c2L7yXeGvUyrPgYsDnWRRC1AYE******' # not real
)
or have to give the right permission to the lambda function.