Django and Ajax refreshing a div - django

Question

I am very new to JS/Ajax and a relative novice to Django. I am testing to see how I can get information back and forth from an Ajax call to my view, and back to Ajax to replace a header string as a simple test.
I can receive information back to my view (h1, which is "AJAX TEST"). What I can't seem to get is the h2text to change to "HEADER CHANGED".
Any help is appreciated as I don't know if it's my Django return function or my Ajax function.
Here is my ajax_test.html:
<div class="content">
<div class="center">
<h1 id="h1">AJAX TEST</h1>
<div>
<button id="btn">PRESS ME</button>
</div>
</div>
<div id="update_div">
{% include "ProdPlat/ajax_test_div.html" %}
</div>
</div>
<script type="text/javascript" src="{% static 'ProdPlat\js\ajax_test.js' %}"></script>
{% endblock %}
My ajax_test_div.html (which I'm trying to refresh):
<div class="content">
<div class="center">
<h2 id="h2">{{h2text.h2text}}</h2>
</div>
</div>
My views_test.py:
def test_ajax(request):
h2text = {'h2text': "INITIAL HEADER"}
if request.method == 'POST':
logger.debug('POST request')
text = request.POST.get('text')
logger.debug('text = {}'.format(text))
h2text = "HEADER CHANGED"
dict = {
'h2text': h2text,
}
# return JsonResponse(dict)
# return render(request, 'ProdPlat/ajax_test_div.html', {'h2text': h2text})
return render_to_response('ProdPlat/ajax_test_div.html', dict)
return render(request, 'ProdPlat/ajax_test.html', {'h2text': h2text})
And finally my Ajax call:
$(document).on('click', 'button', function(){
var csrftoken = getCookie('csrftoken');
console.log('Button Clicked!');
var text = $('h1').text()
console.log('h1 text = ' + text);
$.ajax({
type : 'POST',
url : "/ProdPlat/Ajax_Test/",
dataType: 'json',
data: {'text' : text,
'csrfmiddlewaretoken': csrftoken,
},
success: function(data) {
console.log('data = ' + data);
console.log('data.h2text = ' + data.h2text);
$('#update_div').load(' #update_div')
console.log('Success!');
},
failure: function(data) {
console.log('Failed!');
console.log('data = ' + data);
},
})
})