I have made an small weather web app in django & it is working properly but
when a wrong city name is entered it start showing KeyError page.
from django.shortcuts import render, redirect
from django.contrib import messages
import requests
#search page
def search(request):
return render(request, 'index.html')
#forecast result page
def forecast(request):
c = request.POST['city']
url = 'http://api.openweathermap.org/data/2.5/weather?q={}&appid=7fee53226a6fbc936e0308a3f4941aaa&units=metric'.format(c)
r = requests.get(url)
data = r.json()
weather = {
'description': data['weather'][0]['description'],
'icon': data['weather'][0]['icon'],
'city': c.title(),
'temperature': data['main']['temp']
}
print(r)
return render(request, 'weather.html', {'weather': weather})
On entering wrong city name it is giving KeyError,So I want that instead of giving KeyError django will redirect it to my homepage i.e index.html with an error message below it.
The API will tell you if the city name is not valid.
r = requests.get(url)
if r.status_code == 404:
messages.add_message('City not found')
return redirect('home')
data = r.json()
...
First of all, please do not construct the querysetring yourself: querystrings can not include a lot of characters. You can use Django's QueryDict for that, like:
from django.http import QueryDict
qd = QueryDict(mutable=True)
qd.update(q=c, appid='7fee53226a6fbc936e0308a3f4941aaa', units='metric')
url = 'http://api.openweathermap.org/data/2.5/weather?{}'.format(qd.urlencode())
For cities like 'New York', it will encode this as:
>>> qd.urlencode()
'q=New+York&appid=7fee53226a6fbc936e0308a3f4941aaa&units=metric'
so it replaces the space with a +.
Furthermore you can use try-except here to redirect to a different page, like:
from django.http import QueryDict
from django.shortcuts import redirect
def forecast(request):
try:
city = request.POST['city']
except:
return redirect('name-of-some-view')
qd = QueryDict(mutable=True)
qd.update(q=city, appid='7fee53226a6fbc936e0308a3f4941aaa', units='metric')
url = 'http://api.openweathermap.org/data/2.5/weather?{}'.format(qd.urlencode())
try:
data = r.json()
weather = {
'description': data['weather'][0]['description'],
'icon': data['weather'][0]['icon'],
'city': c.title(),
'temperature': data['main']['temp']
}
except KeyError:
return redirect('name-of-some-view')
return render(request, 'weather.html', {'weather': weather})
You can use the Django Messages Framework [Django-doc] to show messages to a user.
Related
I can't figure out why my redirection after paying doesn't work.
I'm trying to display the thank_you template once the user has paid via Paypal. My code all works other than the final render of the thank_you template (I receive the email and see the 'Made it' print statement).
Urls:
from django.urls import path
from . import views
app_name = 'checkout'
urlpatterns = [
path('', views.checkout, name='checkout'),
path('thank_you', views.thank_you, name='thank_you'),
path('order_success', views.order_success, name='order_success'),
]
Views.py:
import json
from django.shortcuts import render, redirect, reverse, HttpResponseRedirect
from django.http import JsonResponse
from django.contrib import messages
from django.urls import reverse
from profiles.models import UserProfile
from products.models import Product
from django.views.decorators.http import require_POST
from .models import Order, OrderDetail
from django.core.mail import send_mail
from the_rescuers.settings import DEFAULT_FROM_EMAIL
from templated_email import send_templated_mail
from .forms import OrderForm
def checkout(request):
bag = request.session.get('bag', {})
if not bag:
messages.error(request, "There's nothing in your bag at the moment")
return redirect(reverse('products:products_list'))
order_form = OrderForm()
bag_products = []
for item_id, quantity in bag.items():
product = Product.objects.get(pk=item_id)
name = product.name
id = product.id
bag_products.append({'name': name, 'id': id, 'quantity': quantity})
bag_products = json.dumps(bag_products)
# Attempt to prefill the form with any info the user maintains in
# their profile
if request.user.is_authenticated:
profile = UserProfile.objects.get(user=request.user)
order_form = OrderForm(initial={
'first_name': profile.default_first_name,
'last_name': profile.default_last_name,
'email': profile.default_email,
'phone_number': profile.default_phone_number,
'country': profile.default_country,
'postcode': profile.default_postcode,
'city': profile.default_city,
'street_address_1': profile.default_street_address_1,
'street_address_2': profile.default_street_address_2,
'county': profile.default_county,
})
template = 'checkout/checkout.html'
success_url = '/checkout/order_success'
thank_you = '/checkout/thank_you'
context = {
'order_form': order_form,
'success_url': success_url,
'bag_products': bag_products,
'thank_you': thank_you,
}
return render(request, template, context)
def order_success(request):
"""
View that creates a new object with the JSON data, then redirects to the
thankyou page.
"""
# Take the request, decode it, split it into bag_contents and order_data
# and use this data to create a new order
request2 = request.body
my_json = request2.decode('utf8').replace("'", '"')
json_data = json.loads(my_json)
bag_contents = json_data.get('bagContents')
bag_contents = json.loads(bag_contents)
order_data = json_data.get('jsonData')
order_data = json.loads(order_data)
# Manually fill the user_id field with the user's id
order_data["user_id"] = request.user.id
# Remove the csrf token from the data
order_data.pop("csrfmiddlewaretoken", None)
# Create a new instance of the Order model using the order_data received
order = Order.objects.create(**order_data)
order.save()
# Loop through the bag_contents and save the details in OrderDetail model
for item in bag_contents:
product = Product.objects.get(pk=item['id'])
order_detail = OrderDetail(order=order, product=product,
quantity=item['quantity'])
order_detail.save()
order.update_total()
# Create a value to check in the thank_you view
request.session['redirected_from_order_success'] = True
print("Original: ", request.session)
# Send email to the provided email address
send_templated_mail(
template_name='order_confirmation',
from_email=DEFAULT_FROM_EMAIL,
recipient_list=[order.email],
context={'name': order.first_name,
'order_number': order.order_number,
'order_total': order.order_total,
},
)
return HttpResponseRedirect(reverse('checkout:thank_you'))
def thank_you(request):
"""
View that displays the thankyou page after processing an order.
"""
# Redirect to the custom 404 page if trying to access the page without
# making an order
if request.session.get('redirected_from_order_success'):
# Clear the bag and redirection token now that the order has been
# created
request.session.pop('bag', None)
request.session['redirected_from_order_success'] = False
print("Made it: ", request.session)
return render(request, 'checkout/thank_you.html')
else:
print("Diverted it: ", request.session)
return render(request, "404.html")
Relevant Checkout.html Javascript:
function completeOrder(){
let url = '{{ success_url }}'
const request= fetch(url, {
method: 'POST',
headers:{
'Content-type':'application/json',
'X-CSRFToken': csrftoken,
},
body:JSON.stringify({"bagContents": bagContents, "jsonData": jsonData} )
})
}
onApprove: (data, actions) => {
return actions.order.capture().then(function (orderData) {
const transaction = orderData.purchase_units[0].payments.captures[0];
return completeOrder()})
}
What's confusing is that the GET request for the thank_you template is made and gives a 200, it just doesn't move from the checkout page?
[24/Jan/2023 08:43:02] "POST /checkout/order_success HTTP/1.1" 302 0
Made it: <django.contrib.sessions.backends.db.SessionStore object at 0x7f75867dcb50>
[24/Jan/2023 08:43:03] "GET /checkout/thank_you HTTP/1.1" 200 6287
Any help would be much appreciated!
I am trying to create a registration form and store values in database, And i am able to store data in database successfully but i am getting error like this.
please someone tell me what i have done wrong in my code.
Error :
ValueError at /signup
The view home.views.signup didn't return an HttpResponse object. It returned None instead.
Request Method: POST
Request URL: http://127.0.0.1:8000/signup
Django Version: 4.0
Exception Type: ValueError
Exception Value: The view home.views.signup didn't return an HttpResponse object. It returned None instead.
Code:
from django.http.response import HttpResponse, HttpResponseRedirect
from django.shortcuts import redirect, render
from home.models import Public
from datetime import datetime
# Create your views here.
def signup(request):
if request.method == "POST":
name = request.POST.get("name")
email = request.POST.get("email")
pass1 = request.POST.get("password1")
pass2 = request.POST.get("password2")
user = Public(name= name, email= email, password= pass1, date= datetime.today())
if pass1 == pass2:
user.save()
else:
dictionary = {"error": "Password and Confirm password is not match"}
return render(request, 'signup.html', dictionary)
else:
return render(request, 'signup.html')
How to setup Django to authenticate with Instagram by default?
Tried django-socialauth, but no results.
Which way is the best?
Check this out:
I've found solution from sample_app.py in python-instagram :) And sync with django auth
from django.conf import settings
from django.http import HttpResponseRedirect, HttpResponse
from django.contrib.auth import login, logout
from django.contrib.auth.decorators import login_required
from django.contrib.auth.models import User
from django.shortcuts import render
from instagram import client
from app.models import UserProfile
unauthenticated_api = client.InstagramAPI(**settings.INSTAGRAM_CONFIG)
#login_required
def index(request):
return render(request, 'app/index.html', {})
def on_login(request):
try:
url = unauthenticated_api.get_authorize_url(scope=["likes","comments"])
return render(request, 'app/login.html', {'url': url})
except Exception as e:
print(e)
def on_callback(request):
code = request.GET.get("code")
if not code:
return "Missing code"
try:
access_token, user_info = unauthenticated_api.exchange_code_for_access_token(code)
if not access_token:
return "Could not get access token"
api = client.InstagramAPI(access_token=access_token, client_secret=settings.INSTAGRAM_CONFIG['client_secret'])
request.session['access_token'] = access_token
print "%s" % access_token
except Exception as e:
print(e)
print "%s" % user_info
print "%s" % user_info['username']
user, created = User.objects.get_or_create(username=user_info['username'])
user.backend = 'django.contrib.auth.backends.ModelBackend'
if user:
if user.is_active:
login(request, user)
return HttpResponseRedirect('/app/')
else:
return HttpResponse("Your account is disabled.")
else:
return HttpResponse("No login.")
#login_required
def on_logout(request):
logout(request)
return HttpResponseRedirect('/app/')
It's simple first redirect your users to this url
BASE_URL = "https://api.instagram.com/oauth/authorize/?"
REDIRECT_URI = "http://127.0.0.1:5000/grant-access"
url = BASE_URL + "client_id={}&redirect_uri={}&response_type=code".format(CLIENT_ID, REDIRECT_URI)
return HttpResponseRedirect(url)
Then
REQUEST_ACCESS = "https://api.instagram.com/oauth/access_token/?"
def grant_access(request):
code = request.GET.get('code')
payload = {'client_id': CLIENT_ID, 'client_secret':CLIENT_SECRET, 'grant_type':'authorization_code','redirect_uri': REDIRECT_URI, 'code': code}
resp = requests.post(REQUEST_ACCESS, data= payload)
response = json.loads(resp.text)
Now you will have the access-token save that one into db for later use and log in
I have a page which shows the user and their about. And in that, there's a link to update their about. But when I open that link it shows me with this error:
DoesNotExist at /profile/user/update_about/
User matching query does not exist.
And the traceback hightlights this line, which from the profile method in the views:
13. user = User.objects.get(username=unquote(user_name))
However this error does not occur when I load the profile method. It occurs only on the update_profile method in the views.
views.py
from django.shortcuts import render
from django.http import HttpResponseRedirect
from urllib import unquote
from django.contrib.auth.models import User
from models import About
from forms import AboutForm
# Create your views here.
def profile(request, user_name):
user = User.objects.get(username=unquote(user_name))
about = About.objects.get_or_create(user=user)
about = about[0]
return render(request, 'user_profile.html', {
'user':user,
'about_user':about
})
def update_about(request, user_name):
user = User.objects.get(username=unquote(user_name))
if request.method == 'POST':
form = AboutForm(request.POST)
if form.is_valid():
form.save()
return HttpResponseRedirect('/')
else:
about = About.objects.get(user=user)
form = AboutForm(initial={'dob':about.dob})
return render(request, 'update_about.html',{
'form':form
})
urls.py
urlpatterns = patterns('',
# Examples:
url(r'(?P<user_name>[\w#%.]+)/$', 'user_related.views.profile', name='profile'),
url(r'(?P<user_name>[\w#%.]+)/update_about/$', 'user_related.views.update_about', name='update_about'),
What is causing this? Your help will be very much appreciated. Thank you.
You forgot to add the caret sign (^) at the first position of regex. So the first regex matched "update_about/" part of the url.
Fixed code:
url(r'^(?P<user_name>[\w#%.]+)/$', 'user_related.views.profile', name='profile'),
url(r'^(?P<user_name>[\w#%.]+)/update_about/$', 'user_related.views.update_about', name='update_about'),
I know this is an easy question, I am just not getting something...so thank you for your patience and advice.
I have a view that asks a user to register to use our app. The data he/she submits is stored in a database and he is sent off to another page to set up the application:
#views.py
def regPage(request, id=None):
form = RegForm(request.POST or None,
instance=id and UserRegistration.objects.get(id=id))
# Save new/edited pick
if request.method == 'POST' and form.is_valid():
form.save()
return HttpResponseRedirect('/dev/leaguepage/')
user_info = UserRegistration.objects.all()
context = {
'form':form,
'user_info' :user_info,
}
return render(request, 'regpage.html', context)
Rather than sending ALL users to the same page '/dev/leaguepage/', I need to send each user to his own page based on the PK in the database like: '/dev/PrimaryKey/' I am not sure how to make this happen either on the views file or in the URLs.py file:
#urls.py
from django.conf.urls.defaults import patterns, include, url
from acme.dc_django import views
urlpatterns = patterns('',
url(r'^leaguepage/$','acme.dc_django.views.leaguePage'),
url(r'^$', 'acme.dc_django.views.regPage'),
)
Thank you for your help!
dp
Updated code:
#url
url(r'^user/(?P<id>\d+)/$','acme.dc_django.views.leaguePage', name="league_page"),
#view
def regPage(request, id):
form = RegForm(request.POST)
# Save new/edited pick
if request.method == 'POST' and form.is_valid():
form.save()
return HttpResponseRedirect(reverse('league_page', kwargs={'id' :id}))
#return HttpResponseRedirect('/dev/leaguepage/')
user_info = UserRegistration.objects.all()
context = {
'form':form,
'user_info' :user_info,
}
return render(request, 'regpage.html', context)
You can do a reverse lookup on your leaguePage to do your redirect, passing in the values you need to resolve the pattern. You'll need to add a name to the URL pattern you want to reverse, but basically the syntax is:
return HttpResponseRedirect(reverse('my_detail', args=(), kwargs={'id' : id}))
Example URL pattern and view:
urlpatterns = patterns('my_app.views',
url(r'^my-pattern/(?P<id>\d+)/$', 'my_action', name='my_detail'),
)
def my_action(request, id):
#do something
Hope that helps you out.