How to access to the children views in SwiftUI? - swiftui

I'm working on the SwiftUI, and feeling it's very similar with React. Just now I'm customizing a Button of SwiftUI and have a problem which can't access to the children views of Button dynamically
Following codes is what I'm going to do:
struct FullButton : View {
var action: () -> Void
var body: some View {
Button(action: action) {
// render children views here even what is that
children
}
}
}
and usage:
VStack {
FullButton(action: {
print('touched')
}) {
Text("Button")
}
}
Please, do I have a wrong idea?
Update
Depends on #graycampbell 's answer I tried as following
struct FullButton<Label> where Label : View {
var action: () -> Void
var label: () -> Label
init(action: #escaping () -> Void, #ViewBuilder label: #escaping () -> Label) {
self.action = action
self.label = label
}
var body: some View {
Button(action: action, label: label)
}
}
So the FullButton looks well as itself. But I have another compile error in usage at this time.
VStack {
FullButton(action: { print("touched") }) {
Text("Fullbutton")
}
}
The error is Referencing initializer 'init(alignment:spacing:content:)' on 'VStack' requires that 'FullButton<Text>' conform to 'View'.
It means FullButton hasn't return the body now?
I'm not sure why it is because the FullButton still extends View class.
Please let me know what's the correct body definition of that type of class.

This is what you're looking for, if I'm understanding your question correctly:
struct FullButton<Label>: View where Label: View {
var action: () -> Void
var label: () -> Label
var body: some View {
Button(action: self.action, label: self.label)
}
}
This would allow you to pass whatever content you want to be displayed on your button, meaning that the code you have here would now work:
FullButton(action: {
print("touched")
}) {
Text("Button")
}
Update
After looking over your question several times, I've realized that your confusion is stemming from a misunderstanding of what is happening when you create a normal Button.
In the code below, I'm creating a Button. The button takes two arguments - action and label.
Button(action: {}, label: {
Text("Button")
})
If we look at the documentation for Button, we see that it is declared like this:
struct Button<Label> where Label : View
If we then look at the initializers, we see this:
init(action: #escaping () -> Void, #ViewBuilder label: () -> Label)
Both action and label expect closures. action expects a closure with a return type of Void, and label expects a #ViewBuilder closure with a return type of Label. As defined in the declaration for Button, Label is a generic representing a View, so really, label is expecting a closure that returns a View.
This is not unique to Button. Take HStack, for example:
struct HStack<Content> where Content : View
init(alignment: VerticalAlignment = .center, spacing: Length? = nil, #ViewBuilder content: () -> Content)
Content serves the same purpose here that Label does in Button.
Something else to note - when we create a button like this...
Button(action: {}) {
Text("Button")
}
...we're actually doing the same thing as this:
Button(action: {}, label: {
Text("Button")
})
In Swift, when the last argument in a method call is a closure, we can omit the argument label and append the closure to the outside of the closing parenthesis.
In SwiftUI, you cannot implicitly pass content to any View. The View must explicitly accept a #ViewBuilder closure in its initializer.
And so, you cannot pass a #ViewBuilder closure to FullButton unless FullButton accepts a #ViewBuilder closure as an argument in its initializer, as shown at the beginning of my answer.

There is a ViewInspector library that uses Swift's reflection for extracting SwiftUI views from any hierarchy.
let view = FullButton()
let button = try view.inspect().button()
let children = button.anyView().view(OtherView.Type)
// By the way, you can even tap the button programmatically:
try button.tap()

Related

SwiftUI Providing destination for NavigationLink in the view init resulting in "Type 'any View' cannot conform to 'View'" [duplicate]

This question already has an answer here:
Swiftui How to pass a view that takes a parameter to another view that will set the parameter when calling the view
(1 answer)
Closed last month.
I am trying to make a NavigationLink and provide the destination in its init but I am receiving an error:
Type 'any View' cannot conform to 'View'
struct MenuButton: View {
let iconName: String
let destination: () -> any View
var body: some View {
NavigationLink { //Type 'any View' cannot conform to 'View'
destination()
} label: {
Image(systemName: iconName)
.foregroundColor(.pink)
.padding()
}
}
}
struct MenuBar: View {
var body: some View {
HStack {
MenuButton(iconName: "gearshape") {
//providing destination here
let user = User(firstName: "Mock", lastName: "Data", dateStarted: 142356345)
return HomeView(viewModel: HomeViewModel(user: user))
}
}
}
}
If I switch any View to some View in the destination declaration, I receive an error:
Property declares an opaque return type, but has no initializer expression from which to infer an underlying type
You just need to make MenuButton generic over some type (say V) that conforms to View:
struct MenuButton<V: View>: View {
let iconName: String
let destination: () -> V
var body: some View {
NavigationLink {
destination()
} label: {
Image(systemName: iconName)
.foregroundColor(.pink)
.padding()
}
}
}
Another option I found is wrapping destination() in AnyView:
struct MenuButton: View {
let iconName: String
let destination: () -> any View
var body: some View {
NavigationLink {
AnyView(destination())
} label: {
Image(systemName: iconName)
.foregroundColor(.pink)
.padding()
}
}
}

onTapGesture is not working in TabView, how to make it work?

I used the .onTapGesture in TabView but it is not working. It also affecting the tab bar functionality.
TabView{
}
.onTapGesture {
<#code#>
}
Instead of using onTapGesture on tabView we can write an extension to Binding and it will detect the new tab selection value even if we tap the tab bar within the same tab it will detect the changes. Here I am provided the binding extension.
extension Binding {
func onUpdate(_ closure: #escaping () -> Void) -> Binding<Value> {
Binding(get: {
wrappedValue
}, set: { newValue in
wrappedValue = newValue
closure()
})
}}
I used this in my tabView. I attached my code below.
TabView(selection: $tabSelection.onUpdate {
setNewValue(value: tabSelection)
}) {
ContentView()
.tabItem {
Label {
Text("Home")
} icon: {
Image("HomePage_icon")
.renderingMode(.template)
}
}
.tag(TabViews.homepage)
}
SetNewValue function, this function acts like onTapGesture
func setNewValue(value: TabViews){
self.tabSelection = value
*/ inside this function we can write the code, we like to write it in onTapGesture */
}

Why the List does not appear?

Why the presetsList does not appear? No errors were thrown though.
import SwiftUI
struct AddMessagePreset: View {
let presetsList = [
Preset(name: "preset text 1"),
Preset(name: "preset text 2"),
Preset(name: "preset text 3")
]
var body: some View {
List(presetsList) { singlePresetModel in
SinglePresetChild (presetModel: singlePresetModel)
}
}
}
import SwiftUI
struct Preset: Identifiable {
let id = UUID()
let name: String
}
struct SinglePresetChild: View {
var presetModel: Preset
var body: some View {
Text("Preset Name \(presetModel.name)")
}
}
UPDATE: To show a List inside another ScrollView (or List), you have to set a height on the inner list view:
struct Preview: View {
var body: some View {
ScrollView {
AddMessagePreset().frame(height: 200)
// more views ...
}
}
}
But let me advise against doing so. Having nested scroll areas can be very confusing for the user.
As discussed in the comments, your component code is fine. However, the way you integrate it into your app causes a problem. Apparently, nesting a List inside a ScrollView does not work properly (also see this thread).
List is already scrollable vertically, so you won't need the additional ScrollView:
struct Preview: View {
var body: some View {
VStack {
AddMessagePreset()
}
}
}
P.S.: If you only want to show AddMessagePreset and won't add another sibling view, you can remove the wrapping VStack; or even show AddMessagePreset as the main view, without any wrapper.

How to execute non-view code inside a SwiftUI view

I have been struggling with this over and over again, so I think I'm missing something. I need to do math, make a setting, assign a value or any of a host of simple operations in reaction to some user action, such as the example shown here, and SwiftUI is wanting a View where I don't need a view. There's got to be a way around the ViewBuilder's rules. I kind of worked around this by creating an unnecessary view and executing the code I need inside the View's init(), but that seems terribly awkward.
import SwiftUI
struct ContentView: View
{
#State var showStuff = false
var body: some View
{
VStack
{
Toggle(isOn: $showStuff)
{
Text("Label")
}
if showStuff
{
UserDefaults.standard.set(true, forKey: "Something")
}
}
}
}
Way 1 (best):
struct ExecuteCode : View {
init( _ codeToExec: () -> () ) {
codeToExec()
}
var body: some View {
return EmptyView()
}
}
usage:
HStack {
ExecuteCode {
print("SomeView1 was re-drawn!")
}
SomeView1()
}
Way 2:
( my first way is better - you're able to write only simple code here )
Code with let _ = works inside of View!
HStack {
let _ = print("SomeView1 was re-drawn!")
SomeView1()
}
Way 3:
( my first way is better - too difficult code structure; But code doings the same )
HStack {
// here is the magic
{ () -> SomeView1() in
// here is code to execute
print("SomeView1 was re-drawn!")
// here is the magic
return SomeView1()
}
}
Views are actually so-called Function Builders, and the contents of the view body are used as arguments to to the buildBlock function, as mentioned by #Asperi.
An alternative solution if you must run code inside this context is using a closure that returns the desired view:
VStack {
// ... some views ...
{ () -> Text in
// ... any code ...
return Text("some view") }()
// ... some views ...
}
In SwiftUI 2.0, there's a new ViewModifier onChange(of:perform:), that allows you to react to changes in values.
But you can create something similar to that with a neat trick (I forgot where I saw it, so unfortunately I can't leave proper attribution), by extending a Binding with onChange method:
extension Binding {
func onChange(perform action: #escaping (Value, Value) -> Void) -> Self {
.init(
get: { self.wrappedValue },
set: { newValue in
let oldValue = self.wrappedValue
DispatchQueue.main.async { action(newValue, oldValue) }
self.wrappedValue = newValue
})
}
}
You can use it like so:
Toggle(isOn: $showStuff.onChange(perform: { (new, old) in
if new {
UserDefaults.standard.set(true, forKey: "Something")
}
}))
You cannot do what you try to do, because actually every view block inside body is a ViewBuidler.buildBlock function arguments. Ie. you are in function arguments space. I hope you would not expect that expression like
foo(Toggle(), if showStuff { ... } )
would work (assuming foo is func foo(args: View...). But this is what you try to do in body.
So expressions in SwiftUI have to be out of ViewBuilder block (with some exceptions which ViewBuilder itself supports for views).
Here is a solution for your case:
SwiftUI 2.0
struct ContentView: View {
#AppStorage("Something") var showStuff = false
var body: some View {
VStack {
Toggle(isOn: $showStuff) {
Text("Label")
}
}
}
}
SwiftUI 1.0
Find in already solved SwiftUI toggle switches
Note: View.body (excluding some action modifiers) is equivalent of UIView.draw(_ rect:)... you don't store UserDefaults in draw(_ rect:), do you?

How to print() to Xcode console in SwiftUI?

So I tried to put a print statement while debugging in a SwiftUI View.
print("landmark: \(landmark)")
In the following body.
var body: some View {
NavigationView {
List {
Toggle(isOn: $userData.showFavoritesOnly) {
Text("Favorite only")
}
ForEach(landmarkData) { landmark in
print("landmark: \(landmark)")
if !self.userData.showFavoritesOnly || landmark.isFavorite {
NavigationButton(destination: LandmarkDetail(landmark: landmark)) {
LandmarkRow(landmark: landmark)
}
}
}
}
.navigationBarTitle(Text("Landmarks"))
}
}
Compiler errors out:
So, what is the proper way to print to console in SwiftUI?
EDIT:
I made Landmark conform to CustomStringConvertible:
struct Landmark: Hashable, Codable, Identifiable, CustomStringConvertible {
var description: String { name+"\(id)" }
var id: Int
var name: String
.....
I still get the "String is not convertible to any" error. Should it work now?
You can easily add a print statement anywhere in a function builder by simply storing its return value in a wildcard, effectively ignoring it:
let _ = print("hi!")
No setup or other verbosity needed!
Why does this work while a regular print() doesn't?
The way SwiftUI's #ViewBuilder (and result builders in general) is that they consume any values in a closure that aren't used otherwise (e.g. if you just have 42 on its own line). The print function returns Void (nothing), which the builder would have to build into a view, so it fails. By instead assigning it to a variable (in this case _, basically a variable that you can never access), the Void is never offered to the view builder in the first place.
You could argue the builder should simply accept and ignore Void values, but the idea is that your builder closures should not have side effects (I'd remove print statements after finishing debugging too)—you should not rely on these closures being called at certain times.
Here's a helper Print( ... ) View that acts like a print( ... ) function but within a View
Put this in any of your view files
extension View {
func Print(_ vars: Any...) -> some View {
for v in vars { print(v) }
return EmptyView()
}
}
and use inside of body like so
Print("Here I am", varOne, varTwo ...)
or inside a ForEach {} like so
self.Print("Inside ForEach", varOne, varTwo ...)
Note: you might need to put Print() into a Group {} when combining with existing views
Try right-clicking on the live preview play button and selecting 'Debug Preview from the popup
You can print in the body structure but to do so you have to explicitly return the view you want to render. The body property inside a View is just a computed property like any other in Swift that implicitly returns the view. And just like any other computed property, you can perform operations inside the computed property as long as a value is explicitly returned. For example, this will throw an error when you try to print because there is no explicit return:
struct SomeView: View {
#State var isOpen = false
var body: some View {
print(isOpen) // error thrown here
VStack {
// other view code
}
}
}
But if we explicitly return the view we want then it will work e.g.
struct SomeView: View {
#State var isOpen = false
var body: some View {
print(isOpen) // this ok because we explicitly returned the view below
// Notice the added 'return' below
return VStack {
// other view code
}
}
}
The above will work well if you're looking to view how state or environment objects are changing before returning your view, but if you want to print something deeper down within the view you are trying to return, then I would go with #Rok Krulec answer.
It is possible to use print() remembering that all SwiftUI View content are (a) implicit closures and (b) it is highly recommended to decompose views as much as possible to have simple structure, so it might look like the following...
struct Model: Identifiable {
let value: String
var id: String {
value
}
init (_ value: String) {
self.value = value
}
}
struct TestView: View {
#State var showFavoritesOnly = false
#State var listData: [Model] = [Model("one"), Model("two"), Model("three")]
var body: some View {
NavigationView {
List {
Toggle(isOn: $showFavoritesOnly) {
Text("Favorite only")
}
ForEach(listData) { data in
self.rowView(data: data)
}
}
}
}
private func rowView(data: Model) -> some View {
#if DEBUG
print(">> \(data.value)")
#endif
return NavigationLink(destination: Text("Details")) {
Text("Go next from \(data.value)")
}
}
}
... and right clicking in Preview to select run as Debug Preview we get:
2019-10-31 14:28:03.467635+0200 Test[65344:11155167] [Agent] Received connection, creating agent
2019-10-31 14:28:04.472314+0200 Test[65344:11155168] [Agent] Received display message
>> one
>> two
>> three
You can declare a printing() method that includes print() and returns EmptyView struct.
struct ContentView: View {
#State private var offset = CGSize.zero
func printing(_ items: Any...) -> some View {
let _ = print(items)
return EmptyView()
}
var body: some View {
#if DEBUG
printing(offset) // prints [(0.0, 0.0)]
#endif
ZStack {
Text("Hello")
}
}
}
The safest and easiest way to print while debugging in a SwiftUI View.
extension View {
func Print(_ item: Any) -> some View {
#if DEBUG
print(item)
#endif
return self
}
}
Usage Example:
struct ContentView: View {
var body: some View {
VStack {
ForEach((1...5), id: \.self) { number in
Text("\(number)")
.Print(number)
}
}
}
}
Console output:
1
2
3
4
5
It can be generalized to:
extension View {
func Perform(_ block: () -> Void) -> some View {
block()
return EmptyView()
}
}
So in your example:
ForEach(landmarkData) { landmark in
Perform { print("landmark: \(landmark)") }
if !self.userData.showFavoritesOnly || landmark.isFavorite {
NavigationButton(destination: LandmarkDetail(landmark: landmark)) {
LandmarkRow(landmark: landmark)
}
}
}
Here you go. It will just work like simple print but inside a view.
func printv( _ data : Any)-> EmptyView{
print(data)
return EmptyView()
}
and use it like that
struct ContentView: View {
var body: some View {
VStack() {
Text("hello To SwiftUI")
printv("its easy to code in SwiftUI")
Text("And Good to have you here")
}
}
}
The following extension on View is as intuitive as print because it's made to replicate the default print(_:separator:terminator:) function signature & behavior.
extension View {
func printUI(_ args: Any..., separator: String = " ", terminator: String = "\n") -> EmptyView {
let output = args.map(String.init(describing:)).joined(separator: separator)
print(output, terminator: terminator)
return EmptyView()
}
}
Usage Example:
struct ContentView: View {
var body: some View {
VStack {
printUI("ContentView", "1")
printUI("ContentView", "2", separator: ", ", terminator: "\n.\n.\n")
printUI("ContentView", "3", separator: "; ")
Text("Hello, World!")
}
}
}
Console Output:
ContentView 1
ContentView, 2
.
.
ContentView; 3
EDIT: Debug Preview is no longer supported in the latest versions of Xcode.
Very easy way to debug your Preview:
Open your Swift project in Xcode 11.
Right-click (or Control-click) on the Live Preview button in the bottom right corner of the preview.
Select Debug Preview.
How to debug your SwiftUI previews in Xcode
// Try this, add a 'return' on a view then the 'print' can stay alive in.
struct ContentView: View {
var num: Int = 1
var body: some View {
print(num)
return Text("hello")
}
}
You can't because you're in a computed property. You need for example a button and in the action you define the print. Or work with breakpoints
You can not print in body structure i.e. a structure which is some view type.For print you need to make function out of body structure and call it using button or something else.
This should work
if true {
print(aVar, "xx")
}
return ZStack {
...
}