Transform a dynamic alphanumeric string - regex

I have a Build called 700-I20190808-0201. I need to convert it to 7.0.0-I20190808-0201. I can do that with regular expression:
sed 's/\([0-9]\)\([0-9]\)\([0-9]\)\(.\)/\1.\2.\3\4/' abc.txt
But the solution does not work when the build ID is 7001-I20190809-0201. Can we make the regular expression dynamic so that it works for both (700 and 7001)?


Could you please try following.
awk 'BEGIN{FS=OFS="-"}{gsub(/[0-9]/,"&.",$1);sub(/\.$/,"",$1)} 1' Input_file


If you have Perl available, lookahead regular expressions make this straightforward:
$ cat foo.txt
700-I20190808-0201
7001-I20190809-0201
$ perl -ple 's/(\d)(?=\d+\-I)/\1./g' foo.txt
7.0.0-I20190808-0201
7.0.0.1-I20190809-0201


You can implement a simple loop using labels and branching using sed:
$ echo '7001-I20190809-0201' | sed ':1; s/^\([0-9]\{1,\}\)\([0-9][-.]\)/\1.\2/; t1'
7.0.0.1-I20190809-0201
$ echo '700-I20190809-0201' | sed ':1; s/^\([0-9]\{1,\}\)\([0-9][-.]\)/\1.\2/; t1'
7.0.0-I20190809-0201
If your sed support -E flag:
sed -E ':1; s/^([0-9]+)([0-9][-.])/\1.\2/; t1'


sed -e 's/\([0-9]\)\([0-9]\)\([0-9]\)\(.\)/\1.\2.\3.\4/' -e 's/\.\-/\-/' abc.txt
This worked for me, very simple one. Just needed to extract it in my ant script using replaceregex pattern

Related

sed not performing expected substitution

I have a bash variable, some file path (with spaces) and filename, e.g:
$ echo $tmp
/home/xyz/some/path/with spaces/AlbumArt_{random-number-sequence}_Large.jpg
When I attempt to identify the filename part with grep, e.g:
$ echo "$tmp" | egrep 'AlbumArt.*Large.jpe?g$'
/home/xyz/some/path/with spaces/**AlbumArt_{random-number-sequence}_Large.jpg**
The filename part appears to be identified correctly, but when I attempt to convert this to a sed substitution expression, e.g:
$ echo "$tmp" | sed 's#AlbumArt.*Large.jpe?g$#NewString#'
/home/xyz/some/path/with spaces/AlbumArt_{random-number-sequence}_Large.jpg
The expected substitution isn't happening. Thanks in advance for any help.

In fact egrep is a variant of grep -E, allowing to 'activate' extended regular expression (you can see: https://en.wikipedia.org/wiki/Regular_expression#Standards).
Thus, you just need to use the same option with sed:
echo "$tmp" | sed -E 's#AlbumArt.*Large.jpe?g$#NewString#'

Swap columns in bash using SED without using loop

I'm new to Sed, I'm trying to learn some pattern using Sed.
I got a filenamne.txt that has the following entry:
ppp/jjj qqq/kkk rrr/lll
My goal is to swap the word before the slash and the word after the slash in each of the three word1/word2 columns:
jjj/ppp kkk/qqq lll/rrr
I tried using sed –re ‘s!(.*)(/)(.*)!\1\2\!’ filename.txt, but it didn't work. Any idea how can I go about it?

$ echo "ppp/jjj qqq/kkk rrr/lll" | sed -e 's/$/ /' -e 's!\([^/]*\)/\([^ ]*\) !\2/\1 !g'
jjj/ppp kkk/qqq lll/rrr

Use replacement in perl command-line is a lot more straight-forward :-
perl -pe 's/(\w+)\/(\w+)/$2\/$1/g' file
jjj/ppp kkk/qqq lll/rrr

$ sed 's#\([^ ]*\)/\([^ ]*\)#\2/\1#g' file
jjj/ppp kkk/qqq lll/rrr

BASH: replacing PERL with SED for in-place substitution

Would like to replace this statement with perl:
perl -pe "s|(?<=://).+?(?=/)|$2:80|"
with
sed -e "s|<regex>|$2:80|"
Since sed has a much less powerful regex engine (for example it does not support look-arounds) the task boils down to writing a sed compatible regex to match only a domain name in a fully qualitied URL. Examples:
http://php2-mindaugasb.c9.io/Testing/JS/displayName.js
http://php2-mindaugasb.c9.io?a=Testing.js
http://www.google.com?a=Testing.js
Should become:
http://$2:80/Testing/JS/displayName.js
http://$2:80?a=Testing.js
http://$2:80?a=Testing.js
A solution like this would be ok:
sed -e "s|<regex>|http://$2:80|"
Thanks :)

Use the below sed command.
$ sed "s~//[^/?]\+\([?/]\)~//\$2:80\1~g" file
http://$2:80/Testing/JS/displayName.js
http://$2:80?a=Testing.js
http://$2:80?a=Testing.js
You must need to escape the $ at the replacement part.

sed 's|http://[^/?]*|http://$2:80|' file
Output:
http://$2:80/Testing/JS/displayName.js
http://$2:80?a=Testing.js
http://$2:80?a=Testing.js

How to cut a string from a string

My script gets this string for example:
/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file
let's say I don't know how long the string until the /importance.
I want a new variable that will keep only the /importance/lib1/lib2/lib3/file from the full string.
I tried to use sed 's/.*importance//' but it's giving me the path without the importance....
Here is the command in my code:
find <main_path> -name file | sed 's/.*importance//
I am not familiar with the regex, so I need your help please :)
Sorry my friends I have just wrong about my question,
I don't need the output /importance/lib1/lib2/lib3/file but /importance/lib1/lib2/lib3 with no /file in the output.
Can you help me?

I would use awk:
$ echo "/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file" | awk -F"/importance/" '{print FS$2}'
importance/lib1/lib2/lib3/file
Which is the same as:
$ awk -F"/importance/" '{print FS$2}' <<< "/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file"
importance/lib1/lib2/lib3/file
That is, we set the field separator to /importance/, so that the first field is what comes before it and the 2nd one is what comes after. To print /importance/ itself, we use FS!
All together, and to save it into a variable, use:
var=$(find <main_path> -name file | awk -F"/importance/" '{print FS$2}')
Update
I don't need the output /importance/lib1/lib2/lib3/file but
/importance/lib1/lib2/lib3 with no /file in the output.
Then you can use something like dirname to get the path without the name itself:
$ dirname $(awk -F"/importance/" '{print FS$2}' <<< "/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file")
/importance/lib1/lib2/lib3

Instead of substituting all until importance with nothing, replace with /importance:
~$ echo $var
/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file
~$ sed 's:.*importance:/importance:' <<< $var
/importance/lib1/lib2/lib3/file
As noted by #lurker, if importance can be in some dir, you could add /s to be safe:
~$ sed 's:.*/importance/:/importance/:' <<< "/dir1/dirimportance/importancedir/..../importance/lib1/lib2/lib3/file"
/importance/lib1/lib2/lib3/file

With GNU sed:
echo '/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file' | sed -E 's#.*(/importance.*)#\1#'
Output:
/importance/lib1/lib2/lib3/file

pure bash
kent$ a="/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file"
kent$ echo ${a/*\/importance/\/importance}
/importance/lib1/lib2/lib3/file
external tool: grep
kent$ grep -o '/importance/.*' <<<$a
/importance/lib1/lib2/lib3/file

I tried to use sed 's/.*importance//' but it's giving me the path without the importance....
You were very close. All you had to do was substitute back in importance:
sed 's/.*importance/importance/'
However, I would use Bash's built in pattern expansion. It's much more efficient and faster.
The pattern expansion ${foo##pattern} says to take the shell variable ${foo} and remove the largest matching glob pattern from the left side of the shell variable:
file_name="/dir1/dir2/dir3.../importance/lib1/lib2/lib3/file"
file_name=${file_name##*importance}

Removeing the /file at the end as you ask:
echo '<path>' | sed -r 's#.*(/importance.*)/[^/]*#\1#'
Input /dir1/dir2/dir3.../importance/lib1/lib2/lib3/file
Returns: /importance/lib1/lib2/lib3
See this "Match groups" tutorial.

Remove substring till first Token using regexp

I have the Path:
GarbageContainingSlashesAndDots/TOKEN/xyz/TOKEN/abc
How coukt I remove GarbageContainingSlashesAndDots?
I know, it is before TOKEN, but Unfortunately, there are two substrings TOKEN in string.
using sed s/.*TOKEN// makes my string to /abc,
but I need /TOKEN/xyz/TOKEN/abc
Thank You!!!

Divide and conquer:
$ echo 'Garbage.Containing/Slashes/And.Dots/TOKEN/xyz/TOKEN/abc' |
sed -n 's|/TOKEN/|\n&|;s/.*\n//;p'
/TOKEN/xyz/TOKEN/abc

Is perl instead of sed allowed?
perl -pe 's!.*?(?=/TOKEN)!!'
echo 'GarbageContainingSlashesAndDots/TOKEN/xyz/TOKEN/abc' | perl -pe 's!.*?(?=/TOKEN)!!'
# returns:
/TOKEN/xyz/TOKEN/abc
Sed does not support non-greedy matching. Perl does.

I think you have bash, so it can be a simple as
$ s="GarbageContainingSlashesAndDots/TOKEN/xyz/TOKEN/abc"
$ echo ${s#*/}
TOKEN/xyz/TOKEN/abc
or if you have Ruby(1.9+)
echo $s | ruby -e 'print gets.split("/",2)[-1]'

Thank you for all suggestions, I've learnt something new.
Finally I was able to reach my goal using grep -o
echo "GarbageContainingSlashesAndDots/TOKEN/xyz/TOKEN/abc" | grep -o "/TOKEN/.*/TOKEN/.*"

Using grep:
word='GarbageContainingSlashesAndDots/TOKEN/xyz/TOKEN/abc'
echo $word | grep -o '/.*'

echo "./a//...b/TOKEN/abc/TOKEN/xyz"|sed 's#.*\(/TOKEN/.*/TOKEN/.*\)#\1#'

UPDATE 2: have you tried this?
s!.*\(/TOKEN.+TOKEN.*\)!\1!
UPDATE: sorry, non-greedy matches are not supported by sed
Try this:
s/.*?TOKEN//
.*? matches only for the first occurance of TOKEN.