Return all codes - String - c++

Question

Assume that the value of a = 1, b = 2, c = 3, ... , z = 26. You are given a numeric string S. Write a program to return the list of all possible codes that can be generated from the given string.
For most of the cases this code works but it gives wrong output for inputs which have numbers greater than 26. For eg: 12345.
#include <iostream>
#include <string.h>
using namespace std;
using namespace std;
int atoi(char a)
{
int i=a-'0';
return i;
}
char itoa(int i)
{
char c='a'+i-1;
return c;
}
int getCodes(string input, string output[10000]) {
if(input.size()==0)
{
return 1;
}
if(input.size()==1)
{
output[0]=output[0]+itoa(atoi(input[0]));
return 1;
}
string result1[10000],result2[10000];
int size2;
int size1=getCodes(input.substr(1),result1);
if(input.size()>1)
{
if(atoi(input[0])*10+atoi(input[1])>10&&atoi(input[0])*10+atoi(input[1])<27)
{
size2=getCodes(input.substr(2),result2);
}
}
for(int i=0;i<size1;i++)
{
output[i]=itoa(atoi(input[0]))+result1[i];
}
for(int i=0;i<size2;i++)
{
output[i+size1]=itoa(atoi(input[0])*10+atoi(input[1]))+result2[i];
}
return size1+size2;
}
int main(){
string input;
cin >> input;
string output[10000];
int count = getCodes(input, output);
for(int i = 0; i < count && i < 10000; i++)
cout << output[i] << endl;
return 0;
}
if i give input 12345, the output is:
"
abcde
awde
lcde
l"
instead of :
"
abcde
awde
lcde"

Answer 1

i got it fellow members. i did not initialised the size2 variable to zero. also i didn't use >= operator.
int getCodes(string input, string output[10000]) {
if(input.size()==0)
{
output[0]="";
return 1;
}
if(input.size()==1)
{
output[0]=itoa(atoi(input[0]));
return 1;
}
string result1[10000],result2[10000];
int size2=0;
int size1=getCodes(input.substr(1),result1);
if(input.size()>1)
{
if(atoi(input[0])*10+atoi(input[1])>=10&&atoi(input[0])*10+atoi(input[1])<27)
{
size2=getCodes(input.substr(2),result2);
}
}
int k=0;
for(int i=0;i<size1;i++)
{
output[k++]=itoa(atoi(input[0]))+result1[i];
}
for(int i=0;i<size2;i++)
{
output[k++]=itoa(atoi(input[0])*10+atoi(input[1]))+result2[i];
}
return k;
}
this is the final code for getCodes function. Thanks everyone :)

Answer 2

You can do that more simply with something like this:
#include <utility>
#include <string>
#include <vector>
#include <iostream>
using namespace std;
void getCodesRec(unsigned int num, string& current, vector<string>& result)
{
// First and last chars for the codes
static constexpr char FIRST_CHAR = 'a';
static constexpr char LAST_CHAR = 'z';
if (num == 0)
{
// When there is no more number add the code to the results
result.push_back(current);
}
else
{
// Add chars to the existing code
unsigned int next = num;
unsigned int rem = next % 10;
unsigned int f = 1;
// While we have not gone over the max char number
// (in practice this loop will run twice at most for a-z letters)
while (next > 0 && rem <= (unsigned int)(LAST_CHAR - FIRST_CHAR) + 1)
{
next = next / 10;
if (rem != 0) // 0 does not have a replacement
{
// Add the corresponding char
current.insert(0, 1, FIRST_CHAR + char(rem - 1));
// Recursive call
getCodesRec(next, current, result);
// Remove the char
current.erase(0, 1);
}
// Add another number
f *= 10;
rem += f * (next % 10);
}
}
}
vector<string> getCodes(unsigned int num)
{
vector<string> result;
string current;
getCodesRec(num, current, result);
return result;
}
int main()
{
unsigned int num = 12345;
vector<string> codes = getCodes(12345);
cout << "Codes for " << num << endl;
for (string& code : codes)
{
cout << "* " << code << endl;
}
return 0;
}
Output:
Codes for 12345
* abcde
* lcde
* awde