Using Notepad++, how do I replace a word with a number within ()?
For instance, replace the word "serial" with "(1234)"? When I try to do this, the word "serial" is replaced with "1234", but without the parens.
In Notepad++ the parenthesis have to be escaped in the replacement part.
Ctrl+H
Find what: serial
Replace with: \(1234\)
CHECK Wrap around
CHECK Regular expression
Replace all
Screen capture (before):
Screen capture (after):
Choosing Extended (\n,\r,\t,\0, \x...) as the Search Mode and just specifying (1234) as the Replace with value worked fine.
The answer by Toto solves my problem.
In Notepad++ the parenthesis have to be escaped in the replacement part.
Ctrl+H
Find what: serial
Replace with: (1234)
CHECK Wrap around
CHECK Regular expression
Replace all
Related
I built an expression to find any instances of '[###]' in Notepad++ for a given file:
[1]0x0a[22]0xbb[33]0xcc
and replace them with whitespace. Seems easy enough...
(\[[0-9]\]|\[[0-9][0-9]\]|\[[0-9][0-9][0-9]\])
and permutations of
/(\[[0-9]\]|\[[0-9][0-9]\]|\[[0-9][0-9][0-9]\])g
They did not yield any matches.
I tested this out on http://extendsclass.com/regex-tester.html and it worked as expected.
Am I missing some nuance for Regex in Notepad++? And, yes, I did have Search mode set for "Regular Expression".
My question is not a duplicate of this one: Delete brackets and numbers via Notepad++
My Regex works, just not in the version of Notepad++ I am using.
Ctrl+H
Find what: \[\d+\]
Replace with: A SPACE
CHECK Wrap around
CHECK Regular expression
Replace all
Explanation:
\[ # opening bracket
\d+ # 1 or more digits
\] # closing bracket
Screenshot (before):
Screenshot (after):
Good Morning in my timezone
I want to replace a character that is in the beginning of each line
So i had used the following regular expression to find the text
^\d
And it works fine in finding all the characters
The problem is in the replace with
I want to replace with single quote followed by the same character found above
How can i do it ?
Thanks in advance
You may try this option:
Find:
^(?=\d)
Replace:
' <-- just a single quote
The find pattern uses a positive lookahead which asserts that the first character is a digit, but nothing is ever matched. Then, the replacement is a single quote.
You may use
Find What: ^\d
Replace With: '$0
where $0 is the backreference to the match value.
Another one would be:
Find:
^(\d)
Replace:
'\1
In this example \1 would be 1st captured group.
How to find the text between the second and fourth slashes in a path like /folder/subfolder-1/subfolder-2/subfolder-3? I’m trying to replace this with something like /folder/new-folder/subfolder-3.
The most important for me is to be able to find the part after the n-th slash.
I tried the regex /((.*?)/){3}, but it doesn’t work.
Using Match resetter \K meta-character you are able to do it in a simpler way.
Find:
/.*?/\K(.*?/){2}
Replace with:
new-folder/
One way you could to it is by using this string in the pattern to replace
(/.+?)(/.+?){2}(/\S+)
And use this one in your pattern to replace it with
$1/new-folder$3
From your string:
/folder/subfolder-1/subfolder-2/subfolder-3
(/.+?) will match /folder as $1
(/.+?){2} will match /subfolder-1/subfolder-2 as $2 (not used)
(/\S+) will match everything that isn't a space, in this case/subfolder-3 as $3
Leaving you room to insert your new-folder in-between.
How can I just mark till the slash?
Find what: (/[^/]+/)[^/]+/[^/]+
Replace with: $1new-folder
To find text between second and forth slash you can use the regex ^(/[^/]*/)([^/]*/[^/]*) then you can reference to the text between slashes with \2 when replacing the text.
To keep the text before the slashes you can enter something like \1myNewTextBetweenSlashes2and4.
In notepad++ Find by this:
(/[^/]+)(?:/[^/]+/[^/]+/)(.*)
And Replace by this:
\1\/new-folder/\2
Make sure that: .matches newline is not checked
{2} indicates 2 levels after first level will be repalced by new-folder
Find:
(\/.*?\/)(.*?\/){2}(.*)
Replace:
$1new-folder/$3
Demo: https://regex101.com/r/XIA3IN/3
I would like to replace the single quotes from the number in the below text.
('28','Harry Potter');
The output required is
(28,'Harry Potter');
What kind of regex is required to remove the quotes in Word/notepad++ ?
How about:
Ctrl+H
Find what: '(\d+)'
Replace with: $1
Then click on Replace all
This will remove all single quotes arround digits.
For Word 2010:
Use
Find what:
([0-9]{2,})
replace with:
\1
I have looked around and found good answers but none work with notepad++, most are for java and php. I have found the search strings below but obviously I'm a noob with regex as i don't know what open/close tags are proper in notepad++.
I would like to add a space before each capital letter.
Example:
StackOverflowKegger
becomes
Stack Overflow Kegger
This is what i have found.
Find: [a-z]+[A-Z]+
Replace: $1 (there is a space before the $)
Find:
(?<!^)((?<![:upper:])[:upper:]|[:upper:](?![:upper:]))
("(\\p{Ll})(\\p{Lu})","$1 $2")
(?!^)(?=[A-Z])
Any help would be appreciated.
Search string: (.)([A-Z])
Replacement: \1 \2
This doesn't insert spaces before capitals that are the first letter on their line.
In Notepad++, do a search-n-Replace (ctrl+h), in 'find what' input '([a-z])([A-Z])' without single quotes. in 'Replace with' input '\1 \2' without quotes.
Select radio button 'Regular Expression' and make sure you Check 'Match Case' checkbox. Now find next and keep replacing. it will convert camel or Pascal case strings into words with a space before every capital letter except the first.
Hope it is helpful. I just used it with one of my tasks.
Find: ^([A-Z])
Replace: \1
this will add a space to the first uppercase character in notepad++
Make sure you put the space before the \1 in the replace section.
WABET : <-from
WABET : <-to
Find what: .\K([A-Z])
Replace with: $1 a space before $1
Note!!!!!! Must to check match-case see in attached photo.
If you can live with a space before the first word, then this solution worked for me.
I used the following with the Regular Expression radio button checked.:
Find what: ([A-Z])
Replace With: \1
Note the leading space before the \1 in the replace