App works with ModelChoiceField but does not work with ModelMultipleChoiceField - django

I am trying to retrieve user input data in a django page. But I am unable to choose to multichoice field. I have tried multiple alternatives to no relief.
self.fields['site'].queryset=forms.ModelMultipleChoiceField(queryset=sites.objects.all())
self.fields['site'] = forms.ModelChoiceField(queryset=sites.objects.filter(project_id=project_id))
self.fields['site'].queryset = forms.MultipleChoiceField(widget=forms.SelectMultiple, choices=[(p.id, str(p)) for p in sites.objects.filter(project_id=project_id)])
forms.py
class SearchForm(forms.Form):
class Meta:
model= images
fields=['site']
def __init__(self,*args,**kwargs):
project_id = kwargs.pop("project_id") # client is the parameter passed from views.py
super(SearchForm, self).__init__(*args,**kwargs)
self.fields['site'] = forms.ModelChoiceField(queryset=sites.objects.filter(project_id=project_id))
views.py
def site_list(request, project_id):
form = SearchForm(project_id=project_id)
site_list = sites.objects.filter(project__pk=project_id).annotate(num_images=Count('images'))
template = loader.get_template('uvdata/sites.html')
if request.method == "POST":
image_list=[]
form=SearchForm(request.POST,project_id=project_id)
#form=SearchForm(request.POST)
#site_name=request.POST.get('site')
if form.is_valid():
site_name=form.cleaned_data.get('site')
print(site_name)
I expect to get a multiselect field but I end up getting this error:
Exception Value:
'site'
Exception Location: /home/clyde/Downloads/new/automatic_annotator_tool/django_app/search/forms.py in init, line 18
(line 18:self.fields['site'].queryset = forms.MultipleChoiceField(widget=forms.SelectMultiple, choices=[(p.id, str(p)) for p in sites.objects.filter(project_id=project_id)]))

You are not defining your form correctly. The documentation shows you how to do this.
In your case it would be something like this:
class SearchForm(forms.Form):
site = forms.ModelMultipleChoiceField(queryset=Sites.object.none())
def __init__(self,*args,**kwargs):
project_id = kwargs.pop("project_id")
super(SearchForm, self).__init__(*args,**kwargs)
self.fields['site'].queryset = Sites.objects.filter(project_id=project_id))
You also appear to be confusing regular Form and ModelForm, as Meta.model is only used in ModelForm whereas you are using a regular Form. I suggest you read up on the difference in the documentation before you proceed.

Related

Looking for format for KeywordsField.save_form_data

I have a Mezzanine Project and am trying to update the keywords on a blog entry. I am having difficulty getting the format correct to call KeywordsField.save_form_data this invokes a js that will update the keywords on a blog post. See below:
From Messanine/generic/fields.py
class KeywordsField(BaseGenericRelation):
"""
Stores the keywords as a single string into the
``KEYWORDS_FIELD_NAME_string`` field for convenient access when
searching.
"""
default_related_model = "generic.AssignedKeyword"
fields = {"%s_string": CharField(editable=False, blank=True,
max_length=500)}
def __init__(self, *args, **kwargs):
"""
Mark the field as editable so that it can be specified in
admin class fieldsets and pass validation, and also so that
it shows up in the admin form.
"""
super(KeywordsField, self).__init__(*args, **kwargs)
self.editable = True
def formfield(self, **kwargs):
"""
Provide the custom form widget for the admin, since there
isn't a form field mapped to ``GenericRelation`` model fields.
"""
from mezzanine.generic.forms import KeywordsWidget
kwargs["widget"] = KeywordsWidget
return super(KeywordsField, self).formfield(**kwargs)
def save_form_data(self, instance, data):
"""
The ``KeywordsWidget`` field will return data as a string of
comma separated IDs for the ``Keyword`` model - convert these
into actual ``AssignedKeyword`` instances. Also delete
``Keyword`` instances if their last related ``AssignedKeyword``
instance is being removed.
"""
from mezzanine.generic.models import Keyword
related_manager = getattr(instance, self.name)
# Get a list of Keyword IDs being removed.
old_ids = [str(a.keyword_id) for a in related_manager.all()]
new_ids = data.split(",")
removed_ids = set(old_ids) - set(new_ids)
# Remove current AssignedKeyword instances.
related_manager.all().delete()
# Convert the data into AssignedKeyword instances.
if data:
data = [related_manager.create(keyword_id=i) for i in new_ids]
# Remove keywords that are no longer assigned to anything.
Keyword.objects.delete_unused(removed_ids)
super(KeywordsField, self).save_form_data(instance, data)
From my Views.py
class PubForm(forms.ModelForm):
class Meta:
model = BlogPost
fields = ['keywords']
def UpdatePub(request, slug):
blog_post = BlogPost.objects.get(id=slug)
if request.method == 'POST':
form = PubForm(request.POST)
if form.is_valid():
publish_date = datetime.datetime.now()
blog_post.status = CONTENT_STATUS_PUBLISHED
publish_date=publish_date
tags=form.cleaned_data['keywords']
blog_post.save()
KeywordsField.save_form_data(user,blog_post,tags)
return HttpResponseRedirect('/write/')
else:
form = PubForm(instance=blog_post)
return render(request, 'blog_my_pub.html', {'form' : form})
It complains that the field 'user' has no attribute 'name'. I have tried many different values for this parameter and cannot figure it out. Any help would be appreciated.
Thanks for any input.

Filter foreignkey select options on a form based on an object id passed by a view

In my project I need to filter foreign key select options on a form. I can do that passing a parameter to the __init__ method of the form like so:
class ResultadoForm(forms.ModelForm):
frequencia = forms.CharField(max_length=50)
tolerancia = forms.CharField(max_length=255)
def __init__(self, equipamento_id, *args, **kwargs):
equipamento_id = kwargs.pop('equipamento_id')
super (ResultadoForm, self ).__init__(*args, **kwargs)
self.fields['teste'].queryset = Teste.objects.filter(equipamento=equipamento_id)
class Meta:
model = Resultado
exclude = ['actividade']
In the view all I have to do is:
form1 = ResultadoForm(equipamento_id)
The problem is I am unable to pass the parameter equipamento_id to an inlineformset_factory:
form1 = inlineformset_factory(Actividade, Resultado, form=ResultadoForm(equipamento_id), exclude=('actividade',), extra=len(testes_list))
This raises an error. How can I pass the parameter equipamento_id to an inlineformset_factory in order to be able to filter the foreignkey options?
If you are using django 1.9 you could use form_kwargs to pass the data:
FormSet1 = inlineformset_factory(Actividade,
Resultado,
form=ResultadoForm,
exclude=('actividade',),
extra=len(testes_list))
formset = FormSet1(form_kwargs={'equipamento_id': equipamento_id})
django doc about form_kwargs.

ModelChoiceField in forms.Form won't validate if queryset is overridden

I have a django ModelChoiceField that won't validate if I override the queryset.
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
form = PersonalNote()
form.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)
The form.is_valid() error is: "Select a valid choice. That choice is not one of the available choices".
If Tile.objects.none() is replaced with Tile.objects.all() it validates, but loads far too much data from the database. I've also tried:
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
def __init__(self, *args, **kwargs):
yyy = kwargs.pop('yyy', None)
super(PersonalNote, self).__init__(*args, **kwargs)
if yyy:
self.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)
What might be wrong here? Note the real application also overrides the label, but that does not seem to be a factor here:
class ModelChoiceField2(forms.ModelChoiceField):
def label_from_instance(self, obj):
assert isinstance(obj,Tile)
return obj.child_title()
After 2 hours I found the solution. Because you specified a queryset of none in the class definition, when you instantiate that PersonalNote(request.POST) to be validated it is referenceing a null query set
class PersonalNote(forms.Form):
tile = ModelChoiceField(queryset=Tile.objects.none())
note = forms.CharField()
To fix this, when you create your form based on a POST request be sure to overwrite your queryset AGAIN before you check is_valid()
def some_view_def(request):
form = PersonalNote(request.POST)
**form.fields['tile'].queryset = Tile.objects.filter(section__xxx=yyy)**
if form.is_valid():
#Do whatever it is
When you pass an empty queryset to ModelChoiceField you're saying that nothing will be valid for that field. Perhaps you could filter the queryset so there aren't too many options.
I also had this problem. The idea is to dynamically change the queryset of a ModelChoiceField based on a condition (in my case it was a filter made by another ModelChoiceField).
So, having the next model as example:
class FilterModel(models.Model):
name = models.CharField()
class FooModel(models.Model):
filter_field = models.ForeignKey(FilterModel)
name = models.CharField()
class MyModel(models.Model):
foo_field = models.ForeignKey(FooModel)
As you can see, MyModel has a foreign key with FooModel, but not with FilterModel. So, in order to filter the FooModel options, I added a new ModelChoiceField on my form:
class MyForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
# your code here
self.fields['my_filter_field'] = forms.ModelChoiceField(FilterModel, initial=my_filter_field_selected)
self.fields['my_filter_field'].queryset = FilterModel.objects.all()
Then, on your Front-End you can use Ajax to load the options of foo_field, based on the selected value of my_filter_field. At this point everyting should be working. But, when the form is loaded, it will bring all the posible options from FooModel. To avoid this, you need to dynamically change the queryset of foo_field.
On my form view, I passed a new argument to MyForm:
id_filter_field = request.POST.get('my_filter_field', None)
form = MyForm(data=request.POST, id_filter_field=id_filter_field)
Now, you can use that argument on MyForm to change the queryset:
class MyForm(forms.ModelForm):
# your code here
def __init__(self, *args, **kwargs):
self.id_filter_field = kwargs.pop('id_filter_field', None)
# your code here
if self.id_filter_field:
self.fields['foo_field'].queryset = FooModel.objects.filter(filter_field_id=self.id_filter_field)
else:
self.fields['foo_field'].queryset = FooModel.objects.none()

get_readonly_fields in a TabularInline class in Django?

I'm trying to use get_readonly_fields in a TabularInline class in Django:
class ItemInline(admin.TabularInline):
model = Item
extra = 5
def get_readonly_fields(self, request, obj=None):
if obj:
return ['name']
return self.readonly_fields
This code was taken from another StackOverflow question:
Django admin site: prevent fields from being edited?
However, when it's put in a TabularInline class, the new object forms don't render properly. The goal is to make certain fields read only while still allowing data to be entered in new objects. Any ideas for a workaround or different strategy?
Careful - "obj" is not the inline object, it's the parent. That's arguably a bug - see for example this Django ticket
As a workaround to this issue I have associated a form and a Widget to my Inline:
admin.py:
...
class MasterCouponFileInline(admin.TabularInline):
model = MasterCouponFile
form = MasterCouponFileForm
extra = 0
in Django 2.0:
forms.py
from django import forms
from . import models
from feedback.widgets import DisablePopulatedText
class FeedbackCommentForm(forms.ModelForm):
class Meta:
model = models.MasterCouponFile
fields = ('Comment', ....)
widgets = {
'Comment': DisablePopulatedText,
}
in widgets.py
from django import forms
class DisablePopulatedText(forms.TextInput):
def render(self, name, value, attrs=None, renderer=None):
"""Render the widget as an HTML string."""
if value is not None:
# Just return the value, as normal read_only fields do
# Add Hidden Input otherwise the old fields are still required
HiddenInput = forms.HiddenInput()
return format_html("{}\n"+HiddenInput.render(name, value), self.format_value(value))
else:
return super().render(name, value, attrs, renderer)
older Django Versions:
forms.py
....
class MasterCouponFileForm(forms.ModelForm):
class Meta:
model = MasterCouponFile
def __init__(self, *args, **kwargs):
super(MasterCouponFileForm, self).__init__(*args, **kwargs)
self.fields['range'].widget = DisablePopulatedText(self.instance)
self.fields['quantity'].widget = DisablePopulatedText(self.instance)
in widgets.py
...
from django import forms
from django.forms.util import flatatt
from django.utils.encoding import force_text
class DisablePopulatedText(forms.TextInput):
def __init__(self, obj, attrs=None):
self.object = obj
super(DisablePopulatedText, self).__init__(attrs)
def render(self, name, value, attrs=None):
if value is None:
value = ''
final_attrs = self.build_attrs(attrs, type=self.input_type, name=name)
if value != '':
# Only add the 'value' attribute if a value is non-empty.
final_attrs['value'] = force_text(self._format_value(value))
if "__prefix__" not in name and not value:
return format_html('<input{0} disabled />', flatatt(final_attrs))
else:
return format_html('<input{0} />', flatatt(final_attrs))
This is still currently not easily doable due to the fact that obj is the parent model instance not the instance displayed by the inline.
What I did in order to solve this, was to make all the fields, in the inline form, read only and provide a Add/Edit link to a ChangeForm for the inlined model.
Like this
class ChangeFormLinkMixin(object):
def change_form_link(self, instance):
url = reverse('admin:%s_%s_change' % (instance._meta.app_label,
instance._meta.module_name), args=(instance.id,))
# Id == None implies and empty inline object
url = url.replace('None', 'add')
command = _('Add') if url.find('add') > -1 else _('Edit')
return format_html(u'%s' % command, url)
And then in the inline I will have something like this
class ItemInline(ChangeFormLinkMixin, admin.StackedInline):
model = Item
extra = 5
readonly_fields = ['field1',...,'fieldN','change_form_link']
Then in the ChangeForm I'll be able to control the changes the way I want to (I have several states, each of them with a set of editable fields associated).
As others have added, this is a design flaw in django as seen in this Django ticket (thanks Danny W). get_readonly_fields returns the parent object, which is not what we want here.
Since we can't make it readonly, here is my solution to validate it can't be set by the form, using a formset and a clean method:
class ItemInline(admin.TabularInline):
model = Item
formset = ItemInlineFormset
class ItemInlineFormset(forms.models.BaseInlineFormSet):
def clean(self):
super(ItemInlineFormset, self).clean()
for form in self.forms:
if form.instance.some_condition:
form.add_error('some_condition', 'Nope')
You are on the right track. Update self.readonly_fields with a tuple of what fields you want to set as readonly.
class ItemInline(admin.TabularInline):
model = Item
extra = 5
def get_readonly_fields(self, request, obj=None):
# add a tuple of readonly fields
self.readonly_fields += ('field_a', 'field_b')
return self.readonly_fields

In a Django form, how do I make a field readonly (or disabled) so that it cannot be edited?

In a Django form, how do I make a field read-only (or disabled)?
When the form is being used to create a new entry, all fields should be enabled - but when the record is in update mode some fields need to be read-only.
For example, when creating a new Item model, all fields must be editable, but while updating the record, is there a way to disable the sku field so that it is visible, but cannot be edited?
class Item(models.Model):
sku = models.CharField(max_length=50)
description = models.CharField(max_length=200)
added_by = models.ForeignKey(User)
class ItemForm(ModelForm):
class Meta:
model = Item
exclude = ('added_by')
def new_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Validate and save
else:
form = ItemForm()
# Render the view
Can class ItemForm be reused? What changes would be required in the ItemForm or Item model class? Would I need to write another class, "ItemUpdateForm", for updating the item?
def update_item_view(request):
if request.method == 'POST':
form = ItemUpdateForm(request.POST)
# Validate and save
else:
form = ItemUpdateForm()
As pointed out in this answer, Django 1.9 added the Field.disabled attribute:
The disabled boolean argument, when set to True, disables a form field using the disabled HTML attribute so that it won’t be editable by users. Even if a user tampers with the field’s value submitted to the server, it will be ignored in favor of the value from the form’s initial data.
With Django 1.8 and earlier, to disable entry on the widget and prevent malicious POST hacks you must scrub the input in addition to setting the readonly attribute on the form field:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.pk:
self.fields['sku'].widget.attrs['readonly'] = True
def clean_sku(self):
instance = getattr(self, 'instance', None)
  if instance and instance.pk:
    return instance.sku
  else:
    return self.cleaned_data['sku']
Or, replace if instance and instance.pk with another condition indicating you're editing. You could also set the attribute disabled on the input field, instead of readonly.
The clean_sku function will ensure that the readonly value won't be overridden by a POST.
Otherwise, there is no built-in Django form field which will render a value while rejecting bound input data. If this is what you desire, you should instead create a separate ModelForm that excludes the uneditable field(s), and just print them inside your template.
Django 1.9 added the Field.disabled attribute: https://docs.djangoproject.com/en/stable/ref/forms/fields/#disabled
The disabled boolean argument, when set to True, disables a form field using the disabled HTML attribute so that it won’t be editable by users. Even if a user tampers with the field’s value submitted to the server, it will be ignored in favor of the value from the form’s initial data.
Setting readonly on a widget only makes the input in the browser read-only. Adding a clean_sku which returns instance.sku ensures the field value will not change on form level.
def clean_sku(self):
if self.instance:
return self.instance.sku
else:
return self.fields['sku']
This way you can use model's (unmodified save) and avoid getting the field required error.
awalker's answer helped me a lot!
I've changed his example to work with Django 1.3, using get_readonly_fields.
Usually you should declare something like this in app/admin.py:
class ItemAdmin(admin.ModelAdmin):
...
readonly_fields = ('url',)
I've adapted in this way:
# In the admin.py file
class ItemAdmin(admin.ModelAdmin):
...
def get_readonly_fields(self, request, obj=None):
if obj:
return ['url']
else:
return []
And it works fine. Now if you add an Item, the url field is read-write, but on change it becomes read-only.
To make this work for a ForeignKey field, a few changes need to be made. Firstly, the SELECT HTML tag does not have the readonly attribute. We need to use disabled="disabled" instead. However, then the browser doesn't send any form data back for that field. So we need to set that field to not be required so that the field validates correctly. We then need to reset the value back to what it used to be so it's not set to blank.
So for foreign keys you will need to do something like:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].required = False
self.fields['sku'].widget.attrs['disabled'] = 'disabled'
def clean_sku(self):
# As shown in the above answer.
instance = getattr(self, 'instance', None)
if instance:
return instance.sku
else:
return self.cleaned_data.get('sku', None)
This way the browser won't let the user change the field, and will always POST as it it was left blank. We then override the clean method to set the field's value to be what was originally in the instance.
For Django 1.2+, you can override the field like so:
sku = forms.CharField(widget = forms.TextInput(attrs={'readonly':'readonly'}))
I made a MixIn class which you may inherit to be able to add a read_only iterable field which will disable and secure fields on the non-first edit:
(Based on Daniel's and Muhuk's answers)
from django import forms
from django.db.models.manager import Manager
# I used this instead of lambda expression after scope problems
def _get_cleaner(form, field):
def clean_field():
value = getattr(form.instance, field, None)
if issubclass(type(value), Manager):
value = value.all()
return value
return clean_field
class ROFormMixin(forms.BaseForm):
def __init__(self, *args, **kwargs):
super(ROFormMixin, self).__init__(*args, **kwargs)
if hasattr(self, "read_only"):
if self.instance and self.instance.pk:
for field in self.read_only:
self.fields[field].widget.attrs['readonly'] = "readonly"
setattr(self, "clean_" + field, _get_cleaner(self, field))
# Basic usage
class TestForm(AModelForm, ROFormMixin):
read_only = ('sku', 'an_other_field')
I ran across a similar problem.
It looks like I was able to solve it by defining a get_readonly_fields method in my ModelAdmin class.
Something like this:
# In the admin.py file
class ItemAdmin(admin.ModelAdmin):
def get_readonly_display(self, request, obj=None):
if obj:
return ['sku']
else:
return []
The nice thing is that obj will be None when you are adding a new Item, or it will be the object being edited when you are changing an existing Item.
get_readonly_display is documented here.
I've just created the simplest possible widget for a readonly field - I don't really see why forms don't have this already:
class ReadOnlyWidget(widgets.Widget):
"""Some of these values are read only - just a bit of text..."""
def render(self, _, value, attrs=None):
return value
In the form:
my_read_only = CharField(widget=ReadOnlyWidget())
Very simple - and gets me just output. Handy in a formset with a bunch of read only values.
Of course - you could also be a bit more clever and give it a div with the attrs so you can append classes to it.
For django 1.9+
You can use Fields disabled argument to make field disable.
e.g. In following code snippet from forms.py file , I have made employee_code field disabled
class EmployeeForm(forms.ModelForm):
employee_code = forms.CharField(disabled=True)
class Meta:
model = Employee
fields = ('employee_code', 'designation', 'salary')
Reference
https://docs.djangoproject.com/en/dev/ref/forms/fields/#disabled
How I do it with Django 1.11 :
class ItemForm(ModelForm):
disabled_fields = ('added_by',)
class Meta:
model = Item
fields = '__all__'
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
for field in self.disabled_fields:
self.fields[field].disabled = True
One simple option is to just type form.instance.fieldName in the template instead of form.fieldName.
You can elegantly add readonly in the widget:
class SurveyModaForm(forms.ModelForm):
class Meta:
model = Survey
fields = ['question_no']
widgets = {
'question_no':forms.NumberInput(attrs={'class':'form-control','readonly':True}),
}
Yet again, I am going to offer one more solution :) I was using Humphrey's code, so this is based off of that.
However, I ran into issues with the field being a ModelChoiceField. Everything would work on the first request. However, if the formset tried to add a new item and failed validation, something was going wrong with the "existing" forms where the SELECTED option was being reset to the default ---------.
Anyway, I couldn't figure out how to fix that. So instead, (and I think this is actually cleaner in the form), I made the fields HiddenInputField(). This just means you have to do a little more work in the template.
So the fix for me was to simplify the Form:
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].widget=HiddenInput()
And then in the template, you'll need to do some manual looping of the formset.
So, in this case you would do something like this in the template:
<div>
{{ form.instance.sku }} <!-- This prints the value -->
{{ form }} <!-- Prints form normally, and makes the hidden input -->
</div>
This worked a little better for me and with less form manipulation.
I was going into the same problem so I created a Mixin that seems to work for my use cases.
class ReadOnlyFieldsMixin(object):
readonly_fields =()
def __init__(self, *args, **kwargs):
super(ReadOnlyFieldsMixin, self).__init__(*args, **kwargs)
for field in (field for name, field in self.fields.iteritems() if name in self.readonly_fields):
field.widget.attrs['disabled'] = 'true'
field.required = False
def clean(self):
cleaned_data = super(ReadOnlyFieldsMixin,self).clean()
for field in self.readonly_fields:
cleaned_data[field] = getattr(self.instance, field)
return cleaned_data
Usage, just define which ones must be read only:
class MyFormWithReadOnlyFields(ReadOnlyFieldsMixin, MyForm):
readonly_fields = ('field1', 'field2', 'fieldx')
As a useful addition to Humphrey's post, I had some issues with django-reversion, because it still registered disabled fields as 'changed'. The following code fixes the problem.
class ItemForm(ModelForm):
def __init__(self, *args, **kwargs):
super(ItemForm, self).__init__(*args, **kwargs)
instance = getattr(self, 'instance', None)
if instance and instance.id:
self.fields['sku'].required = False
self.fields['sku'].widget.attrs['disabled'] = 'disabled'
def clean_sku(self):
# As shown in the above answer.
instance = getattr(self, 'instance', None)
if instance:
try:
self.changed_data.remove('sku')
except ValueError, e:
pass
return instance.sku
else:
return self.cleaned_data.get('sku', None)
As I can't yet comment (muhuk's solution), I'll response as a separate answer. This is a complete code example, that worked for me:
def clean_sku(self):
if self.instance and self.instance.pk:
return self.instance.sku
else:
return self.cleaned_data['sku']
Based on Yamikep's answer, I found a better and very simple solution which also handles ModelMultipleChoiceField fields.
Removing field from form.cleaned_data prevents fields from being saved:
class ReadOnlyFieldsMixin(object):
readonly_fields = ()
def __init__(self, *args, **kwargs):
super(ReadOnlyFieldsMixin, self).__init__(*args, **kwargs)
for field in (field for name, field in self.fields.iteritems() if
name in self.readonly_fields):
field.widget.attrs['disabled'] = 'true'
field.required = False
def clean(self):
for f in self.readonly_fields:
self.cleaned_data.pop(f, None)
return super(ReadOnlyFieldsMixin, self).clean()
Usage:
class MyFormWithReadOnlyFields(ReadOnlyFieldsMixin, MyForm):
readonly_fields = ('field1', 'field2', 'fieldx')
if your need multiple read-only fields.you can use any of methods given below
method 1
class ItemForm(ModelForm):
readonly = ('sku',)
def __init__(self, *arg, **kwrg):
super(ItemForm, self).__init__(*arg, **kwrg)
for x in self.readonly:
self.fields[x].widget.attrs['disabled'] = 'disabled'
def clean(self):
data = super(ItemForm, self).clean()
for x in self.readonly:
data[x] = getattr(self.instance, x)
return data
method 2
inheritance method
class AdvancedModelForm(ModelForm):
def __init__(self, *arg, **kwrg):
super(AdvancedModelForm, self).__init__(*arg, **kwrg)
if hasattr(self, 'readonly'):
for x in self.readonly:
self.fields[x].widget.attrs['disabled'] = 'disabled'
def clean(self):
data = super(AdvancedModelForm, self).clean()
if hasattr(self, 'readonly'):
for x in self.readonly:
data[x] = getattr(self.instance, x)
return data
class ItemForm(AdvancedModelForm):
readonly = ('sku',)
Two more (similar) approaches with one generalized example:
1) first approach - removing field in save() method, e.g. (not tested ;) ):
def save(self, *args, **kwargs):
for fname in self.readonly_fields:
if fname in self.cleaned_data:
del self.cleaned_data[fname]
return super(<form-name>, self).save(*args,**kwargs)
2) second approach - reset field to initial value in clean method:
def clean_<fieldname>(self):
return self.initial[<fieldname>] # or getattr(self.instance, fieldname)
Based on second approach I generalized it like this:
from functools import partial
class <Form-name>(...):
def __init__(self, ...):
...
super(<Form-name>, self).__init__(*args, **kwargs)
...
for i, (fname, field) in enumerate(self.fields.iteritems()):
if fname in self.readonly_fields:
field.widget.attrs['readonly'] = "readonly"
field.required = False
# set clean method to reset value back
clean_method_name = "clean_%s" % fname
assert clean_method_name not in dir(self)
setattr(self, clean_method_name, partial(self._clean_for_readonly_field, fname=fname))
def _clean_for_readonly_field(self, fname):
""" will reset value to initial - nothing will be changed
needs to be added dynamically - partial, see init_fields
"""
return self.initial[fname] # or getattr(self.instance, fieldname)
For the Admin version, I think this is a more compact way if you have more than one field:
def get_readonly_fields(self, request, obj=None):
skips = ('sku', 'other_field')
fields = super(ItemAdmin, self).get_readonly_fields(request, obj)
if not obj:
return [field for field in fields if not field in skips]
return fields
Here is a slightly more involved version, based on christophe31's answer. It does not rely on the "readonly" attribute. This makes its problems, like select boxes still being changeable and datapickers still popping up, go away.
Instead, it wraps the form fields widget in a readonly widget, thus making the form still validate. The content of the original widget is displayed inside <span class="hidden"></span> tags. If the widget has a render_readonly() method it uses that as the visible text, otherwise it parses the HTML of the original widget and tries to guess the best representation.
import django.forms.widgets as f
import xml.etree.ElementTree as etree
from django.utils.safestring import mark_safe
def make_readonly(form):
"""
Makes all fields on the form readonly and prevents it from POST hacks.
"""
def _get_cleaner(_form, field):
def clean_field():
return getattr(_form.instance, field, None)
return clean_field
for field_name in form.fields.keys():
form.fields[field_name].widget = ReadOnlyWidget(
initial_widget=form.fields[field_name].widget)
setattr(form, "clean_" + field_name,
_get_cleaner(form, field_name))
form.is_readonly = True
class ReadOnlyWidget(f.Select):
"""
Renders the content of the initial widget in a hidden <span>. If the
initial widget has a ``render_readonly()`` method it uses that as display
text, otherwise it tries to guess by parsing the html of the initial widget.
"""
def __init__(self, initial_widget, *args, **kwargs):
self.initial_widget = initial_widget
super(ReadOnlyWidget, self).__init__(*args, **kwargs)
def render(self, *args, **kwargs):
def guess_readonly_text(original_content):
root = etree.fromstring("<span>%s</span>" % original_content)
for element in root:
if element.tag == 'input':
return element.get('value')
if element.tag == 'select':
for option in element:
if option.get('selected'):
return option.text
if element.tag == 'textarea':
return element.text
return "N/A"
original_content = self.initial_widget.render(*args, **kwargs)
try:
readonly_text = self.initial_widget.render_readonly(*args, **kwargs)
except AttributeError:
readonly_text = guess_readonly_text(original_content)
return mark_safe("""<span class="hidden">%s</span>%s""" % (
original_content, readonly_text))
# Usage example 1.
self.fields['my_field'].widget = ReadOnlyWidget(self.fields['my_field'].widget)
# Usage example 2.
form = MyForm()
make_readonly(form)
Today I encountered the exact same problem for a similar use case. However, I had to deal with a class-based views. Class-based views allow inheriting attributes and methods thus making it easier to reuse code in a neat manner.
I will answer your question by discussing the code needed for creating a profile page for users. On this page, they can update their personal information. However, I wanted to show an email field without allowing the user to change the information.
Yes, I could have just left out the email field but my OCD would not allow it.
In the example below I used a form class in combination with the disabled = True method. This code is tested on Django==2.2.7.
# form class in forms.py
# Alter import User if you have created your own User class with Django default as abstract class.
from .models import User
# from django.contrib.auth.models import User
# Same goes for these forms.
from django.contrib.auth.forms import UserCreationForm, UserChangeForm
class ProfileChangeForm(UserChangeForm):
class Meta(UserCreationForm)
model = User
fields = ['first_name', 'last_name', 'email',]
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self.fields['email'].disabled = True
As one can see, the needed user fields are specified. These are the fields that must be shown on the profile page. If other fields need to be added one has to specify them in the User class and add the attribute name to the fields list of the Meta class of this form.
After getting the required metadata the __init__ method is called initializing the form. However, within this method, the email field parameter 'disabled' is set to True. By doing so the behavior of the field in the front-end is altered resulting in a read-only field that one cannot edit even if one changes the HTML code. Reference Field.disabled
For completion, in the example below one can see the class-based views needed to use the form.
# view class in views.py
from django.contrib import messages
from django.contrib.messages.views import SuccessMessageMixin
from django.contrib.auth.mixins import LoginRequiredMixin
from django.views.generic import TemplateView, UpdateView
from django.utils.translation import gettext_lazy as _
class ProfileView(LoginRequiredMixin, TemplateView):
template_name = 'app_name/profile.html'
model = User
def get_context_data(self, **kwargs):
context = super().get_context_data(**kwargs)
context.update({'user': self.request.user, })
return context
class UserUpdateView(LoginRequiredMixin, SuccesMessageMixin, UpdateView):
template_name = 'app_name/update_profile.html'
model = User
form_class = ProfileChangeForm
success_message = _("Successfully updated your personal information")
def get_success_url(self):
# Please note, one has to specify a get_absolute_url() in the User class
# In my case I return: reverse("app_name:profile")
return self.request.user.get_absolute_url()
def get_object(self, **kwargs):
return self.request.user
def form_valid(self, form):
messages.add_message(self.request, messages.INFO, _("Successfully updated your profile"))
return super().form_valid(form)
The ProfileView class only shows an HTML page with some information about the user. Furthermore, it holds a button that if pressed leads to an HTML page configured by the UserUpdateView, namely 'app_name/update_profile.html'. As one can see, the UserUpdateView holds two extra attributes, namely 'form_class' and 'success_message'.
The view knows that every field on the page must be filled with data from the User model. However, by introducing the 'form_class' attribute the view does not get the default layout of the User fields. Instead, it is redirected to retrieve the fields through the form class. This has a huge advantage in the sense of flexibility.
By using form classes it is possible to show different fields with different restrictions for different users. If one sets the restrictions within the model itself every user would get the same treatment.
The template itself is not that spectacular but can be seen below.
# HTML template in 'templates/app_name/update_profile.html'
{% extends "base.html" %}
{% load static %}
{% load crispy_form_tags %}
{% block content %}
<h1>
Update your personal information
<h1/>
<div>
<form class="form-horizontal" method="post" action="{% url 'app_name:update' %}">
{% csrf_token %}
{{ form|crispy }}
<div class="btn-group">
<button type="submit" class="btn btn-primary">
Update
</button>
</div>
</div>
{% endblock %}
As can be seen, the form tag holds an action tag that holds the view URL routing.
After pressing the Update button the UserUpdateView gets activated and it validates if all conditions are met. If so, the form_valid method is triggered and adds a success message. After successfully updating the data the user is returned to the specified URL in the get_success_url method.
Below one can find the code allowing the URL routing for the views.
# URL routing for views in urls.py
from django.urls import path
from . import views
app_name = 'app_name'
urlpatterns = [
path('profile/', view=views.ProfileView.as_view(), name='profile'),
path('update/', view=views.UserUpdateView.as_view(), name='update'),
]
There you have it. A fully worked out implementation of class-based views using form so one can alter an email field to be read-only and disabled.
My apologies for the extremely detailed example. There might be more efficient ways to design the class-based views, but this should work. Of course, I might have been wrong about some things said. I'm still learning as well. If anyone has any comments or improvements let me know!
You can do it just like this:
Check if the request is update or save a new object.
If request is update then disable field sku.
If request is to add a new object then you must render the form with out disabling the field sku.
Here is an example of how to do like this.
class Item(models.Model):
sku = models.CharField(max_length=50)
description = models.CharField(max_length=200)
added_by = models.ForeignKey(User)
class ItemForm(ModelForm):
def disable_sku_field(self):
elf.fields['sku'].widget.attrs['readonly'] = True
class Meta:
model = Item
exclude = ('added_by')
def new_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Just create an object or instance of the form.
# Validate and save
else:
form = ItemForm()
# Render the view
def update_item_view(request):
if request.method == 'POST':
form = ItemForm(request.POST)
# Just create an object or instance of the form.
# Validate and save
else:
form = ItemForm()
form.disable_sku_field() # call the method that will disable field.
# Render the view with the form that will have the `sku` field disabled on it.
Is this the simplest way?
Right in a view code something like this:
def resume_edit(request, r_id):
.....
r = Resume.get.object(pk=r_id)
resume = ResumeModelForm(instance=r)
.....
resume.fields['email'].widget.attrs['readonly'] = True
.....
return render(request, 'resumes/resume.html', context)
It works fine!
If you are working with Django ver < 1.9 (the 1.9 has added Field.disabled attribute) you could try to add following decorator to your form __init__ method:
def bound_data_readonly(_, initial):
return initial
def to_python_readonly(field):
native_to_python = field.to_python
def to_python_filed(_):
return native_to_python(field.initial)
return to_python_filed
def disable_read_only_fields(init_method):
def init_wrapper(*args, **kwargs):
self = args[0]
init_method(*args, **kwargs)
for field in self.fields.values():
if field.widget.attrs.get('readonly', None):
field.widget.attrs['disabled'] = True
setattr(field, 'bound_data', bound_data_readonly)
setattr(field, 'to_python', to_python_readonly(field))
return init_wrapper
class YourForm(forms.ModelForm):
#disable_read_only_fields
def __init__(self, *args, **kwargs):
...
The main idea is that if field is readonly you don't need any other value except initial.
P.S: Don't forget to set yuor_form_field.widget.attrs['readonly'] = True
Start from disable fields mixin:
class ModelAllDisabledFormMixin(forms.ModelForm):
def __init__(self, *args, **kwargs):
'''
This mixin to ModelForm disables all fields. Useful to have detail view based on model
'''
super().__init__(*args, **kwargs)
form_fields = self.fields
for key in form_fields.keys():
form_fields[key].disabled = True
then:
class MyModelAllDisabledForm(ModelAllDisabledFormMixin, forms.ModelForm):
class Meta:
model = MyModel
fields = '__all__'
prepare view:
class MyModelDetailView(LoginRequiredMixin, UpdateView):
model = MyModel
template_name = 'my_model_detail.html'
form_class = MyModelAllDisabledForm
place this in my_model_detail.html template:
<div class="form">
<form method="POST" enctype="multipart/form-data">
{% csrf_token %}
{{ form | crispy }}
</form>
</div>
You will obtain same form as in update view but with all fields disabled.
Based on the answer from #paeduardo (which is overkill), you can disable a field in the form class initializer:
class RecordForm(ModelForm):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
var = self.fields['the_field']
var.disabled = True
If you are using Django admin, here is the simplest solution.
class ReadonlyFieldsMixin(object):
def get_readonly_fields(self, request, obj=None):
if obj:
return super(ReadonlyFieldsMixin, self).get_readonly_fields(request, obj)
else:
return tuple()
class MyAdmin(ReadonlyFieldsMixin, ModelAdmin):
readonly_fields = ('sku',)
I think your best option would just be to include the readonly attribute in your template rendered in a <span> or <p> rather than include it in the form if it's readonly.
Forms are for collecting data, not displaying it. That being said, the options to display in a readonly widget and scrub POST data are fine solutions.