Copy/paste value of preceding element using XLST - xslt

Question

I have the following XML:
<?xml version="1.0"?>
<mysqldump xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<database name="ims_prod">
<table_data name="wp_trp_dictionary_en_us_de_de">
<row>
<field name="id">1</field>
<field name="original">Random text 1</field>
<field name="translated"></field>
<field name="status">0</field>
<field name="block_type">0</field>
</row>
<row>
<field name="id">2</field>
<field name="original">Random text 2</field>
<field name="translated"></field>
<field name="status">0</field>
<field name="block_type">0</field>
</row>
</table_data>
</database>
</mysqldump>
I need to copy the value of every node that has "original" attribute and paste it into the following sibling (sibling that has "translated" attribute.
Expected:
<?xml version="1.0"?>
<mysqldump xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<database name="ims_prod">
<table_data name="wp_trp_dictionary_en_us_de_de">
<row>
<field name="id">1</field>
<field name="original">Random text 1</field>
<field name="translated">**Random text 1**</field>
<field name="status">0</field>
<field name="block_type">0</field>
</row>
<row>
<field name="id">2</field>
<field name="original">Random text 2</field>
<field name="translated">**Random text 2**</field>
<field name="status">0</field>
<field name="block_type">0</field>
</row>
</table_data>
</database>
</mysqldump>
I've tried the following XSLT:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:com="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//table_data/row/field[#name='original']/text()">
<xsl:value-of select="//table_data/row/field[#name='original']/following-sibling::field[#name='translated']"/>
</xsl:template>
</xsl:stylesheet>
But it blanks out all nodes with "original" attributes instead.
What am I doing wrong? Thank you for your help!

Answer 1

You want to change the value of the translated field, so you need to make your template match that. And if the field is empty, then matching its text node will not work.
Try instead:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="field[#name='translated']">
<field name="translated">
<xsl:value-of select="preceding-sibling::field[#name='original']"/>
</field>
</xsl:template>
</xsl:stylesheet>
P.S. Note the use of relative path in select="preceding-sibling::field[#name='original']". Your version would always select the first row's original.

Answer 2

You can use these templates to get your desired outcome:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:com="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="table_data/row/field[#name='translated']">
<xsl:copy>
<xsl:copy-of select="#*" />
<xsl:value-of select="concat('**',preceding-sibling::field[1]/text(),'**')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
The output is as expected.