How put points in an 2D coordinate system radomly? - c++

Question

i want this code can show:
1 2 3 .... 10
1 * *
2 #
.
. *
10 *
#include <iostream>
#include <iomanip>
#include <time.h>
int coordinates[1][10] = { 1,2,3,4, 5,6,7,8,9,10 };
for (int k = 0; k < 1; k++) {
for (int j = 0; j < 10; j++) {
cout << " " << coordinates[k][j];
}
cout << endl;
}
for (int r = 0; r < 1; r++) {
for (int s = 0; s < 10; s++) {
cout << coordinates[r][s] << endl;
}
}
return 0;
}
I want put sign# in position(3,2), LIKE THE ABOVE
and also put some points(*) into coordinate system randomly, and the points cannot be put them at 8 immediate neighbors of #position(3,2)

Answer 1

My suggestion is to make a 2d array of characters:
char board[MAX_ROWS][MAX_COLUMNS] = {0};
A better improvement is to use an extra column for the newline character:
char board[MAX_ROWS][MAX_COLUMNS + 1] = {0};
for (unsigned int i = 0U; i < MAX_ROWS; ++i)
{
board[i][MAX_COLUMNS] = '\n';
}
The extra column allows you to print the board with one statement:
std::cout << board << "\n";
If you want fancies, you can set up the output attributes before printing:
std::cout.width(3); // each cell is 3 wide
std::cout.fill(' '); // Pad each cell with spaces.
std::cout << board << "\n";
You can also add an extra column for displaying the row numbers and an extra row for display column numbers.
Edit 1: Setting a point
Setting a point is simple:
board[row][column] = '*'; // Set a point.
board[x][y] = ' '; // Erase a point.
Since the board is of type char, you can use different characters as points, such as '-', '+', 'M', etc.