How to get object at CreatView - django

Question

There is a form that is rendered by url
url(r'kredit/(?P<credit_slug>[-\.\w\d]+)/$', CreditDetail.as_view(), name='credit_detail'),
urls
url(r'kredit/(?P<credit_slug>[-\.\w\d]+)/$', CreditDetail.as_view(), name='credit_detail'),
url(r'kredit_request/$', CreditOnlineRequestView.as_view(), name='credit_request'),
The form is processed in the CreditOnlineRequestView(CreateView) view.
It is necessary to pull out the credit_slug from CreditDetail view in it (here the form was drawn)
​
views
class CreditDetail(FormView):
form_class = CreditPaymentForm
template_name = 'credits/credit_detail.html'
​
def get_initial(self):
initial = super(CreditDetail, self).get_initial()
initial['request'] = self.request
return initial
​
def get(self, *args, **kwargs):
request_form = CreditOnlineRequestForm(self.request.GET or None, prefix="request")
​
​
class CreditOnlineRequestView(CreateView):
form_class = CreditOnlineRequestForm
model = CreditOnlineRequest
template_name = 'credits/credit_listing.html'
prefix = 'request'
​
def form_valid(self, form, **kwargs):
credit_request = form.save(commit=False)
credit_request.credit = credit #???
return super(CreditOnlineRequestView, self).form_valid(form)
​
def form_invalid(self, form):
errors = dict([(k, v[0]) for k, v in form.errors.items()])
return errors
forms
class CreditOnlineRequestForm(forms.ModelForm):
class Meta:
model = CreditOnlineRequest
exclude = ['credit'] #this field must be define
​
def __init__(self, *args, **kwargs):
super(CreditOnlineRequestForm, self).__init__(*args, **kwargs)
#???
What are the options? I think, either through the cache, or through pulling out the previous page to do, but this is somehow not very humane, as for me. The best option, as for me, is to transfer the credit instance to a hidden form field in the CreditDetail view, but I don’t know how to do it yet.

Answer 1

The problem is that internally the form_valid function is doing the following:
def form_valid(self, form):
"""If the form is valid, save the associated model."""
self.object = form.save()
return super().form_valid(form)
So it does not matter what you're doing in your override that the super will try to save the form directly. You can solve your problem by doing:
def form_valid(self, form, **kwargs):
credit_request = form.save(commit=False)
credit_request.credit = credit
credit_request.save()
return HttpResponseRedirect(self.get_success_url())

Answer 2

urls
url(r'kredit_request/(?P<credit_slug>[-\.\w\d]+)/$', CreditOnlineRequestView.as_view(), name='credit_request'),
html
<form action="{% url 'credit_request' credit.slug %}" method="post">
view
class CreditOnlineRequestView(CreateView):
form_class = CreditOnlineRequestForm
model = CreditOnlineRequest
slug_url_kwarg = 'credit_slug'
prefix = 'request'
def post(self, request, *args, **kwargs):
form = self.get_form()
credit = Credit.objects.get(slug=kwargs.get('credit_slug'))
cache.set('credit_for_request', credit)
if form.is_valid():
return self.form_valid(form)
else:
return self.form_invalid(form)
def form_valid(self, form):
credit_request = form.save(commit=False)
credit = cache.get('credit_for_request')
cache.clear()
credit_request.credit = credit
credit_request.save()
return HttpResponseRedirect(reverse('credit_detail', kwargs={'credit_slug': credit.slug}))