I'd need to split or extract only numbers made of 8 digits from a string in Google Sheets.
I've tried with SPLIT or REGEXREPLACE but I can't find a way to get only the numbers of that length, I only get all the numbers in the string!
For example I'm using
=SPLIT(lower(N2),"qwertyuiopasdfghjklzxcvbnm`-=[]\;' ,./!:##$%^&*()")
but I get all the numbers while I only need 8 digits numbers.
This may be a test value:
00150412632BBHBBLD 12458 32354 1312548896 ACT inv 62345471
I only need to extract "62345471" and nothing else!
Could you please help me out?
Many thanks!
Please use the following formula for a single cell.
Drag it down for more cells.
=INDEX(TRANSPOSE(QUERY(TRANSPOSE(IF(LEN(SPLIT(REGEXREPLACE(A2&" ","\D+"," ")," "))=8,
SPLIT(REGEXREPLACE(A2&" ","\D+"," ")," "),"")),"where Col1 is not null ",0)))
Functions used:
QUERY
INDEX
TRANSPOSE
IF
LEN
SPLIT
REGEXREPLACE
If you only need to do this for one cell (or you have your heart set on dragging the formula down into individual cells), use the following formula:
=REGEXEXTRACT(" "&N2&" ","\s(\d{8})\s")
However, I suspect you want to process the eight-digit number out of all cells running N2:N. If that is the case, clear whatever will be your results column (including any headers) and place the following in the top cell of that otherwise cleared results column:
=ArrayFormula({"Your Header"; IF(N2:N="",,IFERROR(REGEXEXTRACT(" "&N2:N&" ","\s(\d{8})\s")))})
Replace the header text Your Header with whatever you want your actual header text to be. The formula will show that header text and will return all results for all rows where N2:N is not null. Where no eight-digit number is found, null will be returned.
By prepending and appending a space to the N2:N raw strings before processing, spaces before and after string components can be used to determine where only eight digits exist together (as opposed to eight digits within a longer string of digits).
The only assumption here is that there are, in fact, spaces between string components. I did not assume that the eight-digit number will always be in a certain position (e.g., first, last) within the string.
Try this, take a look at Example sheet
=FILTER(TRANSPOSE(SPLIT(B2," ")),LEN(TRANSPOSE(SPLIT(B2," ")))=8)
Or this to get them all.
=JOIN(" ,",FILTER(TRANSPOSE(SPLIT(B2," ")),LEN(TRANSPOSE(SPLIT(B2," ")))=8))
Explanation
SPLIT with the dilimiter set to " " space TRANSPOSE and FILTER TRANSPOSE(SPLIT(B2," ") with the condition1 set to LEN(TRANSPOSE(SPLIT(B2," "))) is = 8
JOIN the outputed column whith " ," to gat all occurrences of number with a length of 8
Note: to get the numbers with the length of N just replace 8 in the FILTER function with a cell refrence.
Using this on a cell worked just fine for me:
(cell_with_data)=REGEXEXTRACT(A1,"[0-9]{8}$")
Sample sheet.
As the title says, given a column of arbitrary number of words of arbitrary length, Want a single ArrayFormula to get the first letters of all words in the said column.
I have tried two methods, seen in sample sheet.
1) Using SPLIT and ARRAYFORMULA, can get it one cell but cannot extend down column.
2) Using 2 REGEXEXTRACT, can get for first 2 initials and extend down
But is it possible to get for arbitrary number of words for whole column using ArrayFormula.
Is it possible to use REGEXEXTRACT to return the first letters of many words?
This replaces every word with the captured first letter
=ARRAYFORMULA(UPPER(REGEXREPLACE(A1:A6,"(\w)\S*\s?","$1")))
I am new to OpenRefine and GREL.
In a address row, I am trying to extract the city and the postal code.
The row will typically contains : 12 rue du Paradis 75012 Paris
I'd like to split this row starting from the 5 digit number (75012). After I could easily extract the city.
In the command "Split into several columns", what Regular expression would you put (or is it another command)?
Thanks!
The 'split into several columns' takes a regular expression as an argument to specify the separator to be used when doing the split. This is probably not what you need in this case - since there isn't a common expression for the separator.
Instead you would probably be better using the "Add column based on this column" option and then using a 'match' function to create the new column. The 'match' takes a regular expression as an argument, but allows you to capture the output - so you can use this to do pattern matching in a string. In this case for example you could use something like:
value.match(/.*\s+(\d{5})\s+(.*)/)
This would capture the 5 digit number and the city in an array:
["75012","Paris"]
You could then use this to create the values you want in the new column, or in two new columns. E.g.:
value.match(/.*\s+(\d{5})\s+(.*)/)[0]
will get the number
I have a column containing two names, which I'd like to extract into two separate columns surname1 and surname2 (I don't need the name nor the initial letter (e.g. N.)).
The exemplary content of that column is:
AwyeEaef2012 MS101 N.Lopez-O.Lorenzi.txt
-Lopez and Lorenzi are these two which we are looking for in this row.
What is good about my situation is that the first name comes always after the first dot (.) and ends just before the dash (-) and the second name comes just after second dot and ends just before the third dot and txt (.txt).
I know how to write a regex and using LIKE check if that column contains some specific surname but not the opposite way- how to read surnames and write them into two new columns.
Several rows from that column look like below:
WyeEaef MN2014 MS401 N.Lopez-O.Lorenzi.txt
AwyufEQ WCH2014 OS401 N.Lorenzi-O.Lopez.txt
THAFa5u WCH2014 LS107 N.Larry-O.Lolly.txt
So the pattern is as I mentioned *.Name1-[A-Z].Name2.txt
Where * is max 30 characters of capital and small letters and numbers
It could be approached in this manner: other words we need to divide this into substrings divided by dots first substring is a waste, the second without two last characters(a dash and acapital letter, e.g. -O) is the first name, the third substring is the second name and the fourth is another waste(a former file format).
I'd like to have an output of three columns:
initialColumn, firstName, secondName
The workaround that I wrote as a formula in Excel which I personally don't love, but might be useful for someone in the future.
=MID(A1;FIND(".";A1;1)+1;FIND(".";A1;FIND(".";A1;1)+1)-FIND(".";A1;1)-3)
I was surprised that Excel can manage processing ~0.5mln of records in the blink of an eye.
I have a column in an Excel spreadsheet that contains the following:
### - 3-digit number
#### - 4-digit number
A### - character with 3-digits
#A## - digit followed by character then 2 more digits
There may also be superfluous characters to the right of these strings.
I would like to sort the entire spreadsheet by this column in the following order (ascending or descending):
the first three types of strings alphabetically as expected (NOT ASCII-Betically!)
Then the #A## by the character first, then by the first digit.
Example:
000...999, 0000...9999, A000...Z999, 0A00...9A99, 0B00...9B99...9Z99
I feel there is a very simple solution using a regular expression or macro but my VBa and RegExp are pretty rusty (a friend asked me for this but I' m more of a C-guy these days). I have read some solutions which involve splitting the data into additional columns which I would be fine with.
I would settle for a link to a good guide. Eternal thanks in advance.
If you want to sort by second character regardless of the content ahead and behind, then regex ^.(.) represents second character match...