Get the level of nodes - xslt

Question

I want to get the level of <li> in my input
input:
<ol start="1" style="1">
<li>
<p type="List Number Level 1">Text 1.</p>
</li>
<li>
<p type="List Number Level 1">Text 2</p>
<ol start="1">
<liFormat><iRef style="a"/>)<t/></liFormat>
<li>
<p type="List Number Level 2">Text 3.</p>
</li>
<li>
<p type="List Number Level 2">Text 4.</p>
</li>
</ol>
</li>
<li>
<p type="List Number Level 1">Text 5.</p>
</li>
</ol>
Output should be :
<ol start="1" style="1">
<li>
<p type="List_1_First">Text 1.</p>
</li>
<li>
<p type="List_1_First">Text 2</p>
<ol start="1">
<liFormat><liRef style="a"/>)<t/></liFormat>
<li>
<p type="List_2_First">Text 3.</p>
</li>
<li>
<p type="List_2_First">Text 4.</p>
</li>
</ol>
</li>
<li>
<p type="List_1_First">Text 5.</p>
</li>
</ol>
Tried code :
<xsl:template match="ol[#start]/li[1]/p[contains(#type,'List')]" priority="30">
<p type="List_{count(li)}_First">
<xsl:apply-templates/>
</p>
</xsl:template>
Here all things have been implemented as i expected. But I have to take the level of li. ex : List_{li level}_First . Nut that par not working properly. I have mentioned my tried code. I am using xslt 2.0.
Thank you

Answer 1

I think you need to count the ancestors here:
<tps:p type="List_{count(ancestor::tps:li)}_First">
Maybe you have other templates in your XSLT, but your current template only matches the first li element under the ol. To get your expected output, maybe you need to do this...
<xsl:template match="tps:ol[#start]/tps:li/tps:p[contains(#type,'List')]" priority="30">
See http://xsltfiddle.liberty-development.net/gWEamKJ for an example.