How to write words from a file to an array [duplicate] - c++

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Read file line by line using ifstream in C++
(8 answers)
Closed 3 years ago.
I cant write a words from a file to an array.
I have tried to use char and strings, but i have problem with both of them.
FILE *file = fopen("films.txt", "r");
string FILMS[500];
while (!feof(file))
{
fscanf(file, "%s", FILMS);
//fgets(FILMS, 500, file);
}
I expect that in each cell there will be a word.

Use the C++ classes and functions to make it easier. Instead of a fixed C style array of exactly 500 films, use a std::vector<std::string>> that will grow dynamically when you put film titles in it.
#include <fstream>
#include <iostream>
#include <string>
#include <vector>
std::vector<std::string> get_films() {
std::ifstream file("films.txt");
std::vector<std::string> FILMS;
if(file) { // check that the file was opened ok
std::string line;
// read until getline returns file in a failed/eof state
while(std::getline(file, line)) {
// move line into the FILMS vector
FILMS.emplace_back(std::move(line));
// make sure line is in a specified state again
line.clear();
}
}
return FILMS;
} // an fstream is automatically closed when it goes out of scope
int main() {
auto FILMS = get_films();
std::cout << "Read " << FILMS.size() << " film titles\n";
for(const std::string& film : FILMS) {
std::cout << film << "\n";
}
}

As I'm not sure why you tried using c style arrays and files, I posted a 'not too elegant' solution like that one, too, hoping it might help. You could always try to make it more dynamic with some malloc (or new), but I sticked with the easy solution for now.
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
void readcpp(const char* fname, std::vector<std::string>& data)
{
std::ifstream file_in(fname, std::ios::in);
if (file_in.is_open())
{
std::string film;
while (std::getline(file_in, film))
{
data.push_back(film);
}
file_in.close();
}
else std::cerr << "file cant be opened" << std::endl;
}
#include <cstdio>
#include <cstdlib>
#include <cstring>
void readc(const char* fname, char data[500][500])
{
FILE* file_in = fopen(fname, "r");
if (file_in)
{
char film[500];
for (unsigned int i = 0; fgets(film, 500, file_in) && i < 500; i++)
{
memcpy(data + i, film, 500);
}
fclose(file_in);
}
else fprintf(stderr, "file cant be opened\n");
}
int main()
{
const char* fname = "films.txt";
char cFilms[500][500];
std::vector<std::string> cppFilms;
readc(fname, cFilms);
readcpp(fname, cppFilms);
return 0;
}
And as the others mentioned before, do not use feof or for that matter, ifstream's eof member function either, for checking wheter you reached the end of file, as it may be unsafe.

Hm, I see a lot of code in answers.
The usage of algorithm will drastically reduce coding effort.
Additionally it is a "more modern" C++ approach.
The OP said, that he want to have words in some array. OK.
So we will use a std::vector<std::string> for storing those words. As you can see in cppreference, the std::vector has many different constructors. We will use number 4, the range constructor.
This will construct the vector with a range of similar data. The similar data in our case are words or std::string. And we would like to read the complete range of the file, beginning with the first word and ending with the last word in the file.
For iterating over ranges, we use iterators. And for iterating of data in files, we use the std::istream_iterator. We tell this function what we want to read as template parameter, in our case a std::string. Then we tell it, from which file to read.
Since we do not have files on SO, I use a std::istringstream. But that's the same reading from a std::ifstream. If you have na open file stream, then you can hand it over to the std::istream_iterator.
And the result of using this C++ algorithms is that we read the complete file into the vector by just defining the varaible with its constructer as a one-liner.
We do similar for the debug output.
#include <iostream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
#include <sstream>
std::istringstream filmFile{ R"(Film1 Film2
Film3 Film4 Film5
Film6
)" };
int main()
{
// Define the variable films and use its range constructor
std::vector<std::string> films{ std::istream_iterator<std::string>(filmFile), std::istream_iterator<std::string>() };
// For debug pruposes, show result on console
std::copy(films.begin(), films.end(), std::ostream_iterator<std::string>(std::cout, "\n"));
return 0;
}

Related

C++ Parsing a CSV file into vector of vectors: Loosing string 1st character

I am reading a CSV file into vector of string vectors. I have written code below.
#include<iostream>
#include<fstream>
#include<string>
#include <vector>
#include <fstream>
#include <cmath>
#include <sstream>
using namespace std;
int main()
{
ifstream mesh;
mesh.open("mesh_reference.csv");
vector<vector<string> > point_coordinates;
string line, word;
while (getline(mesh,line))
{
stringstream ss(line);
vector<string> row;
while (getline(ss, word, ','))
{
row.push_back(word);
}
point_coordinates.push_back(row);
}
for(int i=0; i<point_coordinates.size(); i++)
{
for(int j=0; j<3; j++)
cout<<point_coordinates[i][j]<<" ";
cout<<endl;
}
return 0;
}
When I print out the vector of vectors, I see that I am loosing the first character of Element at 0 position in the vector row. Basically, point_coordinates[0][0] is displaying 0.0001 while the string is supposed to be -0.0001. I am not able to understand the reason for the same. Kindly help.
A typical output line is
.0131 -0.019430324 0.051801
Whereas the CSV data is
0.0131,-0.019430324,0.051801
SAMPLE CSV DATA FROM FILE
NODES__X,NODES__Y,NODES__Z
0.0131,-0.019430324,0.051801
0.0131,-0.019430324,0.06699588
0.0131,-0.018630324,0.06699588
0.0131,-0.018630324,0.051801
0.0131,-0.017630324,0.050801
0.0131,-0.017630324,0.050001
0.0149,-0.017630324,0.050001
0.0149,-0.019430324,0.051801
Although the problem is already solved, I would like to show you a solution using some modern C++ algorithms and eliminating minor issues.
Do not use using namespace std;. You should not do this
Ne need for a separate file.open. The std::ifstream constructor will open the file for you. And the destructor will close it
Check if the file could be opened. The ifstreams ! operator is overloaded. So you can do a boolean check
Do not use int in for loops where you compare against .size(). Use ````size_t instead
Always initialize all variables, even if there is an assignement in the next line
For tokenizing you should use std::sregex_token_iterator. It has exactly been designed for this purpose
In modern C++ you are encouraged to use algorithms
Please see an improved version of your code below:
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <iterator>
#include <regex>
const std::regex comma(",");
int main()
{
// Open source file.
std::ifstream mesh("r:\\mesh_reference.csv");
// Here we will store the result
std::vector<std::vector<std::string>> point_coordinates;
// We want to read all lines of the file
std::string line{};
while (mesh && getline(mesh, line)) {
// Tokenize the line and store result in vector. Use range constructor of std::vector
std::vector<std::string> row{ std::sregex_token_iterator(line.begin(),line.end(),comma,-1), std::sregex_token_iterator() };
point_coordinates.push_back(row);
}
// Print result. Go through all lines and then copy line elements to std::cout
std::for_each(point_coordinates.begin(), point_coordinates.end(), [](std::vector<std::string> & vs) {
std::copy(vs.begin(), vs.end(), std::ostream_iterator<std::string>(std::cout, " ")); std::cout << "\n"; });
return 0;
}
Please consider, if you may want to use such an approach in the future

Read file into array and return it from a function C++

In Lua, I have such a function to read a file into an array:
function readFile(file)
local output = {}
local f = io.open(file)
for each in f:lines() do
output[#output+1] = each
end
f:close()
return output
end
Now in C++, I tried to write that like this:
string * readFile(file) {
string line;
static string output[] = {};
ifstream stream(file);
while(getline(stream, line)) {
output[sizeof(output)+1] = line;
}
stream.close();
return output;
}
I know you can't return arrays from functions, only pointers. So I did this:
string *lines = readFile("stuff.txt");
And it threw me the error cannot convert 'std::string {aka std::basic_string<char>} to' std::string* {aka std::basic_string<char>*}' in intialization string *lines = readFile("stuff.txt");
Can anyone tell me what is wrong here, and is there a better way to read files into arrays?
EDIT:
I'm going to be using the returned array to do value matching using a for loop. In Lua this would be written as:
for _, each in ipairs(output) do
if each == (some condition here) then
--Do Something
end
end
How can this be done in C++, using vectors (according to the answer by Jerry Coffin)?
EDIT 2:
I can't match the vectors correctly for some reason. I wrote the code in a separate test file.
int main() {
vector<string> stuff = read_pass();
cout << stuff.size() << endl;
cout << stuff[0] << endl;
if (stuff[0] == "admin") {
cout << "true";
}
else {
cout << "false";
}
return 0;
}
read_pass() looks like this:
vector<string> read_pass() {
ifstream stream("stuff.txt");
string line;
vector<string> lines;
while(getline(stream, line)) {
lines.push_back(line);
}
stream.close();
return lines;
}
And stuff.txt looks like this:
admin
why?
ksfndj
I just put it some random lines to test the code. Every time I compile and run main.cpp the output I get is
3
admin
false
So why isn't the code being matched properly?
EDIT 3:
So instead of forcing myself down the vectors method of doing things, I decided to try this instead:
#include <cstdlib>
#include <iostream>
#include <fstream>
#include <vector>
#include "basefunc.h"
using namespace std;
int main() {
string storedUsrnm;
string storedPw;
string pw = "admin";
string usrnm = "admin";
ifstream usernames("usrnm.accts");
ifstream passwords("usrpw.accts");
while(getline(usernames, storedUsrnm)) {
getline(passwords, storedPw);
print("StoredUsrnm " + storedUsrnm);
print("StoredPw: " + storedPw);
if (storedUsrnm == usrnm && storedPw == pw) {
print("True!");
return 0;
}
}
print("False!");
return 0;
}
Where print() is
void print(string str) {
cout << str << endl;
}
This still prints false, at the end, and it leads me to believe that for some reason, the "admin" read by the ifstream is different from the "admin" string. Any explanations for how this is so? Or does this code not work either?
Doesn't look to me like your current code should even compile. Anyway, I'd probably do something like this:
std::vector<std::string> read_file(std::istream &infile) {
std:string line;
std::vector<std::string> lines;
while (std::getline(infile, line))
lines.push_back(line);
return lines;
}
So the basic idea here is to read a line from the file, and if that succeeded, add that line (with push_back) to the vector of results. Repeat until reading a line from the file fails. Then return the vector of all the lines to the caller.
A few notes: especially at first, it's fairly safe to presume that any use of pointers is probably a mistake. That shouldn't be taken as an indication that pointers are terribly difficult to work with, or anything like that--just that they're almost never necessary for the kinds of things most relative beginners do in C++.
Likewise with arrays--at first, assume that what you might think of as an array in some other language translates to a std::vector in C++. C++ does also have arrays, but using them can wait a while (a long while, IMO--I've been writing C++ for decades now, and virtually never use raw pointers or arrays at all).
In the interest of simplicity, I've consolidated the data into the program, so it reads the data from the stringstream, like this:
#include <vector>
#include <string>
#include <fstream>
#include <iostream>
#include <sstream>
using namespace std;
vector<string> read_pass(istream &is) {
string line;
vector<string> lines;
while (getline(is, line)) {
lines.push_back(line);
}
return lines;
}
int main() {
istringstream input{ "admin\nwhy?\nksfndj" };
// To read from an external file, change the preceding line to:
// ifstream input{ "stuff.txt" };
vector<string> stuff = read_pass(input);
cout << stuff.size() << endl;
cout << stuff[0] << endl;
if (stuff[0] == "admin") {
cout << "true";
}
else {
cout << "false";
}
return 0;
}
At least for me, this produces:
3
admin
true
...indicating that it has worked as expected. I get the same with an external file. If you're not getting the same with an external file, my immediate guess would be that (at least the first line of) the file contains some data you're not expecting. If the problem continues, you might consider writing out the individual characters of the strings you read in numeric format, to give a more explicit idea of what you're really reading.
After a long time, I finally came up with the answer
#include <fstream>
#include <iostream>
#include <cstdlib>
#include <map>
using namespace std;
typedef map<int, string> strArr;
strArr readFile(string file) {
ifstream stream(file);
string line;
strArr output;
while(getline(stream, line)) {
output[output.size()+1] = line;
}
stream.close();
return output;
}
It doesn't read the file into an array, but it does return a map that does basically the same thing

How to read an array of complex numbers from a text file in C++

As a learner in c++, I decided to play with complex numbers, using the standard library. Now I need to read and write an array of complex from/to text files. This works simply for writing, without supplemental tricks :
void dump(const char *filename){
ofstream result;
result.open (filename);
for(int k=0;k<15;k++){
result<< outputs[k] <<endl;
}
result.close();
}
The data are parenthesized and written line by line looking like : (real,im)...
Now, I guess reading (and loading an array of complex) should be as trivial as reading. However, despite my research, I have not found the right way to do that.
My first attempt was naive :
void readfile(const char *filename){
string line;
ifstream myfile (filename);
if (myfile.is_open())
{
int k=0;
while ( getline (myfile,line) ){
k++;
cout << line << endl;
inputs[k]= (complex<float>) line; //naive !
}
myfile.close();
}
else cout << "Unable to open file";
}
Is there a way to do that simply (without a string parser ) ?
Assuming you have an operator<< for your_complex_type (as has been mentioned, std::complex provides one), you can use an istream_iterator:
#include <fstream>
#include <iterator>
#include <vector>
int main()
{
std::ifstream input( "numbers.txt" );
std::vector<your_complex_type> buffer{
std::istream_iterator<your_complex_type>(input),
std::istream_iterator<your_complex_type>() };
}
This will read all numbers in the file and store them in an std::vector<your_complex_type>.
Edit about your comment
If you know the number of elements you will read up-front, you can optimize this as follows:
#include <fstream>
#include <iterator>
#include <vector>
int main()
{
std::ifstream input( "numbers.txt" );
std::vector<your_complex_type> buffer;
buffer.reserve(expected_number_of_entries);
std::copy(std::istream_iterator<your_complex_type>(input),
std::istream_iterator<your_complex_type>(),
std::back_inserter(buffer));
}
std::vector::reserve will make the vector reserve enough memory to store the specified number of elements. This will remove unnecessary reallocations.
You can also use similar code to write your numbers to a file:
std::vector<your_complex_type> numbers; // assume this is filled
std::ofstream output{ "numbers.txt" };
std::copy(std::begin(numbers), std::end(numbers),
std::ostream_iterator<your_complex_type>(output, '\n') );
C++ version:
std::complex<int> c;
std::ifstream fin("filename");
fin>>c;
C version:
int a,b;
FILE *fin=fopen("filename","r");
fscanf(fin,"(%d,%d)\n",&a,&b);
C++ read multiple lines with multiple complex values on each line
#include <stdio.h>
#include <fstream>
#include <complex>
#include <iostream>
#include <sstream>
int main ()
{
std::complex<int> c;
std::ifstream fin("test.in");
std::string line;
std::vector<std::complex<int> > vec;
vec.reserve(10000000);
while(std::getline(fin,line))
{
std::stringstream stream(line);
while(stream>>c)
{
vec.push_back(c);
}
}
return 0;
}

Reading line from text file and putting the strings into a vector?

I am trying to read each line of a textfile which each line contains one word and put those words into a vector. How would i go about doing that?
This is my new code: I think there is still something wrong with it.
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
using namespace std;
int main()
{
std::string line;
vector<string> DataArray;
vector<string> QueryArray;
ifstream myfile("OHenry.txt");
ifstream qfile("queries.txt");
if(!myfile) //Always test the file open.
{
cout<<"Error opening output file"<<endl;
system("pause");
return -1;
}
while (std::getline(qfile, line))
{
QueryArray.push_back(line);
}
if(!qfile) //Always test the file open.
{
cout<<"Error opening output file"<<endl;
system("pause");
return -1;
}
while (std::getline(qfile, line))
{
QueryArray.push_back(line);
}
cout<<QueryArray[0]<<endl;
cout<<DataArray[0]<<endl;
}
Simplest form:
std::string line;
std::vector<std::string> myLines;
while (std::getline(myfile, line))
{
myLines.push_back(line);
}
No need for crazy c thingies :)
Edit:
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
int main()
{
std::string line;
std::vector<std::string> DataArray;
std::vector<std::string> QueryArray;
std::ifstream myfile("OHenry.txt");
std::ifstream qfile("queries.txt");
if(!myfile) //Always test the file open.
{
std::cout<<"Error opening output file"<< std::endl;
system("pause");
return -1;
}
while (std::getline(myfile, line))
{
DataArray.push_back(line);
}
if(!qfile) //Always test the file open.
{
std::cout<<"Error opening output file"<<std::endl;
system("pause");
return -1;
}
while (std::getline(qfile, line))
{
QueryArray.push_back(line);
}
std::cout<<QueryArray[20]<<std::endl;
std::cout<<DataArray[12]<<std::endl;
return 0;
}
Keyword using is illegal C++! Never use it. OK? Good. Now compare what I wrote with what you wrote and try to find out the differences. If you still have questions come back.
#FailedDev did, indeed, list the simplest form. As an alternative, here is how I often code that loop:
std::vector<std::string> myLines;
std::copy(std::istream_iterator<std::string>(myfile),
std::istream_iterator<std::string>(),
std::back_inserter(myLines));
The entire program might look like this:
// Avoid "using namespace std;" at all costs. Prefer typing out "std::"
// in front of each identifier, but "using std::NAME" isn't (very) dangerous.
#include <iostream>
using std::cout;
using std::cin;
#include <fstream>
using std::ifstream;
#include <string>
using std::string;
#include <vector>
using std::vector;
#include <iterator>
using std::istream_iterator;
#include <algorithm>
using std::copy;
int main()
{
// Store the words from the two files into these two vectors
vector<string> DataArray;
vector<string> QueryArray;
// Create two input streams, opening the named files in the process.
// You only need to check for failure if you want to distinguish
// between "no file" and "empty file". In this example, the two
// situations are equivalent.
ifstream myfile("OHenry.txt");
ifstream qfile("queries.txt");
// std::copy(InputIt first, InputIt last, OutputIt out) copies all
// of the data in the range [first, last) to the output iterator "out"
// istream_iterator() is an input iterator that reads items from the
// named file stream
// back_inserter() returns an interator that performs "push_back"
// on the named vector.
copy(istream_iterator<string>(myfile),
istream_iterator<string>(),
back_inserter(DataArray));
copy(istream_iterator<string>(qfile),
istream_iterator<string>(),
back_inserter(QueryArray));
try {
// use ".at()" and catch the resulting exception if there is any
// chance that the index is bogus. Since we are reading external files,
// there is every chance that the index is bogus.
cout<<QueryArray.at(20)<<"\n";
cout<<DataArray.at(12)<<"\n";
} catch(...) {
// deal with error here. Maybe:
// the input file doesn't exist
// the ifstream creation failed for some other reason
// the string reads didn't work
cout << "Data Unavailable\n";
}
}
Simplest version:
std::vector<std::string> lines;
for (std::string line; std::getline( ifs, line ); /**/ )
lines.push_back( line );
I'm omitting the includes and other gunk. My version is almost the same as FailedDev's but by using a 'for' loop I put the declaration of 'line' in the loop. This is not just a trick to reduce the line count. Doing this reduces the scope of line -- it disappears after the for loop. All variables should have the smallest scope possible, so therefore this is better. For loops are awesome.
A short version for C++11 and above. The vector is constructed directly from the file contents:
ifstream qfile("queries.txt");
vector<string> lines {
istream_iterator<string>(qfile),
istream_iterator<string>()
};
Note that this code will only work if the input file is in the format described by the OP, i.e. "each line contains one word". Or if you set special locale via qfile.imbue(), as mheyman kindly pointed out.

Most Compact Way to Count Number of Lines in a File in C++

What's the most compact way to compute the number of lines of a file?
I need this information to create/initialize a matrix data structure.
Later I have to go through the file again and store the information inside a matrix.
Update: Based on Dave Gamble's. But why this doesn't compile?
Note that the file could be very large. So I try to avoid using container
to save memory.
#include <iostream>
#include <vector>
#include <fstream>
#include <sstream>
using namespace std;
int main ( int arg_count, char *arg_vec[] ) {
if (arg_count !=2 ) {
cerr << "expected one argument" << endl;
return EXIT_FAILURE;
}
string line;
ifstream myfile (arg_vec[1]);
FILE *f=fopen(myfile,"rb");
int c=0,b;
while ((b=fgetc(f))!=EOF) c+=(b==10)?1:0;
fseek(f,0,SEEK_SET);
return 0;
}
I think this might do it...
std::ifstream file(f);
int n = std::count(std::istreambuf_iterator<char>(file), std::istreambuf_iterator<char>(), '\n') + 1;
If the reason you need to "go back again" is because you cannot continue without the size, try re-ordering your setup.
That is, read through the file, storing each line in a std::vector<string> or something. Then you have the size, along with the lines in the file:
#include <fstream>
#include <iostream>
#include <string>
#include <vector>
int main(void)
{
std::fstream file("main.cpp");
std::vector<std::string> fileData;
// read in each line
std::string dummy;
while (getline(file, dummy))
{
fileData.push_back(dummy);
}
// and size is available, along with the file
// being in memory (faster than hard drive)
size_t fileLines = fileData.size();
std::cout << "Number of lines: " << fileLines << std::endl;
}
Here is a solution without the container:
#include <fstream>
#include <iostream>
#include <string>
#include <vector>
int main(void)
{
std::fstream file("main.cpp");
size_t fileLines = 0;
// read in each line
std::string dummy;
while (getline(file, dummy))
{
++fileLines;
}
std::cout << "Number of lines: " << fileLines << std::endl;
}
Though I doubt that's the most efficient way. The benefit of this method was the ability to store the lines in memory as you went.
FILE *f=fopen(filename,"rb");
int c=0,b;while ((b=fgetc(f))!=EOF) c+=(b==10)?1:0;fseek(f,0,SEEK_SET);
Answer in c.
That kind of compact?
#include <stdlib.h>
int main(void) { system("wc -l plainfile.txt"); }
Count the number of instances of '\n'. This works for *nix (\n) and DOS/Windows (\r\n) line endings, but not for old-skool Mac (System 9 or maybe before that), which used just \r. I've never seen a case come up with just \r as line endings, so I wouldn't worry about it unless you know it's going to be an issue.
Edit: If your input is not ASCII, then you could run into encoding problems as well. What's your input look like?