Value not passing to subroutine using a common block - fortran

I'm trying to pass a parameter between a Fortran main program and a subroutine. However for some reason a different value is obtained in the subroutine. I am using common blocks.
program main
nzcur=1
write(*.*)"nzcur in main",nzcur
call hit
subroutine hit
common/part/nzcur
write(*,*)"nzcur in hit",nzcur; pause
end
end program
I would expect nzcur=1 but I get nzcur=0.
I think it could be a data type mismatch as I do not define it, only as a common block.

As noted in the comments, the correct learning response to this question is to avoid using common blocks to have access to variables from other scopes. In writing code in the modern era there are far better ways (more later).
Fortunately, however, we can look at this question in terms of "how do I understand what is happening with this common block?". Such a question is useful to those unfortunate programmers trying to understand old (or badly written new) code.
In considering the program of the question one should note that several corrections are required to have compilable code (with different possible approaches). The errors there are not directly relevant to the discussion.
In the subroutine
subroutine hit
common/part/nzcur
write(*,*)"nzcur in hit",nzcur; pause
end
we have a named common block called part, with one numeric storage unit which contains the integer variable nzcur (thanks to implicit typing).
In the question there is clearly the expectation that the variable nzcur in this common block accesses some other variable called nzcur and that this other variable is the one in the main program called nzcur. This is not correct.
nzcur in the subroutine is associated only with the first numeric storage unit of any other common block named part. The association is not based on named or location in the common block definition.
In the program of the question, there is no other common block called part; nzcur of the subroutine is not associated with anything else. It is certainly not associated with a variable not in a common block.
Because of this lack of association, the variable is not defined by the time the write statement references it. Again, the definition of the variable in the main program does not affect the definition of the local variable in the subroutine.
To "correct" the association, it will be necessary to put the variable nzcur of the main program in the correct location in a common block named part (in the main program).
To answer the question of "how do I set the value of nzcur in the subroutine without using common blocks?", refer to other questions such as this one.

Related

How does Fortran handle optional arguments and strings? [duplicate]

I have a FORTRAN code with a routine:
SUBROUTINE READ_NC_VALS(NCID, RECID, VARNAME, VARDATA)
integer ncid, recid
character*(*) varname
real*8 vardata
dimension vardata(15,45,75)
etc.
I want to add some flexibility to this code, and I thought I would do it by first adding an optional flag argument:
SUBROUTINE READ_NC_VALS(NCID, RECID, VARNAME, VARDATA, how_to_calculate)
! everything the same and then ...
logical, optional :: how_to_calculate
Now, at this point, I am not even using "how_to_calculate". I am just putting it into the code for testing. So I compile the code without a hitch. Then I run it, and I get an error in the subroutine. Specifically, some of the values in the code later on are "magically" altered from what they were without that optional argument. The new values don't make sense to the logic of the code, so it exits politely with an error message. Let me stress again that at this point, I am not even using this optional argument. So then, on a lark, I go back to all the places in the source that call this routine and, even though my new argument in optional, I put in values for it in all the calls. When I do that, the code runs fine. So, what's up? How can the mere presence of an unused optional argument in a subroutine result in other data being corrupted? And how can adding input parameters for this optional argument fix things again? This is being compiled with PGI, by the way.
Any ideas? Thanks.
BTW, sorry for not providing more code. My boss might not be too happy with me if I did that. I don't make the rules; I just work here.
Optional arguments in Fortran are implemented by passing 0 (a null pointer) for each optional argument that has no value provided by the calling subroutine. Because of this subroutines that take optional arguments have to:
either have an explicit INTERFACE definition inside the calling subroutine
or be a module-level subroutine (for them interfaces are generated automatically)
If you add an optional argument to a subroutine but it neither has an interface in the caller or is not a module-level subroutine, then the compiler will not generate the right calling sequence - it will pass less arguments than expected. This could pose a problem on Unix systems, where PGI passes the length of all CHARACTER*(*) arguments at the end of the argument list (on Windows it passes the length as the next argument after the address of the string). One missing argument would shift the length arguments placement in the stack (or put them in the wrong registers on x64) leading to the incorrect length of the VARNAME string being received by READ_NC_VALS. This could lead to all sorts of ill behaviour, including overwritting memory and "magically" changing values that should not change according to the program logic.
Obviously, just adding a dummy argument to a subroutine, with or without the optional attribute, shouldn't cause any problems. What might happen, though, is that the change exposes some other problem with the code, which was already there, but didn't cause any visible bad effects.
Without any more code, all we can do is guess, which usually isn't really useful.
One thing that pops into mind is the necessity of an explicit interface, when using optional arguments. Is the code organized into modules?

Is It Necessary to declare the Type of User-Defined Functions in ANY Calling Routine?

I use the Intel Visual Fortran. According to Chapmann's book, declaration of function type in the routine that calls it, is NECESSARY. But look at this piece of code,
module mod
implicit none
contains
function fcn ( i )
implicit none
integer :: fcn
integer, intent (in) :: i
fcn = i + 1
end function
end module
program prog
use mod
implicit none
print *, fcn ( 3 )
end program
It runs without that declaration in the calling routine (here prog) and actually when I define its type (I mean function type) in the program prog or any other unit, it bears this error,
error #6401: The attributes of this name conflict with those made accessible by a USE statement. [FCN] Source1.f90 15
What is my fault? or if I am right, How can it be justified?
You must be working with a very old copy of Chapman's book, or possibly misinterpreting what it says. Certainly a calling routine must know the type of a called function, and in Fortran-before-90 it was the programmer's responsibility to ensure that the calling function had that information.
However, since the 90 standard and the introduction of modules there are other, and better, ways to provide information about the called function to the calling routine. One of those ways is to put the called functions into a module and to use-associate the module. When your program follows this approach the compiler takes care of matters. This is precisely what your code has done and it is not only correct, it is a good approach, in line with modern Fortran practice.
association is Fortran-standard-speak for the way(s) in which names (such as fcn) become associated with entities, such as the function called fcn. use-association is the way implemented by writing use module in a program unit, thereby making all the names in module available to the unit which uses module. A simple use statement makes all the entities in the module known under their module-defined names. The use statement can be modified by an only clause, which means that only some module entities are made available. Individual module entities can be renamed in a use statement, thereby associating a different name with the module entity.
The error message you get if you include a (re-)declaration of the called function's type in the calling routine arises because the compiler will only permit one declaration of the called function's type.

Passing function pointers as an API interface to a compiled library

Dearest stack exchange,
I'm programming an MRI scanner. I won't go into too much background, but I'm fairly constrained in how much code I've got access to, and the way things have been set up is...suboptimal. I have a situation as follows:
There is a big library, written in C++. It ultimately does "transcoding" (in the worst possible way), writing out FPGA assembly that DoesThings. It provides a set of functions to "userland" that are translated into (through a mix of preprocessor macros and black magic) long strings of 16 bit and 32 bit words. The way this is done is prone to buffer overflows, and generally to falling over.*
The FPGA assembly is then strung out over a glorified serial link to the relevant electronics, which executes it (doing the scan), and returning the data back again for processing.
Programmers are expected to use the functions provided by the library to do their thing, in C (not C++) functions that are linked against the standard library. Unfortunately, in my case, I need to extend the library.
There's a fairly complicated chain of preprocessor substitution and tokenization, calling, and (in general) stuff happening between you writing doSomething() in your code, and the relevant library function actually executing it. I think I've got it figured out to some extent, but it basically means that I've got no real idea about the scope of anything...
In short, my problem is:
In the middle of a method, in a deep dark corner of many thousands of lines of code in a big blob I have little control over, with god-knows-what variable scoping going on, I need to:
Extend this method to take a function pointer (to a userland function) as an argument, but
Let this userland function, written after the library has been compiled, have access to variables that are local to both the scope of the method where it appears, as well as variables in the (C) function where it is called.
This seems like an absolute mire of memory management, and I thought I'd ask here for the "best practice" in these situations, as it's likely that there are lots of subtle issues I might run into -- and that others might have lots of relevant wisdom to impart. Debugging the system is a nightmare, and I've not really got any support from the scanner's manufacturer on this.
A brief sketch of how I plan to proceed is as follows:
In the .cpp library:
/* In something::something() /*
/* declare a pointer to a function */
void (*fp)(int*, int, int, ...);
/* by default, the pointer points to a placeholder at compile time*/
fp = &doNothing(...);
...
/* At the appropriate time, point the pointer to the userland function, whose address is supplied as an argument to something(): /*
fp= userFuncPtr;
/* Declare memory for the user function to plonk data into */
i_arr_coefficients = (int) malloc(SOMETHING_SENSIBLE);
/* Create a pointer to that array for the userland function */
i_ptr_array=&i_arr_coefficients[0];
/* define a struct of pointers to local variables for the userland function to use*/
ptrStrct=createPtrStruct();
/* Call the user's function: */
fp(i_ptr_array,ptrStrct, ...);
CarryOnWithSomethingElse();
The point of the placeholder function is to keep things ticking over if the user function isn't linked in. I get that this could be replaced with a #DEFINE, but the compiler's cleverness or stupidity might result in odd (to my ignorant mind, at least) behaviour.
In the userland function, we'd have something like:
void doUsefulThings(i_ptr_array, ptrStrct, localVariableAddresses, ...) {
double a=*ptrStrct.a;
double b=*ptrStrct.b;
double c=*localVariableAddresses.c;
double d=doMaths(a, b, c);
/* I.e. do maths using all of these numbers we've got from the different sources */
storeData(i_ptr_array, d);
/* And put the results of that maths where the C++ method can see it */
}
...
something(&doUsefulThings(i_ptr_array, ptrStrct, localVariableAddresses, ...), ...);
...
If this is as clear as mud please tell me! Thank you very much for your help. And, by the way, I sincerely wish someone would make an open hardware/source MRI system.
*As an aside, this is the primary justification the manufacturer uses to discourage us from modifying the big library in the first place!
You have full access to the C code. You have limited access to the C++ library code. The C code is defining the "doUsefullthings" function. From C code you are calling the "Something" function ( C++ class/function) with function pointer to "doUseFullThings" as the argument. Now the control goes to the C++ library. Here the various arguments are allocated memory and initialized. Then the the "doUseFullThings" is called with those arguments. Here the control transfers back to the C code. In short, the main program(C) calls the library(C++) and the library calls the C function.
One of the requirements is that the "userland function should have access to local variable from the C code where it is called". When you call "something" you are only giving the address of "doUseFullThings". There is no parameter/argument of "something" that captures the address of the local variables. So "doUseFullThings" does not have access to those variables.
malloc statement returns pointer. This has not been handled properly.( probably you were trying to give us overview ). You must be taking care to free this somewhere.
Since this is a mixture of C and C++ code, it is difficult to use RAII (taking care of allocated memory), Perfect forwarding ( avoid copying variables), Lambda functions ( to access local varibales) etc. Under the circumstances, your approach seems to be the way to go.

Localize the range of common block variables in Fortran 77

I'm working on this F77 code with extensive use of COMMON BLOCKS, and those COMMON BLOCKS are also used in a C program (after name mangling). If foo(a, b, ...) is the main routine of the fortran code, is there anyway to make the COMMON BLOCKS local to foo() so I can do something like the following?
program new_control_routine()
...
call foo(a1,b1,...)
...
call foo(a2,b2,...)
...
end
The point is to have multiple calls of "foo" with each of them having independent COMMON BLOCKS, even though they those blocks have the same names. The only way I know is to rename the COMMON BLOCKS and related subroutines in the second call of "foo", so it becomes another routine "foo1", so I can do:
programe new_control_routine()
...
call foo(a1,b1,...)
...
call foo1(a2,b2,...)
But this is certainly mundane and error-prone.
The point of common blocks is that they are global, accessible to any routine that uses their name. Could you make the variables in the common blocks arrays, and pass an index, so that your different calls accessed different elements?
Why limit yourself to FORTRAN 77? With Fortran 95/2003 you could create a user-defined type and create a array-variable of that type. Then you pass the index of the element that you want to work on. The user-defined type can be a complex group of variables. The variable can either be an argument to the subroutines or a module variable.

Passing an internal procedure as argument

I want to solve a differential equation lots of times for different parameters. It is more complicated than this, but for the sake of clarity let's say the ODE is y'(x) = (y+a)*x with y(0) = 0 and I want y(1). I picked the dverk algorithm from netlib for solving the ODE and it expects the function on the right hand side to be of a certain form. Now what I did with the Intel Fortran compiler is the following (simplified):
subroutine f(x,a,ans)
implicite none
double precision f,a,ans,y,tol,c(24),w(9)
...
call dverk(1,faux,x,y,1.d0,tol,ind,c,1,w)
...
contains
subroutine faux(n,xx,yy,yprime)
implicite none
integer n
double precision xx,yy(n),yprime(n)
yprime(1) = (yy(1)+a)*xx
end subroutine faux
end subroutine f
This works just fine with ifort, the sub-subroutine faux sees the parameter a and everything works as expected. But I'd like the code to be compatible with gfortran, and with this compiler I get the following error message:
Error: Internal procedure 'faux' is not allowed as an actual argument at (1)
I need to have the faux routine inside f, or else I don't know how to tell it the value of a, because I can't change the list of parameters, since this is what the dverk routine expects.
I would like to keep the dverk routine and understand how to solve this specific problem without a workaround, since I feel it will become important again when I need to integrate a parameterized function with different integrators.
You could put this all in a module, and make a a global module variable. Make faux a module procedure. That way, it has access to a.
module ode_module
double precision::a
contains
subroutine f(x,a,ans)
implicit none
double precision f,ans,y,tol,c(24),w(9)
call dverk(1,faux,x,y,1.d0,tol,ind,c,1,w)
end subroutine
subroutine faux(n,xx,yy,yprime)
implicite none
integer n
double precision xx,yy(n),yprime(n)
yprime(1) = (yy(1)+a)*xx
end subroutine faux
end module
You can check here which compilers support this F2008 feature:
http://fortranwiki.org/fortran/show/Fortran+2008+status
On that page, search for "Internal procedure as an actual argument" .
Passing an internal procedure is allowed by Fortran 2008. That means that your code is correct Fortran and just a more recent compiler is needed.
At the time when this question was posted the support for that in existing compilers was patchy. Some did support it, some did not. This changed considerably and at the time of writing this revision of the answer one can normally use it without needing to think about compiler support any more.
You are not limited to sharing the data in a module. You just have to make sure, that the containing procedure is still running. It is not possible to save the pointer and make a so called 'closure' known from LISP and many modern languages. In languages like Fortran or C the enclosing environment for future calls is not saved and pointers to internal functions become invalid.
The advantage of internal procedure over module procedure is that you can share the data without sharing it in the whole module.
It works well will reasonably old versions of GCC (gfortran), Intel Fortran and Cray Fortran (personally tested) and possibly others. I remember not being able to compile by PGI and Oracle Fortran. As shown by Daniel, it can be checked at http://fortranwiki.org/fortran/show/Fortran+2008+status (search Internal procedure as an actual argument). The most recent version of this table is periodically published in ACM SIGPLAN Fortran Forum.
There is some interesting info in this article https://stevelionel.com/drfortran/2009/09/02/doctor-fortran-in-think-thank-thunk/
Be aware that the implementation of this feature normally requires executable stack due to the use of trampolines. One does not normally think about that but if the OS forbids executable stack, the executable might fail (there were issues in initial versions of Windows Subsystem for Linux, for example).