Edit update all schedules except primary key in Django Rest Framework - django

I wanna change all fields of a json object except 'pk' in DRF. I just need to keep one json data. When adding a new data ,this one should override existing data. Is there a way to do it with django ?
my models.py
class ClientUser2(models.Model):
phone_number = models.CharField(max_length=20,unique=True)
name = models.CharField(max_length=100,blank=True)
status = models.IntegerField(default=1)
class ClientNameSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = ClientUser2
fields = ('url','phone_number','name','status','pk')
my views.py
class ClientViewSet(viewsets.ModelViewSet):
"""
API endpoint that allows messages to be viewed or edited.
"""
queryset = ClientUser2.objects.all()
serializer_class = ClientNameSerializer
and it's my api root
api_root

If you want to be able to only retrieve and update models you can use RetrieveUpdateApiView
Reference : https://www.django-rest-framework.org/api-guide/generic-views/#retrieveupdateapiview

Related

How can I create model instance via Serializer without creating models from nested serialziers?

I have model with many links into it:
class Travel(BaseAbstractModel):
tags = models.ManyToManyField(
Tag,
related_name='travels',
)
owner = models.ForeignKey(
'users.TravelUser',
related_name='travel_owner'
)
payment = models.ForeignKey(
Payment,
related_name='travels',
)
country = models.ForeignKey(
Country,
related_name='travels,
)
........
Many of these models have only two fields with unique name and image.
I create serializer for each of these models and put them in TravelSerializer
class TravelBaseSerializer(DynamicFieldsModelSerializer):
owner = UserSerializer(required=False)
tags = TagSerializer(many=True)
payment = PaymentSerializer()
country = CountrySerializer()
Based on docs I override create() and update.
The problem is, when I sent JSON data, Django create each model from nested serializers. But I want to create only Travel instance. Also I want receive and respond serialized object not only pk field.
UPDATE
I solved this problem, put code in the answer. Now I can receive and respond with Serializer data without creating object.
But I think the DRF provides more elegant approach then I do. It is my first project with DRF, maybe I miss something and there's an easier solution.
I decide override to_internal_value() put it in custom serailizer and inherit all nested serializers from it:
class NestedRelatedSerializer(serializers.ModelSerializer):
def to_internal_value(self, data):
try:
pk = data['pk']
except (TypeError, KeyError):
# parse pk from request JSON
raise serializers.ValidationError({'_error': 'object must provide pk!'})
return pk
Get all pk from it and save in create and updated methods:
def update(self, instance, validated_data):
# If don't get instance from db, m2m field won't update immediately
# I don't understand why
instance = Travel.objects.get(pk=instance.pk)
instance.payment_id = validated_data.get('payment', instance.payment_id)
instance.country_id = validated_data.get('country', instance.country_id)
# update m2m links
instance.tags.clear()
instance.tags.add(*validated_data.get('tags'))
instance.save()
return instance
I'm not exactly sure I understand what you want to do, but could setting read_only_fields is the Meta class be what you need ?
class TravelBaseSerializer(DynamicFieldsModelSerializer):
owner = UserSerializer(required=False)
tags = TagSerializer(many=True)
payment = PaymentSerializer()
country = CountrySerializer()
class Meta:
read_only_fields = ('tags',)
See this section in the docs.

Django Rest Framework Update or Create if not exists

I want to use the perform an update or create in django-rest-framework, by passing or not the id field. I've got this model
class Etiqueta(models.Model):
name_tag = models.CharField(max_length=200, blank=False, null=False)
description_tag = models.TextField(max_length=500, blank=False, null=False)
def __unicode__(self):
return self.name_tag
And in django-rest-framework I've got this serializer
from myapp.modulos.estado_1.models import Etiqueta
from rest_framework import serializers, viewsets
# Serializers define the API representation.
class TagSerializer(serializers.ModelSerializer):
class Meta:
model = Etiqueta
fields = (
'id',
'name_tag',
'description_tag'
)
# ViewSets define the view behavior.
class TagViewSet(viewsets.ModelViewSet):
queryset = Etiqueta.objects.all()
serializer_class = TagSerializer
Normally when I create an object, I perform a POST to the URL without the /:id, but if I've got an object with a local id, I want him to be created in the REST with the same id (remote id), django overwrite my local id and creates a new one. Does anybody know how achieve this? Also it is important to mention that I'm working with google-app-engine, google-cloud-datastore and django-dbindexer.
This code should work for your case -
class TagViewSet(viewsets.ModelViewSet):
queryset = Etiqueta.objects.all()
serializer_class = TagSerializer
def get_object(self):
if self.request.method == 'PUT':
obj, created = Etiquetta.objects.get_or_create(pk=self.kwargs.get('pk'))
return obj
else:
return super(TagViewSet, self).get_object()
You should have a look at how Django REST framework does currently and adapts your create method to update whenever you have an id field.
The original ViewSet.create is here and the ViewSet.update is here.
Please note that you will probably end up with two different serializers for /tag/ and /tag/:id since the later should not allow the id field to be writable while the former should.
I've write a drf views mixin for updating an object by id, if no corresponding object, just create it then update.

Django Rest Framework auto increment primary key value

I'm new to using the DRF so I apologize if this is a trivial question but I've had no luck finding an answer thus far.
I'm using DRF along with Angularjs to create a single page application. When I make posts to my API I get this error to create a new Task object: task_id: [This field is required.] task_id is my primary key on this object. How can I make it so that it gets incremented automatically like it would on a Django Model Form?
class TaskSerializer(serializers.ModelSerializer):
class Meta:
model = Task
fields = ('route', 'date', 'task_id', )
class AddTask(generics.CreateAPIView):
serializer_class = TaskSerializer
def get(self, request, format=None):
response = {}
response['form'] = TaskForm().as_p()
return Response(response)
Are you using task_id in your application page? If not, then remove it from the serializer and DRF will automatically take care of this for you.
Something like this:
class TaskSerializer(serializers.ModelSerializer):
class Meta:
model = Task
fields = ('route', 'date',)

Django Restframework update manytomany via through table

I have following models and one another ClientWarehouse. For some reasons i have to create ManyToManyField Relation via a through table named RouteInfo
class Route(models.Model):
user = models.ForeignKey(User)
warehouse = models.ManyToManyField(ClientWarehouse,
verbose_name='Warehouse Location',
through='RouteInfo',
blank=True, null=True)
class RouteInfo(models.Model):
route = models.ForeignKey(Route)
warehouse = models.ForeignKey(ClientWarehouse)
i have following serializer class writtern
class RouteInfoSerializer(serializers.ModelSerializer):
class Meta:
model = RouteInfo
class RouteSerializer(serializers.ModelSerializer):
warehouse = serializers.PrimaryKeyRelatedField(many=True, read_only=True)
class Meta:
model = Route
And Following Viewset
class RouteViewSet(viewsets.ModelViewSet):
model = Route
def get_object(self, pk):
try:
return Route.objects.get(pk=pk)
except Route.DoesNotExist:
raise Http404
def create(self, request, format=None):
r = RouteSerializer(data=request.DATA)
if r.is_valid():
r.save()
return Response(r.data, status=status.HTTP_201_CREATED)
return Response(r.errors, status=status.HTTP_400_BAD_REQUEST)
However on going through the documentation of DRF i found that it does not support write operations on a ManytoManyField via through table.
Currently when i try to save the route via the api call, it does not save the clientwarehouse, ie the RouteInfo table is not created, but the Route object is created with no clientwarehouse in it.
Is there any way i can update the through table ie RouteInfo while creating a route in Route table.
Alternatively i found that i can acomplish the same by first saving the Route Instance and the using the Route.id and warehouse to save into RouteInfo model.
Hence this turned into two step process. First saving the original model and then saving the through model.

Django REST framework and creating two table entries from a POST form

I want to create entries in two tables (Log and Post) using the DRF Browseable API POST form.
The example below is contrived, but it outlines what I am trying to do.
class Post(models.Model):
info = models.CharField()
class Log(TimeStampedModel):
ip = models.GenericIPAddressField(('IP Address'))
name = models.CharField()
data = models.ForeignKey(Post)
I want to use the browseable API to submit a form to create a Log entry. Here are the serializers:
class PostSerializer(serializers.ModelSerializer):
class Meta:
model = Post
fields = ('info',)
class LogSerializer(serializers.ModelSerializer):
data = serializers.Field()
class Meta:
model = Log
fields = ('ip', 'name', 'data')
The problem with the above is that serializer.Field is read only so does not show up on the POST form. If I change it to CharField it shows up, but then I get an error because an instance of a Post is expected not just a field of the Post object.
Here are my views:
class LogMixin(object):
queryset = Log.objects.all()
serializer_class = LogSerializer
class LogList(LogMixin, ListCreateAPIView):
pass
class LogDetail(LogMixin, RetrieveUpdateDestroyAPIView):
pass
What's the correct way of doing this?
From what I can tell you want to create a nested Log object. There are 2 ways of doing this:
Send 2 POST Requests, One to create the Post, and the other to create the Log contained the received HTTP 200 data from the API.
(Django and best way) Send the data all in one POST and parse it server side. Django Rest Framework takes care of this for you.
I have changed your code so that it should work.
Source
class LogSerializer(serializers.ModelSerializer):
class Meta:
model = Log
fields = ('ip', 'name')
class PostSerializer(serializers.ModelSerializer):
log = LogSerializer()
class Meta:
model = Post
fields = ('info', 'log')
views.py
import generics
class PostCreateAPIView(generics.CreateAPIView):
model = Post
serializer_class = PostSerializer
Then you can send a POST Request containing 'info', 'ip', and 'name'.
This is a hacky way and the best way to use the nested serializer as stated above. But just to show another way I am posting it here.
# Add New Item
#api_view(('POST',))
def add_new_item(request):
request.data['areaname_name'] = request.data['item_areaname']
request.data['buildingname_name'] = request.data['item_buildingname']
item_serializer = TblItemSerializer(data=request.data)
area_name_serializer = TblAreanameSerializer(data=request.data)
building_name_serializer = TblBuildingnameSerializer(data=request.data)
response = []
if item_serializer.is_valid() & area_name_serializer.is_valid() & building_name_serializer.is_valid():
# Save To Item Table
item_serializer.save()
# Save Unique Values Into Areaname and Buildingname Tables
area_name_serializer.save()
building_name_serializer.save()
return Response(item_serializer.data, status=status.HTTP_201_CREATED)
else:
response.append(item_serializer.errors)
response.append(area_name_serializer.errors)
response.append(building_name_serializer.errors)
return Response(response, status=status.HTTP_400_BAD_REQUEST)
In the error response you could also use (depending on how you want to handle on client side)
merge = {**item_serializer.errors, **area_name_serializer.errors, **building_name_serializer.errors}
return Response(merge, status=status.HTTP_400_BAD_REQUEST)