Trying to remove strings that follow the pattern
Tag Starts With
Size:
and before the next COMMA (,) includes the - character.
Example:
Size: XS-S-M-L-XL-2XL,
or
Size: XS-S-M,
etc.
WOULD get selected (including ,)
but Size_S, would be ignored because there is no -
I'm close with:
Size:(.*)-*(.?),
But still not stopping at ,
Here is 1 line of tags:
Athletics, Fitted, Mesh, Feature_Moisture Wicking, Material_Polyester 100%, , Material_Polyester 100%, Material_Polyester Over 50%, School, Style_Short Sleeves, Size_2XL, Size_L, Size_M, Size_S, Size_XL, Size_XS, Size: XS-S-M-L-XL-2XL, Uniforms, Unisex, V-Neck, VisibleLogos, Youth
To remove all size 'range' tags from my cells and only leave the single size tag.
Solution can be found here: regex101.com/r/VuTzba/1
In your pattern Size:(.*)-*(.?), you are first matching until the end of the string using (.*).
After that the hyphen -* and single character in the group (.?) are optional so it will backtrack until the last comma as that is the only character that has to be matched.
To get a more exact match, you could use a repeating pattern to match the sizes:
Size: (?:\d*X[SL]|L|M|S)(?:-(?:\d*X[LS]|L|M|S))*,
Explanation
Size: Match Size followed by a space
(?: Non capturing group
\d*X[SL]|L|M|S match one of the listed items in the alternation
) Close group
(?: Non capturing group
-(?:\d*X[LS]|L|M|S) Match a hyphen followed by any of the listed items
)*, Close group and repeat 0+ times and match a comma
Regex demo
As more broader pattern could be using a character class and list all the allowed characters Size: [XSML\d]+(?:-[XSML\d]+)*, or match until the first comma Size:[^,]+,
Edit
To also match Size: 28W-30W-32W-34W-36W-38W-40W, Size: 28W-30W-32W-34W or you could use extend the character class adding |\d+W to it and end the pattern matching either a comma or assert the end of the string $
Size: (?:\d*X[SL]|L|M|S|\d+W)(?:-(?:\d*X[LS]|L|M|S|\d+W))*(?:,|$)
Regex demo
We might want to add more boundaries in our expression here. Let's start with something similar to:
Size:\s+([A-Z0-9-]+),
where the capturing group () collects our desired data.
RegEx
If this expression wasn't desired, it can be modified or changed in regex101.com.
RegEx Circuit
jex.im also helps to visualize the expressions.
Size:\s*(.*?), will grab everything after the colon and before the next comma skipping leading white space.
Related
How to match strings that are entirely composed of a predefined set of substrings. For example, I want to see if a string is composed of only the following allowed substrings:
,
034
140
201
In the case when my string is as follows:
034,201
The string is fully composed of the 'allowed' substrings, so I want to positively match it.
However, in the following string:
034,055,201
There is an additional 055, which is not in my 'allowed' substrings set. So I want to not match that string.
What regex would be capable of doing this?
Try this one:
^(034|201|140|,)+$
Here is a demo
Step by step:
^ begining of a line
(034|201|140|,) captures group with alternative possible matches
+ captured group appears one or more times
$ end of a line
This regex will match only your values and ensure that the line doesn't start or end with a comma. Only matches in group 0 if it is valid, the groups are non-matching.
^(?:034|140|201)(?:,(?:034|140|201))*$
^: start
(?:034|140|201): non-matching group for your set of items (no comma)
(?:,(?:034|140|201))*: non-matching group of a comma followed by non-matching group of values, 0 or more times
$: end
I am trying to find regex which would find below matches. I would replace these with blank. I am able to create regex for few of these conditions individually, but I am not able to figure out how to create one regex for all of these
Strings:
song1 artist (SiteWithMp3Keyword.com).mp3
02.song2 | siteWithdownloadKeyword.in 320 Kbps
song3 [SitewithDjKeyword.in] 128kbps.mp3
Output
song1 artist.mp3
song2
song3.mp3
Criteria for match:
Case Insensitive
Find Strings with particular keyword and remove whole word, even if inside any braces
Find kpbs keyword and remove it along with any number before it (128/320)
if string ends in .mp3, keep it as it is.
Remove junk characters (like | ) and replace _ with space.
Remove number if present at start of string, like 001_ 02. etc.
Trim whitespaces before and after remaining string
Example Regex for 2.
\S+(mp3|dj|download)\S+
https://regex101.com/r/nxp4d3/1
Try this regex ....
Find:^[0-9. ]*(song\d+ (\w+ )?).*?(\.mp3 ?)?$
Replace with:$1$3
P.S , if this code doesn't solve your problem, please share a sample of your real data, so someone well better understand you,
Thanks...
For the example data, you might use:
^\h*(?:\d+\W*)?(\w+(?:\h+\w+)*).*?(\.mp3)?\h*$
The pattern matches:
^ Start of string
\h* Match optional leading spaces
(?:\d+\W*)? Match 1+ digits followed by optional non word characters
(\w+(?:\h+\w+)*) Capture group 1, match word characters optionally repeated with a space in between
.*? Match any character except a newline, as least as possible
(\.mp3)? Optionally capture .mp3 in group 2
\h* Match optional trailing spaces
$ End of string
Regex demo
Replace with capture group 1 and group 2
$1$2
I have to parse all the text in a paranthesis but not the one that contains "GST"
e.g:
(AUSTRALIAN RED CROSS – ATHERTON)
(Total GST for this Invoice $1,104.96)
today for a quote (07) 55394226 − admin.nerang#waste.com.au − this applies to your Nerang services.
expected parsed value:
AUSTRALIAN RED CROSS – ATHERTON
I am trying:
^\(((?!GST).)*$
But its only matching the value and not grouping correctly.
https://regex101.com/r/HndrUv/1
What would be the correct regex for the same?
This regex should work to get the expected string:
^\((?!.*GST)(.*)\)$
It first checks if it does not contain the regular expression *GST. If true, it then captures the entire text.
(?!*GST)(.*)
All that is then surrounded by \( and \) to leave it out of the capturing group.
\((?!.*GST)(.*)\)
Finally you add the BOL and EOL symbols and you get the result.
^\((?!.*GST)(.*)\)$
The expected value is saved in the first capture group (.*).
You can use
^\((?![^()]*\bGST\b)([^()]*)\)$
See the regex demo. Details:
^ - start of string
\( - a ( char
(?![^()]*\bGST\b) - a negative lookahead that fails the match if, immediately to the right of the current location, there are zero or more chars other than ) and ( and then GST as a whole word (remove \bs if you do not need whole word matching)
([^()]*) - Group 1: any zero or more chars other than ) and (
\) - a ) char
$ - end of string
Bonus:
If substrings in longer texts need to be matched, too, you need to remove ^ and $ anchors in the above regex.
I have a list of thousands of records within a .txt document.
some of them look like these records
201910031044 "00059" "11.31AG" "Senior Champion"
201910031044 "00060" "GBA146" "Junior Champion"
201910031044 "00999" "10.12G" "ProAM"
201910031044 "00362" "113.1LI" "Abcd"
Whenever a record similar to this occurs I'd like to get rid of the last words/numbers/etc in the last quotation marks (like "Senior Champion", "Junior Champion" etc. There are many possibilities here)
e.g. (before)
201910031044 "00059" "11.31AG" "Senior Champion"
after
201910031044 "00059" "11.31AG"
I tried the following regex but it wouldn't work.
Search: ^([0-9]{17,17} + "[0-9]{8,8}" + "[a-zA-Z0-9]").*$
Replace: \1 (replace string)
OK I forgot the . (dot) sign however even if I do not have a . (dot) sign it would not work. Not sure if it has anything to do when using the + sign used more than once.
I'd like to get rid of the last words/numbers/etc in the last quotation marks
This does the job:
Ctrl+H
Find what: ^.+\K\h+".*?"$
Replace with: LEAVE EMPTY
CHECK Wrap around
CHECK Regular expression
UNCHECK . matches newline*
Replace all
Explanation:
^ # beginning of line
.+ # 1 or more any character but newline
\K # forget all we have seen until this position
\h+ # 1 or more horizontal spaces
".*?" # something inside quotes
$ # end of line
Screen capture (before):
Screen capture (after):
The RegEx looks for the 4th double quote:
^(?:[^"]*\"){4}([^|]*)
You can see this demo: https://regex101.com/r/wJ9yS6/163
You will still need to parse the lines, so probably easier opening in excel or parsing using code as a CSV.
You have a problem with the count of your characters:
you specify that the line should start with exactly 17 digits ([0-9]{17,17}). However, there are only 12 digits in the data 201910031044.
you can specify exactly 12 digits by using {12} or if it could be 12-17, then {12,17}. I'll assume exactly 12 based on the current data.
similarly, for the second column you specify that it's exactly 8 digits surrounded by quotes ("[0-9]{8,8}") but it only has 5 digits surrounded by quotes.
again, you can specify exactly 5 with {5} or 5-8 with {5,8}. I will assume exactly 5.
finally, there is no quantifier for the final field, so the regex tries to match exactly one character that is a letter or a number surrounded by quotes "[a-zA-Z0-9]".
I'm not sure if there is any limit on the number of characters, so I would go with one or more using + as quantifier "[a-zA-Z0-9]+" - if you can have zero or more, then you can use *, or if it's any other count from m to n, then you can use {m,n} as before.
Not a character count problem but the final column can also have dots but the regex doesn't account for. You can just add . inside the square brackets and it will only match dot characters. It's usually used as a wildcard but it loses its special meaning inside a character class ([]), so you get "[a-zA-Z0-9.]+"
Putting it all together, you get
Search: ^([0-9]{12} + "[0-9]{5}" + "[a-zA-Z0-9.]+").*$
Replace: \1
Which will get rid of anything after the third field in Notepad++.
This can be shortened a bit by using \d instead of [0-9] for digits and \s+ for whitespace instead of +. As a benefit, \s will also match other whitespace like tabs, so you don't have to manually account for those. This leads to
Search: ^(\d{12}\s+"\d{5}"\s+"[a-zA-Z0-9.]+").*$
Replace: \1
If you want to get rid of the last words/numbers/etc in the last quotation marks you could capture in a group what is before that and match the last quotation marks and everything between it to remove it using a negated character class.
If what is between the values can be spaces or tabs, you could use [ \t]+ to match those (using \s could also match a newline)
Note that {17,17} and {8,8} may also be written as {17} and {8} which in this case should be {12} and {5}
^([0-9]{12}[ \t]+"[0-9]{5}"[ \t]+"[a-zA-Z0-9.]+")[ \t]{2,}"[^"\r\n]+"
In parts
^ Start of string
( Capture group 1
[0-9]{12}[ \t]+ Match 12 digits and 1+ spaces or tabs
"[0-9]{5}"[ \t]+ Match 5 digits between " and 1+ spaces or tabs
"[a-zA-Z0-9.]+" Match 1+ times any of the listed between "
) Close group
[ \t]{2,} Match 1+ times
"[^"\r\n]+"
In the replacement use group 1 $1
Regex demo
Before
After
I am using Notepad++ and the Find and Replace pattern with regular expressions to alter usernames such that only the first and last character of the screen name is shown, separated by exactly four asterisks (*). For example, "albobz" would become "a****z".
Usernames are listed directly after the cue "screen_name: " and I know I can find all the usernames using the regular expression:
screen_name:\s([^\s]+)
However, this expression won't store the first or last letter and I am not sure how to do it.
Here is a sample line:
February 3, 2018 screen_name: FR33Q location: Europe verified: false lang: en
Method 1
You have to work with \G meta-character. In N++ using \G is kinda tricky.
Regex to find:
(?>(screen_name:\s+\S)|\G(?!^))\S(?=\S)
Breakdown:
(?> Construct a non-capturing group (atomic)
( Beginning of first capturing group
screen_name:\s\S Match up to first letter of name
) End of first CG
| Or
\G(?!^) Continue from previous match
) End of NCG
\S Match a non-whitespace character
(?=\S) Up to last but one character
Replace with:
\1*
Live demo
Method 2
Above solution substitutes each inner character with a * so length remains intact. If you want to put four number of *s without considering length you would search for:
(screen_name:\s+\S)(\S*)(\S)
and replace with: \1****\3
Live demo