I have this code:
import os
def inplace_change(filename, old_string, new_string):
# Safely read the input filename using 'with'
with open(filename, 'r') as f:
s = f.read()
if old_string not in s:
print('"{old_string}" not found in {filename}.'.format(**locals()))
return
else:
# Safely write the changed content, if found in the file
with open(filename, 'w') as f:
s = s.replace(old_string, new_string)
f.write(s)
path = raw_input("Enter the file's full path: ")
old = raw_input("String to change: ")
new = raw_input("change to: ")
print "********************************"
print "**** WORKING... PLEASE WAIT ****"
print "********************************\n"
for file in os.listdir(path):
filename = os.path.join(path,file)
inplace_change(filename, old, new)
os.system("pause")
As you can see, the code is replacing sub string in a file with another sub string. I want my code to change text as directed in a text file, like "instruction file" what to change.
The text file will be:
"old_string" "new_string"
"old_string" "new_string"
"old_string" "new_ string"
the result will be that all files in directory will change all the old_string to new_string
How can I do it?
Related
I am trying to modify the code to apply to multiple text files in the same directory. The code looks as follows but there is an error "NameError: name 'output' is not defined". Can you help me to suggest improvements to the code?
import re
def replaceenglishwords(filename):
mark_pattern = re.compile("\\*CHI:.*")
word_pattern = re.compile("([A-Za-z]+)")
for line in filename:
# Split into possible words
parts = line.split()
if mark_pattern.match(parts[0]) is None:
output.write()
continue
# Got a CHI line
new_line = line
for word in parts[1:]:
matches = word_pattern.match(word)
if matches:
old = f"\\b{word}\\b"
new = f"{matches.group(1)}#s:eng"
new_line = re.sub(old, new, new_line, count=1)
output.write(new_line)
import glob
for file in glob.glob('*.txt'):
outfile = open(file.replace('.txt', '-out.txt'), 'w', encoding='utf8')
for line in open(file, encoding='utf8'):
print(replaceenglishwords(line), '\n', end='', file=outfile)
outfile.close()
replaceenglishwords needs two parameters, one for the file you are searching and one for the file where you write you results: replaceenglishwords(filename, output). It looks like your function is reading the input file line by line by itself.
Now you can open both files in your loop and pass them to replaceenglishwords:
for file in glob.glob('*.txt'):
textfile = open(file, encoding='utf8')
outfile = open(file.replace('.txt', '-out.txt'), 'w', encoding='utf8')
replaceenglishwords(textfile, outfile)
textfile.close()
outfile.close()
I have a task to get all the files from a directory , read the files find if the files contain anything with extension .crv. I have written the following code using Python but there is something wrong the code runs infintely. Can some help me in identifying what could possibly be wrong.
for file in os.listdir(location):
try:
if file.endswith(".cxx"):
#print "crvfile found:\t", file
filepath = location+"\\"+file
#print filepath
cxxopenfile = open(filepath,"r")
for line in crvopenfile:
line = line.rstrip()
find = re.findall('^\S*(['.crv']+), line)
#if len(find) > 0:
v
v
cxxopenfile.close()
cxxfiles.append(str(file))
counter = counter+1
except Exception as e:
raise e
print "No files found here!"
print "Total files found:\t", counter
#!/usr/bin/env python
import os
import sys
import re
from os import listdir
location = "c:\\git\\repos\\test-code"
counter = 0
for file in os.listdir(location):
try:
if file.endswith(".cxx"):
#print "crvfile found:\t", file
filepath = location+"\\"+file
#print filepath
cxxopenfile = open(filepath,"r")
for line in cxxopenfile:
line = line.rstrip()
find = re.findall("^\S*['.crv']+", line)
if len(find) > 0:
#cxxfiles.append(str(file))
counter = counter+1
else:
print "No extension .crv found!"
cxxopenfile.close()
except Exception as e:
raise e
print "No files found here!"
print "Total files found:\t", counter
Results:
$ python ./test.py
No extension .crv found!
No extension .crv found!
No extension .crv found!
Total files found: 2
I am having a bit of trouble in obtaining a file path so that I can open and execute my data from the specified (text) file. Below is the code I have written so far:
def pickfile():
options={}
options['defaultextension'] = '.txt'
options['filetypes'] = [('all files','.*'), ('text files', '.*txt')]
options['initialfile'] = 'sample.txt'
options['initialdir'] = 'C:\Users\profcs\Desktop'
filename=open(tkFileDialog.askopenfilename(**options))
if filename:
print(filename)
return
with open(filename, 'rb') as f:
reader = csv.reader(f)
try:
for row in reader:
print row
except csv.Error as e:
sys.exit('file %s, line %d: %s' % (filename, reader.line_num,e))
but1 = Button(widget1, text='Pick Your File', command=pickfile)
but1.pack(side=BOTTOM, padx=10, pady=1, anchor=SE)
but1.config(relief=RAISED, bd=2)
When I display a filename, I now get the path in this form:
================ RESTART: C:\Users\profcs\Desktop\BD TEST.py ================
<open file u'C:/Users/profcs/Desktop/sample.txt', mode 'r' at 0x01EFF128>
How can I filter this path and only get 'C:/Users/profcs/Desktop/sample.txt' so that I can open my file?
Thanks in advance.
filename.name gives you the path from filename object.
I hope this helps :
filename = open(tkFileDialog.askopenfilename(**options))
print (filename.name)
'C:/Users/profcs/Desktop/sample.txt'
In your case filename is an object which represents an open file.
My code is currently taking in a csv file and outputting to text file. The piece of code I have below and am having trouble with is from the csv I am searching for a keyword like issues and every row that has that word I want to output that to a text file. Currently, I have it printing to a JSON file but its all on one line like this
"something,something1,something2,something3,something4,something5,something6,something7\r\n""something,something1,something2,something3,something4,something5,something6,something7\r\n"
But i want it to print out like this:
"something,something1,something2,something3,something4,something5,something6,something7"
"something,something1,something2,something3,something4,something5,something6,something7"
Here is the code I have so far:
def search(self, filename):
with open(filename, 'rb') as searchfile, open("weekly_test.txt", 'w') as text_file:
for line in searchfile:
if 'PBI 43125' in line:
#print (line)
json.dump(line, text_file, sort_keys=True, indent = 4)
So again I just need a little guidance on how to get my json file to be formatted the way I want.
Just replace print line with print >>file, line
def search(self, filename):
with open('test.csv', 'r') as searchfile, open('weekly_test.txt', 'w') as search_results_file:
for line in searchfile:
if 'issue' in line:
print >>search_results_file, line
# At this point, both the files will be closed automatically
I am fairly new in python.
I am parsing a big file and I want to check that the different inputs are correct, especially if the ID entered is in the file header.
When I run the following code, I get this error message:
AttributeError: 'str' object has no attribute 'readlines'
filename = str(raw_input('enter filename: '))
try:
with open(filename, 'rU'): pass
except IOError:
print 'The file does not exist'
sys.exit(0)
def findID(w):
return re.compile(r'\b({0})\b'.format(w), flags=re.IGNORECASE).search
while True:
ID = (raw_input("Enter ID: ")).upper()
IDheader = ID + ".NA"
with open(filename, 'rU') as f:
first_line = f.readline()
if findID(IDheader)(first_line):
print "you entered ",ID
break
else:
pass
print "ID not in this file."`
for line in filename.readlines():
Line = line.split()
if...
Thank you
filename is a filename, not a file handle. You need to open it:
with open(filename, 'r') as handle:
for line in handle:
line = line.split()