"cout<<count<<endl;" isn't printing anything - c++

Question

cout<<count<<endl; sould provide an output according to the conditions , but it isn't printing anything, what is the fault/error/defects in the code that are causing such results ?
it is my first question , sorry if i am not completely understandable.
i used the following code , i can't understand whats happening here.this is a simple input output question. the output provides us info about matching two team's uniform.
#include <stdio.h>
#include <iostream>
using namespace std;
main(){
int a;
cin>>a;
int **b;
b=new int*[a];
for (int i = 0; i < a; i++)
{
b[i]=new int[2];
for (int j = 0; j <2 ; j++)
{
cin>>b[i][j];
}
}
int count=0;
for (int i = 0; i < a*(a-1); i++)
{ for (int j = 0; j < a; j++)
if (b[i][0]==b[j][1])
count=count+1;
}
cout<<count<<endl;
for (size_t i = 0; i < a; i++)
{
delete b[i];
}
delete b;
}
input:
3
1 2
2 4
3 4
output does not contain anything

Answer 1

You use the array out of bounds and delete when you should delete[]. Comments in code:
#include <iostream> // use the correct headers
#include <cstddef>
// not recommended: https://stackoverflow.com/questions/1452721/why-is-using-namespace-std-considered-bad-practice
using namespace std;
int main() { // main must return int
size_t a; // better type for an array size
cin >> a;
int** b;
b = new int*[a];
for(size_t i = 0; i < a; i++) {
b[i] = new int[2];
for(size_t j = 0; j < 2; j++) {
cin >> b[i][j];
}
}
int count = 0;
std::cout << a * (a - 1) << "\n"; // will print 6 for the given input
for(size_t i = 0; i < a * (a - 1); i++) {
// i will be in the range [0, 5]
for(size_t j = 0; j < a; j++)
if(b[i][0] == b[j][1]) count = count + 1;
// ^ undefined behaviour
}
cout << count << endl;
for(size_t i = 0; i < a; i++) {
delete[] b[i]; // use delete[] when you've used new[]
}
delete[] b; // use delete[] when you've used new[]
}