Django next page in pagination on form submission - django

Question

def listing(request):
contact_list = Question.objects.all()
paginator = Paginator(contact_list, 1) # Show 25 contacts per page
page = request.GET.get('page')
contacts = paginator.get_page(page)
Let's say in each page I have a form, and when the form submitted I need to go to the next page.
I first tried to add a hidden field in the form, and manually calculate the next page, and put into HTTPResponseRedirect, but then I get an empty object error for the last page because of the following:
<input type="hidden" name="next" value="?page={{ contacts.next_page_number }}">
That page contains no results
{% for contact in contacts %}
{# Each "contact" is a Contact model object. #}
{{ contact.question_text|upper }}<br>
...
<form action="{% url 'listing' %}" method="post">
{% csrf_token %}
{% for choice in contact.choice_set.all %}
<input type="radio" name="choice" id="choice{{ forloop.counter }}" value="{{ choice.id }}">
<label for="choice{{ forloop.counter }}">{{ choice.choice_text }}</label><br>
<input type="hidden" name="next" value="?page={{ contacts.next_page_number }}">
{% endfor %}
<input type="submit" value="Vote">
</form>
{% endfor %}
<div class="pagination">
<span class="step-links">
{% if contacts.has_previous %}
« first
previous
{% endif %}
<span class="current">
Page {{ contacts.number }} of {{ contacts.paginator.num_pages }}.
</span>
{% if contacts.has_next %}
next
last »
{% endif %}
</span>
</div>
So what should be my strategy? Do I need to create a seperate view for form action, or should I use listing as form action and check wheter it is a GET/POST method, I am kind of lost here.