Input :
<img xlink:href="figure_one"><?isoimg-id 9324-098_kr1figure1.JPG?></img>
I want to filter out as .jpg part from above input using XSLT. I have no idea to how can I filter out it.
You could simply remove the file extension (regardless of what it is) by using the substring-before() function:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="processing-instruction('isoimg-id')">
<xsl:processing-instruction name="isoimg-id">
<xsl:value-of select="substring-before(., '.')" />
</xsl:processing-instruction>
</xsl:template>
</xsl:stylesheet>
Related
I have a requirement to transform below XML
<XML>
<Obj1 attr1="value1" attr2="value2" attr="10"/>
<Test1 tatt1="tvalue1" tatt2="tvalue2" attr="10"/>
<Obj1 attr1="value11" attr2="value21" attr="101"/>
<Test1 tatt1="tvalue11" tatt2="tvalue21" attr="101"/>
<Obj1 attr1="value12" attr2="value22" attr="102"/>
<Test1 tatt1="tvalue12" tatt2="tvalue22" attr="102"/>
</XML>
I want transformed XML like
<XML>
<Obj1 attr1="value1" attr2="value2" attr="10" tatt1="tvalue1"/>
<Obj1 attr1="value11" attr2="value21" attr="101" tatt1="tvalue11"/>
<Obj1 attr1="value12" attr2="value22" attr="102" tatt1="tvalue12"/>
</XML>
I have achieved it through normal pattern matching and finding the matching attribute value in all other elements. I doubt about the performance. So wanted to check if it can be done using group-by attribute name and combining attributes from all such elements into one.
I want to merge contents (all attributes of Obj1 and selected attributes from matching elements) of all matching elements having attr= into transformed XML.
Try this XSLT-1.0 stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="xml" indent="yes"/>
<xsl:key name="tests" match="Test1" use="#attr" />
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()"> <!-- Identity template: copies all nodes to the output - unless a more specific template matches -->
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Obj1"> <!-- Modifies all 'Obj1' elements -->
<xsl:copy>
<xsl:copy-of select="#*|key('tests',#attr)/#tatt1" />
</xsl:copy>
</xsl:template>
<xsl:template match="Test1" /> <!-- Removes all 'Test1' elements from the output -->
</xsl:stylesheet>
The output should be as desired. And the use of the xsl:key will improve the performance.
AFAICT, you could so simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/XML">
<xsl:copy>
<xsl:for-each select="Obj1">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:copy-of select="following-sibling::Test1[1]/#tatt1"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you want do it by matching the value of the attr attribute instead of by position, then it would become:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:key name="test" match="Test1" use="#attr"/>
<xsl:template match="/XML">
<xsl:copy>
<xsl:for-each select="Obj1">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:copy-of select="key('test', #attr)/#tatt1"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I am completely clueless trying to change the value of card number for all records to 0 (zero)
The default transform file looks like the following:
<?xml version ="1.0" encoding="utf8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<!-- Parameters assigned at runtime. -->
<xsl:param name="paramCurrentTimestamp">20001231173010</xsl:param>
<xsl:param name="paramCurrentDT" >12/31/2000 5:30:10 PM</xsl:param>
<xsl:param name="paramCurrentCulture">en-US</xsl:param>
<!-- The transformation below provides trivial default copy of everything. -->
<xsl:template match="*|#*">
<xsl:copy>
<xsl:apply-templates select="*|#*|text()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*">
<xsl:copy />
</xsl:template>
<!-- End of customizable area. -->
</xsl:stylesheet>
The sample data input looks like:
Sample input
-<CrossFire culture-info=" en-US" platform-version=" 2.60.18" product-version=" 2.60.18">
-<SoftwareHouse.NextGen.Common.SecurityObjects.Personnel ImportMode=" Default">
<GUID>e7d37b37-9418-4e20-a6b7-f54b76c389cd</GUID>
-<SoftwareHouse.NextGen.Common.SecurityObjects.Credential ImportMode=" Default">
<GUID>e3adb09c-fb8e-4277-90d8-1839dd1bd83b</GUID>
<CardNumber>210316</CardNumber>
</SoftwareHouse.NextGen.Common.SecurityObjects.Credential>
</SoftwareHouse.NextGen.Common.SecurityObjects.Personnel>
</CrossFire>
What I want to see for all of the records is 0
In order to change the value of CardNumber to 0 while keeping everything else as is, you can do simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="CardNumber">
<xsl:copy>0</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I want to remove specific values from my XML but keep the tag names. I've seen examples that do the opposite (remove tags but keep values). Here is my XML:
<Result>
<Max>100</Max>
<Min>10</Min>
<Range>90</Range>
<ResultPoints>
<ResultP1>.</ResultP1>
<ResultP2>.</ResultP2>
<ResultP3>.</ResultP3>
<ResultP4>.</ResultP4>
<ResultP5>.</ResultP5>
</ResultPoints>
</Result>
I want to remove the '.' but keep the tag names so my XML will look like this:
<Result>
<Max>100</Max>
<Min>10</Min>
<Range>90</Range>
<ResultPoints>
<ResultP1/>
<ResultP2/>
<ResultP3/>
<ResultP4/>
<ResultP5/>
</ResultPoints>
</Result>
Here is my XLT. This completely removes the ResultPn tags.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[. = '.']">
<xsl:value-of select="''"/>
</xsl:template>
</xsl:stylesheet>
Any Help will be appreciated!
You just need to do an xsl:copy in your template, to copy across the element you have matched. Note you don't really need to output an empty string here either.
Try this XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[. = '.']">
<xsl:copy>
<xsl:apply-templates select="#*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note, I added an xsl:apply-templates to copy across any existing attributes.
Alternatively, you could replace the second template with this one instead (which matches the text node directly, rather than the parent element)
<xsl:template match="text()[. = '.']" />
Is there any way on how to convert a string to binary base64? I've seen many references but it didn't work in my end. For example I have this input file:
<RootElement xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Data>
<Binary>
<RawData>This element should convert string to binary base64.</RawData>
</Binary>
</Data>
</RootElement>
I need to generate:
<RootElement xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Data>
<Binary>
<RawData>VGhpcyBlbGVtZW50IHNob3VsZCBjb252ZXJ0IHN0cmluZyB0byBiaW5hcnkgYmFzZTY0Lg==</RawData>
</Binary>
</Data>
I created an xslt and used the namespace I've seen online:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dp="http://www.datapower.com/extensions">
<xsl:output method="xml" version="1.0" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="RawData">
<xsl:element name="RawData">
<xsl:value-of select="dp:encode(., 'base-64')"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Thank you.
There is a pure XSLT 1.0 solution that works for any XSLT processor: JAXP, Saxon, Xalan, Xsltproc, Microsoft:
Download base64.xsl
Download base64_binarydatamap.xml
Use XSLT 1.0:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:b64="https://github.com/ilyakharlamov/xslt_base64">
<xsl:output method="xml"/>
<xsl:include href="base64.xsl"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="/RootElement/Data/Binary/RawData">
<xsl:call-template name="b64:encode">
<xsl:with-param name="asciiString" select="text()"/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
I'm trying to bound the value of an xml attribute using xslt/xpath 1.0. In this example, it would be the id attribute on the m_m element.
<blart>
<m_data>
<m_m name="arggg" id="99999999" subs="asas"/>
</m_data>
<m_data>
<m_m name="arggg" id="99" subs="asas"/>
</m_data>
</blart>
If the id is greater then 20000 it gets set to 20000. I have the following xslt. I know it selects the correct node and attribute. It obviously is just outputing 20000. I realize I should have some sort of xpath logic in there but I'm having a hard time developing it. I have some big holes in my knowledge of xpath and xslt. If you can point me in the right direction in helping me understand on what I should be doing I would really appreciate it.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match ="m_data/m_m/#id[.> 20000]">20000 </xsl:template>
</xsl:stylesheet>
The expected output would be
<blart>
<m_data>
<m_m name="arggg" id="20000" subs="asas"/>
</m_data>
<m_data>
<m_m name="arggg" id="99" subs="asas"/>
</m_data>
</blart>
You can use the following XSLT that gives flexibility to the attribute you want to change, and keeps everything else as it is:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match ="m_data/m_m/#id[. > 20000]">
<xsl:attribute name="id">20000</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
Why don't you try:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match ="m_m/#id[. > 20000]">
<xsl:attribute name="id">20000</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
NOTE: Since I posted this, much better answers were contributed (see here and here). SO won't let me delete this one because it was accepted, but in all fairness and for the sake of quality, I should encourage you to upvote the two aforementioned answers, so that they stand out over this one.
How about this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="m_m">
<m_m>
<xsl:copy-of select="#*" />
<xsl:if test="#id > 20000">
<xsl:attribute name="id">20000</xsl:attribute>
</xsl:if>
</m_m>
</xsl:template>
<xsl:template match="m_data">
<m_data>
<xsl:apply-templates select="m_m" />
</m_data>
</xsl:template>
<xsl:template match="/blart">
<blart>
<xsl:apply-templates select="m_data" />
</blart>
</xsl:template>
</xsl:stylesheet>