How to execute overrided method C++ - c++

i'll try to create a structure for executing an overrided method in derived class.
My base code structure:
Base.h EDITED
class Base
{
protected:
virtual void Initialize() = 0;
virtual void Update() = 0;
public:
void Init();
void Upd();
};
Base.cpp
#include "Base.h"
void Base::Initialize() {}
void Base::Update() {}
void Base::Init() {
// Some logic
Initialize();
}
void Base::Upd() {
// Some logic
Update();
}
The following class is the class to be inherited from N other classes that implement Initialize() and Update() then:
Behaviour.h
#include <iostream>
#include "Base.h"
class Behaviour : public Base
{
protected:
virtual void Initialize();
virtual void Update();
};
Behaviour.cpp
#include "Behaviour.h"
void Bheaviour::Initialize() {
std::cout << "Initialize called!" << std::endl;
}
void Bheaviour::Update() {
std::cout << "Update called!" << std::endl;
}
Then I want to execute Behaviour Initialize() and Update() when is executed in the Base class. My main function is:
Core.cpp EDITED
#include "Behaviour.h"
int main() {
Base* base = new Behaviour();
base->Init();
while(!quit) {
base->Upd();
}
}
Thank's in advance for any suggestions!
Thanks for all suggestions, i've solved!

Change Base* base = new Base();
to
Base* base = new Bheviour;
and polmorphism will take care of everything else.
If you don't want to create an object out of base class better to declare it as an abstract class.

Related

Thread creation on a derived class method results in error

I have an abstract class as follows:
class AbstractClass : public std::enable_shared_from_this<AbstractClass> {
public:
virtual ~AbstractClass() = default;
virtual bool Start() = 0;
virtual void Stop() = 0;
};
This is the derived class:
class DerivedClass : public AbstractClass {
public:
bool Start() override;
void Stop() override;
}
I am trying to create an object of derived class and a thread for the derived class method in another file:
// Create object
derivedClass_.reset(...);
//Start a thread for the derived class method
std::unique_ptr<boost::thread> derivedClassThread_;
derivedClassThread_.reset(new boost::thread(std::bind(&DerivedClass::Start,
derivedClass_)));
When I compile this, I get some weird errors:
error: no type named 'type' in 'class std::result_of<bool
(DerivedClass::* const&(const volatile
std::shared_ptr&))()>'
Could someone help me out?
Your code is not selfcontained, so we have to guess things. Here's what I think you would have/want:
Live On Coliru
#include <boost/thread.hpp>
#include <memory>
#include <iostream>
class AbstractClass : public std::enable_shared_from_this<AbstractClass> {
public:
virtual ~AbstractClass() = default;
virtual bool Start() = 0;
virtual void Stop() = 0;
};
class DerivedClass : public AbstractClass {
public:
bool Start() override {
std::cout << __PRETTY_FUNCTION__ << std::endl;
return true;
}
void Stop() override { }
};
int main()
{
// Create object
std::shared_ptr<AbstractClass> derivedClass_ =
std::make_shared<DerivedClass>();
// Start a thread for the derived class method
auto derivedClassThread_ = std::make_unique<boost::thread>(
[derivedClass_] { derivedClass_->Start(); });
if (derivedClassThread_ && derivedClassThread_->joinable())
derivedClassThread_->join();
derivedClassThread_ = std::make_unique<boost::thread>(
std::bind(&AbstractClass::Start, derivedClass_));
if (derivedClassThread_ && derivedClassThread_->joinable())
derivedClassThread_->join();
}
Which compiles without trouble.
Updated in response to the comment, showed that you can actually do it with std::bind just the same.
Prints:
virtual bool DerivedClass::Start()
virtual bool DerivedClass::Start()

Creating List of abstract base class to fill with inherited objects

I want to create a List which is able to hold every Object I throw at it as long as they share the same ABSTRACT base class.
Here is an sample code of how I want to achieve this.
#include <iostream>
#include <memory>
#include <list>
class Observer
{
public:
virtual void update() = 0;
};
class RequestStateObserver
{
public:
void registerObserver(std::shared_ptr<Observer> o){
observerList.push_back(o);
}
private:
std::list<std::shared_ptr<Observer>> observerList;
};
class RestRequestCreator :Observer
{
void update() override;
};
void RestRequestCreator::update()
{
std::cout<<"RestRequestCreator::update()";
}
class dbHandler :Observer
{
void update() override;
};
void dbHandler::update() {
std::cout<<"dbHandler::update()";
}
int main()
{
RestRequestCreator rrc;
RequestStateObserver rso;
dbHandler dbhandler;
std::shared_ptr<RequestStateObserver> stateObserver;
std::shared_ptr<RestRequestCreator> rr_ptr = std::make_shared<RestRequestCreator>(rrc);
rso.registerObserver(rr_ptr);
rso.registerObserver(std::make_shared<Observer> (dbhandler));
}
o->registerObserver(std::make_shared<Observer> dbhandler)will tell me I can't create Observer since it's an abstract class which totally makes sense but
o->registerObserver(rr_ptr) will tell me it can't convert std::shared_ptr<Observer> to std::shared_ptr<RestRequestCreator>
I am at the moment not sure how to fix this problem or what exactly I should try next.
Would Templates help me? If I am correct they would just allow me to put as many objects of ONE child class into my List, if that's wrong please tell me and I will re-read about templates again.
The conversion fails because Observer is a private base of RestRequestCreator, and is inaccessible.
You'll need to use public inheritance for the compiler to implicitly convert from the derived class to the base:
class RestRequestCreator :public Observer
That fixes the immediate problem, but leaves the problems with make_shared<Observable> on the next line.
Also: should an observee co-own an observer? In general that would not be the case. Therefore, instead use regular pointers.
#include <list>
#include <iostream>
using std::cout;
class Observer
{
public:
virtual void update() = 0;
};
class ConcreteObserver : public Observer
{
public:
void update() override {
cout << "ConcreteObserver noticed update\n";}
};
class OtherKindConcreteObserver : public Observer
{
public:
void update() override {
cout << "OtherKindObserver noticed update\n";
}
};
class Subject
{
public:
void registerObserver( Observer* o) {
observerList.push_back( o);
}
void signalObservers() {
for ( auto observer : observerList)
observer->update();
}
private:
std::list<Observer*> observerList;
};
int main() {
ConcreteObserver observer1;
OtherKindConcreteObserver observer2;
Subject subject;
subject.registerObserver( &observer1);
subject.registerObserver( &observer2);
subject.signalObservers();
return 0;
}

Requiring derived class to define a method

I am no doubt overlooking something basic but my implementation is obviously flawed.
I am trying to require a derived classes to implement a method being called in a base class.
class IClock
{
public:
virtual void OnTimeExpired() = 0;
}
class Clock : public IClock
{
... // ABC not implemented
}
class Application : public Clock
{
... // ABC not implemented
}
class DerivedApp : public Application
{
public:
virtual void OnTimeExpired() { ... }
}
I rarely use pure ABCs, so I thought by not defining the pure virtual method in Clock and Application, it would require all derivatives of Application to define the OnTimeExpired() method.
I discovered this will compile and link (MSVS-2017) and if DerivedApp does not implement the method, the Clock object will call an undefined method and crash.
Why does this compile without the pure virtual method being implemented?
How do I force derived Application classes to implement the OnTimeExpired() method?
EDIT: The crash was due to unrelated error - I apologize. Nevertheless the questions I ask are still applicable.
As requested here is a complete, buildable, minimal example:
IClock.h:
#pragma once
class IClock
{
public:
virtual void OnClockTime() = 0;
};
Clock.h:
#pragma once
#include "IClock.h"
class Clock : public IClock
{
public:
Clock();
virtual ~Clock();
void ClockUpdate();
virtual void OnClockTime();
private:
float elapsed_time;
};
Clock.cpp:
#include "Clock.h"
Clock::Clock()
: elapsed_time(0.0f)
{
}
Clock::~Clock()
{
}
void Clock::ClockUpdate()
{
elapsed_time += 0.0000001f; // small ticks for testing
if (elapsed_time >= 1.0f) {
OnClockTime();
elapsed_time -= 1.0f;
}
}
void Clock::OnClockTime()
{}
ApplicationBase.h
#pragma once
#include "Clock.h"
class ApplicationBase : public Clock
{
public:
ApplicationBase();
virtual ~ApplicationBase();
virtual void Init(){}
virtual void Run(){}
protected:
bool app_run;
};
ApplicationBase.cpp:
#include "ApplicationBase.h"
ApplicationBase::ApplicationBase()
: app_run(false)
{
}
ApplicationBase::~ApplicationBase()
{
}
DerivedApp.h:
#pragma once
#include "ApplicationBase.h"
class DerivedApp : public ApplicationBase
{
public:
DerivedApp();
virtual ~DerivedApp();
virtual void Init() {}
virtual void Run();
//virtual void OnClockTime();
};
DerivedApp.cpp:
#include "DerivedApp.h"
#include <iostream>
DerivedApp::DerivedApp()
{
}
DerivedApp::~DerivedApp()
{
}
void DerivedApp::Run()
{
app_run = true;
while (app_run) {
ClockUpdate();
}
}
//void DerivedApp::OnClockTime()
//{
// static int counts(0);
// std::cout << "Tick..." << std::endl;
// counts++;
// if (counts >= 10)
// app_run = false;
//}
main.cpp
#include "DerivedApp.h"
class App : public DerivedApp
{
public:
App(){}
~App(){}
};
int wmain(int argc, wchar_t * argv[])
{
App *app = new App();
app->Init();
app->Run();
delete app;
}
Thanks to those who requested a minimal working example, I built it and it works exactly as I had hoped. The complier will complain about no instantiation of the ABC in the App class. If I remove the comments from DerivedApp::OnClockTime() it compiles and runs the way I wish. Obviously my actual code is not following this model as I thought, so now I need to reexamine where I went wrong. Thanks.
There is no keyword in C++ that forces a class to override some method. However, by making OnTimeExpired() pure virtual you're making IClock an abstract class. Any classes deriving from IClock that do not implement OnTimeExpired() will automatically become an abstract class too, thus not allowing you to create objects of these classes. This means that your code as-is is completely legal unless you try to make objects of these classes
class AbstractBase {
public:
virtual void someFunc() = 0; // Purely Virtual
};
class AbstractDerived : public AbstractBase {
public:
void someOtherFunc();
// Still abstract because the following is not declared-defined
// void someFunc() override { ... }
};
class NonAbstractDerivedA : public AbstractBase { // Derived From Base
public:
void someFunc() override { /* do this class's implementation*/ }
};
class NonAbstractDerivedB : public AbstractDerived { // Derived From AbstractDerived
public:
void someFunc() override { /* do this class's implementation*/ }
};
uses:
#include "above"
int main() {
AbstractBase base; // compiler error
AbstractDerived derived; // compiler error
NonAbstractDerivedA derivedA; // should be okay
NonAbstractDerivedB derivedB; // should be okay
return 0;
}

C++ Overriding method not working

I am expecting "My Game" to print out but I am getting "Base"
This only happens when using methods internally inside the class.
#include <iostream>
namespace Monster { class App {
public:
App(){}
~App(){}
void run(){
this->speak();
}
void speak(){
std::cout << "Base" << "\n";
};
};}; // class / namespace
class MyGame : public Monster::App {
public:
MyGame(){}
~MyGame(){}
void speak(){
std::cout << "My Game" << "\n";
};
};
int main(){
MyGame *child = new MyGame;
child->run();
return 0;
}
In C++ you need to specifically declare a function to be virtual:
class BaseClass {
virtual void speak () {
...
}
};
In C++ a method can only be overridden if it was marked virtual. You can think of virtual as a synonym for "overridable".
The virtual keyword has to appear in the base class. It may also appear optionally in the subclasses at the point of override, but it does not have to.
If you are using a compiler that supports C++11 (and you should if you are learning C++), I recommend that you always use the new override keyword when you mean to override:
class Base {
public:
virtual void speak() {
std::cout << "Base";
}
};
class Derived : public Base {
public:
void speak() override { // <---
std::cout << "Derived";
}
};
If the method isn't actually an override, the compiler will tell you so by giving an error.
It is not always obvious on the first read whether a method is an override. For example the following is correct thanks to return type covariance:
class A {};
class B : public A {};
class Base {
public:
virtual A* foo() {
return nullptr;
}
};
class Derived : public Base {
public:
B* foo() override {
return nullptr;
}
};
This might not be useful very often, but override makes it clear in case someone has to read it.
Also, if you have at least one virtual method in your class, also make its destructor virtual. This will assure that all the destructors will run when needed and things get cleaned up properly:
class App {
public:
App() {}
virtual ~App() {} // <---
void run() {
this->speak();
}
virtual void speak() {
std::cout << "Base\n";
};
};

Derived Class Function Not Called

I am experiencing a problem where a derived class does not have it's own version of a function called when it is called from a base class pointer. To better explain the classes are defined as below
Class Foo
{
public:
Foo();
virtual ~Foo();
virtual void Event();
}
//-----------------------
Class FooBar : public Foo
{
public:
FooBar();
virtual void Update() = 0;
virtual void Draw() = 0;
}
//-----------------------
Class FinalFoo : public FooBar
{
public:
FinalFoo();
void Update();
void Draw();
void Event();
}
There are other classes similar to FinalFoo. So I attempt to call Event on a pointer to a Foo object expecting that it would call the derived implementation. However, it would appear that it calls the base class version and that is all
FinalFoo* myThing = new FinalFoo();
Foo* baseThing = myThing;
baseThing->Event(); // I expected this to call FinalFoo::Event()
Assuming the above code is corrected, it actually does call FinalFoo::Event(). below is a complete and compilable example. Note, that it also adds the keyword override in strategic points: I'd bet that adding override in the original code, too (and compiling with a compiler aware of this keyword) would point out that your override isn't one.
#include <iostream>
class Foo
{
public:
virtual ~Foo() {}
virtual void Event() { std::cout << "Foo::Event()\n"; }
};
//-----------------------
class FooBar : public Foo
{
public:
virtual void Update() = 0;
};
//-----------------------
class FinalFoo : public FooBar
{
public:
FinalFoo() {}
void Update() override { std::cout << "FinalFoo::Update()\n"; }
void Event() override { std::cout << "FinalFoo::Event()\n"; }
};
int main()
{
FinalFoo myThing;
Foo* baseThing = &myThing;
baseThing->Event();
}