Regex to find date string - regex

Question

I have many sites on which I need to find the date, all of these sites have different templates, so I need a regular expression, here are examples of how dates are displayed on these sites:
Saturday, March 24, 2007
1 JANUARY 2016
31st December 2016
23 Agustus 2019
2012年5月7日
August 23, 2019
I tried to do something like this:
re.search(r"((\w+\s\w+(,\s|\s)\w+)|(\w+[0-9]\w))", text)
But during the test, I got this:
2014 jQuery Foundation
81vy4jRyxBHyxIhY67E
How to write a regular expression in my case?

Answer 1

You might have to write some custom expressions, then use alternation, maybe a bit similar to:
^[A-Z][A-Za-z]+[\s,]*[A-Z][A-Za-z]+[\s,]*\d+[\s,]*\d{4}|\d+[A-Za-z]*[\s,]*[A-Z][A-Za-z]+[\s,]*\d{4}|[A-Z][A-Za-z]*[\s,]*\d+[\s,]*\d{4}|\d{4}\D+\d+\D+\d+\D+$
which would likely fail for some instances, which you might want to adjust for. It'd be much better to add much more boundaries.
If you wish to explore/simplify/modify the expression, it's been
explained on the top right panel of
regex101.com. If you'd like, you
can also watch in this
link, how it would match
against some sample inputs.
Test
import re
regex = r"^[A-Z][A-Za-z]+[\s,]*[A-Z][A-Za-z]+[\s,]*\d+[\s,]*\d{4}|\d+[A-Za-z]*[\s,]*[A-Z][A-Za-z]+[\s,]*\d{4}|[A-Z][A-Za-z]*[\s,]*\d+[\s,]*\d{4}|\d{4}\D+\d+\D+\d+\D+$"
test_str = """
Saturday, March 24, 2007
1 JANUARY 2016
31st December 2016
23 Agustus 2019
2012年5月7日
August 23, 2019
2014 jQuery Foundation
81vy4jRyxBHyxIhY67E
"""
print(re.findall(regex, test_str, re.M))
Output
['Saturday, March 24, 2007', '1 JANUARY 2016', '31st December 2016', '23 Agustus 2019', '2012年5月7日 ', 'August 23, 2019']
RegEx Circuit
jex.im visualizes regular expressions: