remove "?show=false" using regex [duplicate] - regex

I looking for regular expression to use in my javascript code, which give me last part of url without parameters if they exists - here is example - with and without parameters:
https://scontent-fra3-1.xx.fbcdn.net/v/t1.0-9/14238253_132683573850463_7287992614234853254_n.jpg?oh=fdbf6800f33876a86ed17835cfce8e3b&oe=599548AC
https://scontent-fra3-1.xx.fbcdn.net/v/t1.0-9/14238253_132683573850463_7287992614234853254_n.jpg
In both cases as result I want to get:
14238253_132683573850463_7287992614234853254_n.jpg

Here is this regexp
.*\/([^?]+)
and JS code:
let lastUrlPart = /.*\/([^?]+)/.exec(url)[1];
let lastUrlPart = url => /.*\/([^?]+)/.exec(url)[1];
// TEST
let t1 = "https://scontent-fra3-1.xx.fbcdn.net/v/t1.0-9/14238253_132683573850463_7287992614234853254_n.jpg?oh=fdbf6800f33876a86ed17835cfce8e3b&oe=599548AC"
let t2 = "https://scontent-fra3-1.xx.fbcdn.net/v/t1.0-9/14238253_132683573850463_7287992614234853254_n.jpg"
console.log(lastUrlPart(t1));
console.log(lastUrlPart(t2));
May be there are better alternatives?

You could always try doing it without regex. Split the URL by "/" and then parse out the last part of the URL.
var urlPart = url.split("/");
var img = urlPart[urlPart.length-1].split("?")[0];
That should get everything after the last "/" and before the first "?".

Related

How to extract part of url - dart/flutter

I'm trying to extract the part of url (To be more specific, I'm trying to extract the value of page_info parameter in the url which is next to rel="next"
String testUrl = "<https://demo.myshopify.com/admin/api/2022-01/products.json?limit=10&page_info=eyJkaXJlY3Rpb24iOiJwcmV2IiwibGFzdF9pZCI6NjczMDU4MDcyMTc1NCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBCcmFjZWxldCJ9>; rel='previous', <https://demo.myshopify.com/admin/api/2022-01/products.json?limit=10&page_info=eyJkaXJlY3Rpb24iOiJuZXh0IiwibGFzdF9pZCI6NjczMDIyNzcxMjA5MCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBIZWFydCBQZW5kYW50IE5lY2tsYWNlIn0>; rel='next'";
List<String> splitUrl = testUrl.split("=");
print(splitUrl[5]);
// this is what it prints out
eyJkaXJlY3Rpb24iOiJuZXh0IiwibGFzdF9pZCI6NjczMDIyNzcxMjA5MCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBIZWFydCBQZW5kYW50IE5lY2tsYWNlIn0>; rel
// this is what I'm trying to extract
eyJkaXJlY3Rpb24iOiJuZXh0IiwibGFzdF9pZCI6NjczMDIyNzcxMjA5MCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBIZWFydCBQZW5kYW50IE5lY2tsYWNlIn0
// value for rel="next"
I tried to split the url by using split function on String but that would also bring the angle bracket with it. I'm trying to extract only page_info= parameter value which is for rel="next"
I know this has to do something with regex but I'm not really good at it! Any help would be really appreciated
I grabbed that url from header response (paginated REST API), it returns two page_info parameters (one for next and other one for previous page) I'm trying to extract value for next page. Splitting the url didn't help me
thank you
An alternative approach is to use Uri.parse to parse the URL:
void main() {
String testUrl = "<https://demo.myshopify.com/admin/api/2022-01/products.json?limit=10&page_info=eyJkaXJlY3Rpb24iOiJwcmV2IiwibGFzdF9pZCI6NjczMDU4MDcyMTc1NCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBCcmFjZWxldCJ9>; rel='previous', <https://demo.myshopify.com/admin/api/2022-01/products.json?limit=10&page_info=eyJkaXJlY3Rpb24iOiJuZXh0IiwibGFzdF9pZCI6NjczMDIyNzcxMjA5MCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBIZWFydCBQZW5kYW50IE5lY2tsYWNlIn0>; rel='next'";
// Extract just the URL.
var match = RegExp(r'<([^>]*)>').firstMatch(testUrl);
if (match != null) {
var uri = Uri.parse(match.group(1)!);
print(uri.queryParameters['page_info']); // Prints: eyJkaXJlY3Rpb24iOiJ...
}
}
Note that the above wouldn't need any of the RegExp code if testUrl were a proper URL without the angle brackets and rel='next' junk.
the regEx pattern page_info=([\w]+)
gives you
eyJkaXJlY3Rpb24iOiJwcmV2IiwibGFzdF9pZCI6NjczMDU4MDcyMTc1NCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBCcmFjZWxldCJ9
eyJkaXJlY3Rpb24iOiJuZXh0IiwibGFzdF9pZCI6NjczMDIyNzcxMjA5MCwibGFzdF92YWx1ZSI6IjE4SyBHb2xkIFBsYXRlZCBIZWFydCBQZW5kYW50IE5lY2tsYWNlIn0
https://regexr.com/6qj1h

error with RegExp inside angular.toJson

I'm trying to do a 'like' query in mongodb. I see that's done with a regexp so I'm trying to set it like this:
$scope.clients = Client.query({
q:angular.toJson({
name: RegExp($routeParams.str)
})
});
The thing is angular.toJson function does not get any regexp:
http://plnkr.co/edit/idXMT1
Is there any other way to do that?
From my understanding of your question, you want your JSON object to contain the regular expression as a string?
In that case, you can manually convert it to a string in the declaration, i.e:
$scope.object = angular.toJson({
"param" : new RegExp(str).toString()
});
See updated plunk:
http://plnkr.co/edit/yLogI8
I finally found a solution.
The problem is using the toJon function as it does not allow any key starting with / or $ so the solution is avoiding the use of this function and just write the object as a string
$scope.clients = Client.query({
q:'{src:{$regex:"' + $routeParams.str + '"}}'
};

Javascript regex replace

I have a langauge dropdown, and a javascript function which changes the page to the corresponding language selected. I need help on my regex replace:
For example, I would like this URL to turn into this url:
http://localhost:7007/en/Product/Detail/1038
http://localhost:7007/fr/Product/Detail/1038
function languageChange(sender) {
var lang = $(sender).val();
var target = window.location.href;
target = target.replace(/(http:\/\/.*?)([a-zA-Z]{2})(.*$)/gim, '$1' + lang + '$3');
window.location = target;
}
Is your URL always the same structure? If so, you may not need a regex at all. Split the url at each "/", replace index 3, then join your array back to together with "/".
Here is a code sample:
function changeLanguage(url, newLang) {
var url = url.split('/');
url[3] = newLang;
return url.join('/');
}
changeLanguage('http://localhost:7007/en/Product/Detail/1038','Fr');
Note: I originally wrote "splice" instead of "join" in my response. Join is the correct method.
Here is a function that processes any number of URLs within a string, and replaces the language part (the first part of path), only if exists and is from 2 to 4 chars long:
function changeLanguage(text, lang) {
return text.replace(
/\b(\w+:\/\/[^\/]+\/)[A-Z]{2,4}(?=[\/\s]|$)/gim,
'$1' + lang);
}
Edit: Converted to function format.
Use this regex:
target =
target.replace(/(https?:\/\/[^/]+)\/?([^/]*)(.*)/gi, '$1/' + lang + '$3');
if e.g. lang='fr' then target holds http://localhost:7007/fr/Product/Detail/1038 value;

Can a sizzle selector evaluate a regular expression?

I need to select links with a specific format of URLs. Can I use sizzle to evaluate a link's href attribute against a regular expression?
For example, can I do something like this:
var arrayOfLinks = Sizzle('a[HREF=[0-9]+$]');
to create an array of all links on the page whose URL ends in a number?
Give this a try. I've attempted to convert the jQuery regex selector that Kobi linked to into a Sizzle selector extension. Seems to work, but I haven't put it through a lot of testing.
Sizzle.selectors.filters.regex = function(elem, i, match){
var matchParams = match[3].split(',', 2);
var attr = matchParams[0];
var pattern = matchParams[1];
var regex = new RegExp(pattern.replace(/^\s+|\s+$/g,''), 'ig');
return regex.test(elem.getAttribute(attr));
};
In this case, your example would be written as:
var arrayOfLinks = Sizzle('a:regex(href,[0-9]+$)');

How to use regular expression in WatiN

I'm working on WatiN automation tool. I'm having problem in regular expression. I've situation where i have to enter some text and click on a button in the popup window. I'm using AttachToIE method and URL attribute("http://192.168.25.10:215/admin/SelectUsers.aspx?Type=FeedbackID=ef5ad7ef5490-4656-9669-32464aeba7cd") of the popup to attach to the popup.
The problem is each time the popup appears the ID value in the URL changes. So i'm not able to access the popup. can anyone plz help with this by giving me Regular Expression for the changing value of ID in the below URL
("http://192.168.25.10:215/admin/SelectUsers.aspx?Type=FeedbackID=ef5ad7ef5490-4656-9669-32464aeba7cd")
thanking you
It appears that you have a URL with 2 query string parameters Type and ID and your pattern is:
"http://192.168.25.10:215/admin/SelectUsers.aspx?Type=Feedback&ID={some id}"
You can use the Find.ByUrl() attribute constraint method and pass it to AttachToIE() as shown below with the regex for matching that pattern.
string url = "http://192.168.25.10:215/admin/SelectUsers.aspx?Type=Feedback&ID="
Regex regex = new Regex(url + "[a-z0-9]+", RegexOptions.IgnoreCase);
IE ie = IE.AttachToIE(Find.ByUrl(regex));
string baseUrl ="http://192.168.25.10:215/admin/SelectUsers.aspx?Type=FeedbackID="
Regex urlIE= new Regex(baseUrl + "[\\wd]+", RegexOptions.IgnoreCase);
IE ie = IE.AttachToIE(Find.ByUrl(urlIE);
I'm not familiar with WatiN but it looks like it's runs on .Net so perhaps this might help?
var desiredId = "000000000000-0000-0000-000000000000";
var url = "http://192.168.25.10:215/admin/SelectUsers.aspx?Type=FeedbackID=ef5ad7ef5490-4656-9669-32464aeba7cd&someMoreStuff";
var pattern = #"(?i)(?<=FeedBackId=)[-a-z0-9]+";
var result = Regex.Replace(url, pattern, desiredId);
Console.WriteLine(result);
//Output: http://192.168.25.10:215/admin/SelectUsers.aspx?Type=FeedbackID=000000000000-0000-0000-000000000000&someMoreStuff
The following pattern should have the same affect but is more defensive. It should only match stuff in the query string, it requires the id to be 35 characters and won't match similar parameter names like "PreviousFeedBackId".
var pattern = #"(?i)(?<=\?.*\bFeedBackId=)[-a-z0-9]{35,35}\b";
If you just want to extract the id:
var id = Regex.Match(url, pattern).Value;
Console.WriteLine(id);
//output: ef5ad7ef5490-4656-9669-32464aeba7cd
WatiN has a feature where in we can use the url by neglecting the query string. Below is the code which is working fine for me.
string baseUrl = "http://192.168.25.10:215/admin/SelectUsers.aspx";
IE ie = IE.AttachToIE(Find.ByUrl(baseUrl,true));