i have a source code that i need to capture. the whole file is of one line but i am not able to capture the data that i require.
allow=ok&secret=4326dwsaddsafsd286435dsfs754
now i need to capture this data 4326dwsaddsafsd286435dsfs754 which changes everytime. it contains mixed a-z and 0-9, total lenght 40 letters
i tried using Left and Right selectors by using "secret=" on left but since the source ends at the end of the value, i dont have any thing to put in right selector.
so i need to know how can i capture this data? is there any regex cmd that can let me.?
thanks
Try this:
\&secret=(.*)
and then capture the first group with $1
Use this regex:
[a-z0-9]*$
It searches for the longest sequence of alpha-numeric characters ([a-z0-9]*) at the end of the string ($).
Test here.
Related
I am using the following regex to remove items in a sentence that falls within brackets
\(.*?\)
So in this sentence anything between (DFKJERLjDLJLF) gets removed.
But if there are more than one brackets in a sentence, I want to target only the last bracket. How do I change my regex?
So in this sentence (only) the last bracket and its contents (DFKJERLjDLJLF) gets removed.
Update: I tried using \s\([^)]+\)$ in my regex tool but it is not matching
Here is the example
.*(\(.*?\))
.* matches every character and moves the position to the end, when it bounce back
and then (\(.*?\)) find the first match in (), i.e. the last match from the start.
A python solution to this is:
def remove_last_brackets(string):
return re.sub(r'^(.*)\(.*?\)?([^()]*)$', lambda x: x.group(1) + x.group(2), string)
This is hard to answer without language context.
The global flag, supported on most regex systems, allows you to match all occurrences of a string directly.
Alternatively, you could store the first location of a match and then start future searches at that location, and repeat until there are no matches.
The input I can get might be
/DemoSystems/DemoFramework/MyRepo/MyModule/tags/2015_02_22
or
/DemoSystems/DemoFramework/MyRepo/MyModule/tags/2015_02_22/Demo.Tests/AverageTests.cs
I need to extract in both cases.
/DemoSystems/DemoFramework/MyRepo/MyModule/tags/2015_02_22
Regex:
^(.*?)tags
is matching till
/DemoSystems/DemoFramework/MyRepo/MyModule/tags
And added complexity is that 2015_02_22 can be anything. A mix of number alphabets and whitespaces. Basically depends on developer. So in other words I have to match till 'tags' + the next folder after it.
Any pointers?
You can use:
.*?tags\/[^\/]+
It will match anything from the start of the line until the word tags, the / after the word tags and the following characters until another / (excluding that) or the end of the string.
Online demo
I have a string like aaa**b***c****ddd, and I want to get a sequence of matched text of pattern [^*]\*+[^*], which should I thank be [a**b, b***c, c***d]. However, when I test this in text editor like vim or emacs, the second (b***c) is not matched.
aaa**b***c***ddd
|--| |---|
first third
|---|
second, which I think should be matched but not
How should I modify the regular expression to match the second?
Yes you can, the trick consists to put all in a capturing group inside a lookahead to allow overlapping results:
(?=([^*]\*+[^*]))
But you can't use this do to replacements since this pattern matches nothing. (or perhaps if you can get the capture group length and the current offset)
EDIT:
it seems to be possible to obtain the capture group length with vim with strlen(submatch(1))
#CommuSoft is correct. One way to approach this problem would be to match the whole string against this regex and then the second time around, you match this regex against the substring that starts at (index_of_first_previous_match + 1) until the end of the string. Hope that is clear.
So if the index of your first match above (a**b) was 2. Then the new substring that you match against the regex the second time should start from index 3 till the end of the string. This will give you the two results.
However, Casimir's answer is much simpler.
I have a large subset of data that looks like this:
MyApp.Whatever\app.config(115): More stuff here, but possibly with numbers or parenthesis...
I'd like to create a replace filter using Notepad++ that would identify and replace the line number "(115):" and replace it with a tab character followed by the same number.
I've been trying filters such as (\(\d+\):) and (\(\[0-9]+\):), but they keep returning the entire value in the \1 output.
How would I create a filter using Notepad++ that would successfully replace (115): with tab character + 115?
Use a quantifier.. (\(\d+?\):) where the ? will prevent it from being greedy. Also, since everything is in a () it will group it all and treat it as \1 ..
If it was in perl I'd say \((\d+?)\): which should match only the inner part.
Edit:
Just talked with my colleague - he said s/\((\d+)\)/\t\1/ and if you needed app config in front you could just put that in the front.
this should work for your needs
replace
\((\d+)\):
with
\t$1
Replacing (\(\d+\):) with \t\1 will keep the parenthesis and the colon since you've included them in the group (the outer parenthesis), and I think that's what you mean by "they keep returning the entire value."
Instead of escaping those inner parenthesis, escape the outer ones like the other answers have suggested: \((\d+)\): - this says to match a left paren, then match and capture a group of digits, then match a right paren and a colon. Replacing that with \t\1 will get rid of the parens and colon that were not in the captured group.
I'm trying to write a regex to sift through a sizable amount of data. After it finds something, I want it to match the next 4 characters whatever they are. How can I do this?
/match long stuff here..../
The . in a regex is "Any character." Four of them gets you four characters. You could also do:
/match long stuff here.{4}/
This may depend on what language you are writing your regex in.
The expression .... matches any four characters. Append that to your pattern, and put parenthesis around it so that whatever those characters are will be captured.
For example:
[Hh]ello [Ww]orld(....)
Look at this example: I want to match an IP and the next 4 characters after it.I have a regex
(?:\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(.{4})
if you match that against the following string 192.167.45.45xabc the first part (?:\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}) will match the IP and the last part (.{4}) will match xabc. (I had added ?: at the beginning to make the first block noncapturing - if you want to capture the IP to just remove ?:)
I hope this helps