Creating Columns From Stacked Data - sas

Question

Piggy backing on a similar question I asked
(Summing a Column By Group In a Dataset With Macros)...
I have the following dataset:
Month Cost_Center Account Actual Annual_Budget
May 53410 Postage 23 134
May 53420 Postage 7 238
May 53430 Postage 98 743
May 53440 Postage 0 417
May 53710 Postage 102 562
May 53410 Phone 63 137
May 53420 Phone 103 909
May 53430 Phone 90 763
June 53410 Postage 13 134
June 53420 Postage 0 238
June 53430 Postage 48 743
June 53440 Postage 0 417
June 53710 Postage 92 562
June 53410 Phone 73 137
June 53420 Phone 103 909
June 53430 Phone 90 763
I would like to "splice" it so each month has its own respective column for Actual while summing the numeric values by Account.
So for example, I want the output to look like the following:
Account May_Actual_Sum June_Actual_Sum Annual_Budget
Postage 14562 37960 255251
Phone [phone]
The code below provided by a fellow user works great when not needing to further dis-aggregated by month; however, I'm not sure if it's possible to do so (I tired adding a 'by month clause' - didn't work).
proc means data=Test N SUM NWAY STACKODS;
class Account_Description;
var Actual annual_budget;
by month;
ods output summary = summary_stats1;
output out = summary_stats2 N = SUM= / AUTONAME;
data want;
set summary_stats2;
run;

Answer 1

Use PROC MEANS to get summaries - same as last time. Please read up the documentation on PROC MEANS to understand how the CLASS statements works and how you can control the different levels of output.
Use PROC TRANSPOSE to flip the data wide. Since the budget amount is consistent across rows you'll be fine.
I'm guessing your next set of question will then be how to sort the columns correctly because your months won't sort and how to reference them dynamically to calculate the month to date changes. Which are some of the reasons why this data structure is not recommended.
data have;
input Month $ Cost_Center $ Account $ Actual Annual_Budget;
cards;
May 53410 Postage 23 134
May 53420 Postage 7 238
May 53430 Postage 98 743
May 53440 Postage 0 417
May 53710 Postage 102 562
May 53410 Phone 63 137
May 53420 Phone 103 909
May 53430 Phone 90 763
June 53410 Postage 13 134
June 53420 Postage 0 238
June 53430 Postage 48 743
June 53440 Postage 0 417
June 53710 Postage 92 562
June 53410 Phone 73 137
June 53420 Phone 103 909
June 53430 Phone 90 763
;
;
;;
run;
*summarize;
proc means data=have noprint nway;
class account month;
var actual annual_budget;
output out=temp sum=actual_total budget_total;
run;
*transpose;
proc transpose data=temp out=want prefix=Month_;
by account budget_total;
var actual_total;
id month;
run;
Output:

Answer 2

I cannot think of a way to generate this report using just one PROC. You will need to do some post processing of PROC MEANS or PROC SUMMARY results to get to this:
proc means data=have SUM ;
class Account month;
var Actual annual_budget;
output out = summary_stats SUM=;
run;
/* Look at summary_stats to understand it's structure here */
/* Otherwise you will not understand the following code */
proc sort data = summary_stats;
where _type_ in (2,3);
by account;
run;
data want;
set summary_stats;
by account ;
retain May_Actual_Sum June_Actual_Sum Annual_Budget_sum;
if first.account then Annual_Budget_sum = Annual_Budget;
else do;
select(month);
when ('May') May_Actual_Sum = actual;
when ('June') June_Actual_Sum = actual;
/* List other months also here. Can use some macros here to make the code compact and expandable for future enhancements */
end;
end;
if last.account then output;
keep account May_Actual_Sum June_Actual_Sum Annual_Budget_sum;
run;