I have string like this:
&breakUp=Mumbai;city,Puma;brand&
where Mumbai;city and Puma;brand are filters(let say) separated by comma(,). I have to add more filters like Delhi;State.
I am using following regular expression to find the above string:
&breakUp=.([\w;,]*).&
and following regular expression to replace it:
&breakUp=$1,Delhi;State&
It is finding the string correctly but while replacing it is removing the first and last character and giving the following result:
&breakUp=umbai;city,Puma;bran,Delhi;State&
How to resolve this?
Also, If I have no filters I don't want that first comma. Like
&breakUp=&
should become
&breakUp=Delhi;State&
How to do it?
My guess is that your expression is just fine, there are two extra . in there, that we would remove those:
&breakUp=([\w;,]*)&
In this demo, the expression is explained, if you might be interested.
To bypass &breakUp=&, we can likely apply this expression:
&breakUp=([^&]+)&
Demo
Your problem seems to be the leading and trailing period, they are matched to any character.
Try using this regex:
&breakUp=([\w;,]*)&
Related
i have the following JSON string that i need to parse:
{'ConnectionDetails':'{\'server\':\'johnssasd02\',\'database\':\'enterprise analytics\'}'}]}
i am already using the expression '([^']*)' to get everything in quotes, which correctly gets me the ConnectionDetails title. However i now need an expression to get me everything between '{ and '} in order to get the full path value. so i need to capture the following from above string:
{\'server\':\'johnssasd02\',\'database\':\'enterprise analytics\'}
but having trouble coming up the regex expression
thanks
In order to extract the data between the curly braces {} you can use the regex: \{(.*?)\}
i accomplished it within an SSIS derived column task where i removed unwanted characters from the input string. that way i don't have to worry about dealing with them using regex.
I'm trying to build an expression which will match all text EXCLUDING text with prefix 'abc' AND suffix 'def' (text which only has the prefix OR the suffix is ok).
I've tried the following:
^(?!([a][b][c]])).*(?!([d][e][f])$), but it doesn't match text which only has one of the criterias (i.e. abc.xxx fails, as well as xxx.pdf, though they should pass)
I understand the answer is related to 'look behind' but i'm still not quite sure how to achieve this behavior
I've also tried the following:
^(?<!([a][b][c])).*(?!([d][e][f])$), but again, with no luck
^((abc.*\.(?!def))|((?!abc).*\.def))$
I think there can be a simpler solution, but this one will work as you wanted it.
[a][b][c] can be simplified to abc, the same goes for def.
The first part of the pattern matches abc.*\. without def at the end.
The second part matches .*\.def without the prefix abc.
Here is a visual representation of the pattern:
Debuggex Demo
Keep it simple and combine it into a single lookahead to check both conditions:
^(?!abc.*def$).*
I need to extract content inside brackets () from the following string in C++;
#82=IFCCLASSIFICATIONREFERENCE($,'E05.11.a','Rectangular',#28);
I tried following regex but it gives an output with brackets intact.
std::regex e2 ("\\((.*?)\\)");
if (std::regex_search(sLine,m,e2)){
}
Output should be:
$,'E05.11.a','Rectangular',#28
The result you are looking for should be in the first matching subexpression, i.e. comprised in the [[1].first, m[1].second) interval.
This is because your regex matches also the enclosing parentheses, but you specified a grouping subexpression, i.e. (.*?). Here is a starting point to some documentation
Use lookaheads: "(?<=\\()[^)]*?(?=\\))". Watch out, as this won't work for nested parentheses.
You can also use backreferences.
(?<=\().*(?=\))
Try this i only tested in one tester but it worked. It basically looks for any character after a ( and before a ) but not including them.
I am using the following regular expression to validate e-mails, but it allows empty strings as well, how can I change it to prevent it:
^[\w\.\-]+#[a-zA-Z0-9\-]+(\.[a-zA-Z0-9\-]{1,})*(\.[a-zA-Z]{2,3}){1,2}$
I am using an asp:RegularExpressionValidator. My other option is to add on a asp:RequiredFieldValidator, but I am curious if this is possible to check for blanks in my RegularExpressionValidator, so I don't have to have 2
see http://www.regular-expressions.info/email.html
That expression does not match empty strings. The expression starts with ^[\w\.\-]+ this translates to "The string must start with a word character, period or slash. There can be more than one of these." There must be something else wrong or you copied the expression incorrectly.
This RegEx validates if a given string is in a valid email-format or not:
/^[a-zA-Z0-9\_\-\.]+\#([a-zA-Z0-9\-]+\.)+[a-zA-Z0-9]{2,4}$/
I'm working wih a regular expression and have some lines in javascript. My expression should deliver two matches but recognizes only one and I don't know whats the problem.
The Lines in javascript look like this:
if(mode==1) var adresse = "?APPNAME=CampusNet&PRGNAME=ACTION&ARGUMENTS=-A7uh6sBXerQwOCd8VxEMp6x0STE.YaNZDsBnBOto8YWsmwbh7FmWgYGPUHysiL9u0.jUsPVdYQAlvwCsiktBzUaCohVBnkyistIjCR77awL5xoM3WTHYox0AQs65SoHAhMXDJVr7="; else var adresse = "?APPNAME=CampusNet&PRGNAME=ACTION&ARGUMENTS=-AHMqmg-jXIDdylCjFLuixe..udPC2hjn6Kiioq7O41HsnnaP6ylFkQLhaUkaWKINEj4l2JqL2eBSzOpmG.b5Av2AvvUxEinUhMBTt5awdgAL4SkBEgYXGejTGUxcgPE-MfiQjefc=";
My expression looks like this:
(?<Popup>(popUp\(')|(adresse...")).*\?((?<Parameters>APPNAME=CampusNet[^>"']*["']))
I want to have two matches with APPNAME...... as Parameters.
[UPDATE] Like Tim Pietzcker wrote i used the greedy version and should have used the lazy version. while he wrote that i solved it myself by using .? instead of . in the middle so the expression looks like this:
(?<Popup>(popUp\(')|(adresse...")).*?\\?((?<Parameters>APPNAME=CampusNet[^>"']*["']))
That worked. Thanks to Tim Pietzcker
Your regex matches too much - from the very first adresse until the very last " because it uses a greedy quantifier .*.
If you make that quantifier lazy, i. e.
(?<Popup>(popUp\(')|(adresse...")).*?\?((?<Parameters>APPNAME=CampusNet[^>"']*["']))
you get two matches.
Alternatively, if your data allows this, use a different quantifier that only matches non-space characters. This will match faster (but will fail of course if the text you're trying to match could possibly contain spaces):
(?<Popup>(popUp\(')|(adresse..."))\S*\?((?<Parameters>APPNAME=CampusNet[^>"']*["']))
Usually you must apply the regex with the "global" flag to find all matches. I can't really say more until I see the complete code sample you are working with.