I'm trying to create regex to retrieve last number if there was a number or any number if there wasn't any from a string.
Examples:
6 łyżek stopionego masła -> 6
5 łyżek blabla, 6 łyżek masła -> 6
5 łyżek mąki lub masła -> 5
I'm matching only on masła (changing variable) so it has to be included in regex
EDIT:
I cannot explain what I actually need:
Here is regex101 example: https://regex101.com/r/pEeRk3/1
EDIT2:
Emma's solution works great, but I would need to parse decimals and 2multiple digit numbers as well, meaning that those would match as well:
https://regex101.com/r/pEeRk3/3 - I added examples with answers in the link
If you want to match the last occurence of a digit with a decimal and you word has to follow this value, you might use lookarounds:
(?<!\S)\d+(?:\.\d+)?(?!\S)(?!.*\d)(?=.*masła)
(?<!\S)\d+(?:\.\d+)?(?!\S) Match 1+ digits with an optional past to match a dot and 1+ digits
(?!.*\d) assert that there are no more digits following
(?=.*masła) Assert what is on the right is your word
Regex demo
Or you might use a capturing group:
(?<!\S)(\d+(?:\.\d+)?)[^\d\n]* masła(?!\S)[^\d\n]*$
Regex demo
This expression might simply suffice:
.*([0-9])
if we are interested in one digit only, or
.*([0-9]+)
if multiple digits might be desired.
Demo 1
If those strings with masła are desired, we can expand our expression to:
(?=.*masła).*([0-9])
Demo 2
If we would not be validating our numbers and our number would be valid, with commas or dots, then this expression might likely return our desired output:
(?=.*masła)([0-9,.]+)(\D*)$
Demo 3
Related
The requirement is "each 2 digits must be only numbers or only text" - so valid patterns are AB-12-CD or 12-AB-CD or AB-CD-12, 12-34-AB.
The below suggested pattern working fine without hyphen but if we want to add a hyphen in between, how to do?
\b(?=[A-Z\d][A-Z])(?=[A-Z\d]\d)(?:[A-Z]{2}|\d{2})+\b
Repeat 1 or more times matching either 2 uppercase chars or 2 digits. Note that there are no hyphens present in the example data.
\b(?:[A-Z]{2}|\d{2})+\b
Regex demo
If there must be a digit and an uppercase character present, you could also use a positive lookahead:
\b(?=[A-Z\d]*[A-Z])(?=[A-Z\d]*\d)(?:[A-Z]{2}|\d{2})+\b
Regex demo
I need to check a block of text from an email for a number that's exactly 8 digits long, and only return the first match.
Here are my test cases:
Test123456789 -- should fail because 9 digits
Test23456789Test -- pass
Test23456789 Test -- pass
13456780Test -- pass
Test0123456 -- fail because 7 digits
Extra text in the email: I’ve attached the information you requested. If you have any questions, please let us know. -- extra text in the email shouldn't matter.
I've tried:
.*(\d{8}).* -- matches multiples
.*?(\d{8}).* -- only one match but it also matches on a 9 digit number
.*(?<!\d)\d{8}(?!\d).* -- I found in another answer but it returns all of the text in the email and I only want the 8 digit number.
Thank you for any guidance!
You can use the following regex:
(?!.*\d{9})\d{8}
It starts by using a negative look ahead for 9 digits. Then it matches 8 digits.
This will fail if there's 7 or 9 digits.
A small tweak to the last version you posted:
Try: .*(?<!\d)(\d{8})(?!\d).*
Demo
As the others have said, you can use negative look ahead and negative look behind, and remember to not include a g flag or else you'll match every occurrence of the pattern:
(?<!\d)\d{8}(?!\d)
Demo (global match)
You could find the first occurrence using:
^[\s\S]+?(?<!\d)(\d{8})(?!\d)
That will match:
^ Assert start of the string
[\s\S]+? Match any character non greedy
(?<!\d) negative lookbehind to check what is on the left is not a digit
(\d{8}) Capture 8 digits in a group
(?!\d) Negative lookahead to check what is on the right is not a digit
Or enable make the dot match the newline in your tool or language or prefix the regex with (?s) and replace [\s\S]+? with .+?
Your value is in the first capturing group.
Regex demo
I am looking for help here. I want to write a regex to help me find EXACTLY a 7 digit in string - no more or less.
For instance in this string:
1234567 RE:TKT-2744870-R6P1G0: Gentle Reminder
It should return only 1234567
In this one:
12345678 RE:TKT-2744870-R6P1G0: Gentle Reminder
It should return none.
Can you help me with this one.
thanks in advance.
The proper regex should include \d{7} (7 digits) and 2 "border criteria",
for both start and end of the match, to block matching of a fragment
from longer sequence of digits.
My first thought was that neither before nor after the match there can be any digit.
But as I see from your example, these border criteria should be extended.
The set of "forbidden" chars (either before or after the match) should
include also - and letters.
E.g. 2744870 in your example data contains just 7 digits (no more, no less),
but you still don't want it to be matched, apparently because they are surrounded with - chars.
To keep the regex short, I propose:
(?<![\w-])\d{7}(?![\w-])
Details:
(?<![\w-]) - Negative lookbehind for word char or -.
\d{7} - 7 digits.
(?![\w-]) - Negative lookahead for word char or -.
If you decide to extend the set of "forbidden" chars in both border criteria,
just add them to [...] fragments in lookbehind / lookahead (but - char
should remain at the end, otherwise it must be quoted with \).
Regex like (\d{7})[^\d] (in other proposition) is wrong,
as it matches last 7 digits from any longer sequence of digits
(no "front border criterion").
It matches also both 2744870 (surronded with - chars), which are not
to be matched.
This one should do for your examples:
(\d{7})[^\d]
The first matching group contains the seven digits.
Alternatively –as suggested in the comments– you can use a negative lookahead to only match the seven digits and not require matching groups:
^\d{7}(?!\d)
My regex is weak, in the case of the following string
"OtherId":47
"OtherId":7
"MyId":47 (Match this one)
"MyId":7
I want to pick up the string that has "MyId" and a number that is not 1 - 9
I thought I could just use:
RegEx: How can I match all numbers greater than 49?
Combined using:
Regular Expressions: Is there an AND operator?
But its not happening... you can see my failed attempt here:
https://www.regextester.com/index.php?fam=99753
Which is
\b"MyId":\b(?=.*^[0-10]\d)
What am I doing wrong?
You can use this regex to match any digit >= 10:
^"MyId":[1-9][0-9]+$
RegEx Demo
If leading zeroes are to be allowed as well then use:
^"MyId":0*[1-9][0-9]+$
[1-9] makes sure number starts with 1-9 and [0-9]+ match 1 or more any digits after first digit.
Essentially, you are looking for 2 or more digits:
\"MyId\"\:(\d{2,})
I have escaped the quotes and colon, and {2,} means 2 or more.
If you need exact match to any number greater than 9
^"MyId":[1-9][0-9]+$
I figured out a regular expresion for my country's phone but I've something missing.
The rule here is: (Area Code) Prefix - Sufix
Area Code could be 3 to 5 digits
Prefix could be 2 to 4 digits.
Area Code + Prefix is 7 digits long.
Sufix is always 4 digits long
Total digits are 11.
I figured I could have 3 simple regex chained with an OR "|" like this:
/(\(?\d{3}\)?[- .]?\d{4}[- .]?\d\d\d\d)|(\(?\d{4}\)?[- .]?\d{3}[- .]?\d\d\d\d)|(\(?\d{5}\)?[- .]?\d{2}[- .]?\d\d\d\d)/
The thing I'm doing wrong is that \d\d\d\d doesn't match only 4 digits for the sufix, for example: (011) 4740-5000 which is a valid phone number, works ok but if put extra digits it will also return as a valid phone number, ie: (011) 4740-5000000000
You should use ^ and $ to match whole string
For example ^\d{4}$ will match exactly 4 digits not more not less.
Here is the complete regex pattern
^((\(?\d{3}\)? \d{4})|(\(?\d{4}\)? \d{3})|(\(?\d{5}\)? \d{2}))-\d{4}$
Online demo
As per your regex pattern delimiter can be -,. or single space then try
^((\(?\d{3}\)?[-. ]?\d{4})|(\(?\d{4}\)?[-. ]?\d{3})|(\(?\d{5}\)?[-. ]?\d{2}))[-. ]?\d{4}$
This pattern works fine for me:
/^\\(?(\d{3,5})?\\)?\s?(15)?[\s|-]?(4)\d{2,3}[\s|-]?\d{4}$/
I've tested this in regex101:
/^((?:\(?\d{3}\)?[- .]?\d{4}|\(?\d{4}\)?[- .]?\d{3}|\(?\d{5}\)?[- .]?\d{2})[- .]?\d{4})$/
RegEx Demo
^ Matches the beginning of a string
( Beginning of capture group
(?: Beginning of non-capturing group
Your different options for area code & prefix
) End non-capturing group
[- .]?\d{4} The last four digits of the phone number
) End capture group
$ Matches the end of a string
If you're trying to validate such a phone number, then the following one should suit your needs:
^(?=.{15}$)[(]\d{3,5}[)] \d{2,4}-\d{4}$
Debuggex Demo
You need to match the complete expression by indicating the start and end with anchors. You also don't need alternation for the different lengths.
/^(?=(\D*\d){11}$)\(?\d{3,5}\)?[- .]?\d{2,4}[- .]?\d{4}$/
Here's the breakdown:
(?=(\D*\d){11}$) is a non-capturing group ensuring that there are 11 digits total,
with any number of non-digits amongst them
\(?\d{3,5}\)?[- .]? matches 3-5 digits in parens (area code), followed by a separator
\d{2,4}[- .]? matches 2-4 digits (prefix), followed by a separator
\d{4} matches the suffix