How to save MultipleChoiceField to db - django

Question

I want to create a settings page where a user can select multiple values of skills they have. It will have a main category and then subcategories. I need to save those into my database, so I can query them and show their selected skillset again.
I know how to create the MultipleChoiceField but not how to save them to the database. How would I go on about that?
Forms.py
from django import forms
class skills(forms.Form):
jobs = [
('Håndværker', (
('Gulv', 'Gulv'),
('Væg', 'Væg'),
)
),
('Murer', (
('Mur', 'Mur'),
('blabla', 'blabla'),
)
),
]
job = forms.MultipleChoiceField(widget=forms.CheckboxSelectMultiple,
choices=jobs)
Views.py
from .forms import skills
def index(request):
if request.method == 'POST':
form = skills(request.POST)
if form.is_valid():
picked = form.cleaned_data.get('job')
# do something with your results
else:
form = skills
return render(request, 'settings/index.html', {"form":form})
It currently looks like this when the page loads which is good. Next step is just how I would save it to the database, so I can display this again with their previous chosen values.

Answer 1

Since you don't have any models setup yet, you can look into django-multiselectfield, which would store the selected choices "as a CharField of comma-separated values". Then you'd just need to pass those values from your form.
Alternatively you can look into PostgreSQL's Array field.

Answer 2

I would recommend you have a Jobs model and a Skills Model. Then have a skills field on the job model which will be a ManyToManyField to the Skills model. The form for this can then be autogenerated for you by Django as a ModelForm.
# Create your models here.
class Skill(models.Model):
name = models.CharField(max_length=20, null=False, blank=False)
def __str__(self):
return self.name
class Job(models.Model):
name = models.CharField(max_length=20, null=False, blank=False)
skills = models.ManyToManyField(Skill)
def __str__(self):
return self.name
class Person(models.Model):
name = models.CharField(max_length=20, null=False, blank=False)
skills = models.ManyToManyField(Skill)
def __str__(self):
return self.name
You can then add them to the db as
skill1 = Skill.objects.create(name="Skill One")
skill2 = Skill.objects.create(name="Skill Two")
skill3 = Skill.objects.create(name="Skill Three")
skill4 = Skill.objects.create(name="Skill Four")
job1 = Job.objects.create(name="Job One")
job1.skills.add(skill1)
job1.skills.add(skill2)
job2 = Job.objects.create(name="Job Two")
job2.skills.add(skill3)
job2.skills.add(skill4)
Have a form to display
class PersonForm(forms.ModelForm):
class Meta:
model = Person
fields = ["name", "skills"]
You can cutomize the form or the template to your linking

Answer 3

in models.py just create the field with CharField
from django.db import models
class UserProfileInfo(models.Model):
Gender = models.CharField(max_length=10,default='')
in forms.py just create CHOICE like below
class UserProfileInfoForm(forms.ModelForm):
YESNO_CHOICES = (('male', 'male'), ('female', 'female'))
Gender = forms.ChoiceField(choices=YESNO_CHOICES)
class Meta():
model = UserProfileInfo
fields = ('Gender',)
in views.py import this form and display it.
or you can definitely go with
https://pypi.org/project/django-multiselectfield/