Cross-referencing with AND condition in XSLT - xslt

Question

I am trying to cross-reference from an external XML file, but instead of comparing just one key, I want to ask if one string AND other strings exist, and if yes reference from the external file:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.tei-
c.org/ns/1.0"
xmlns="http://www.tei-c.org/ns/1.0" exclude-result-prefixes="xs t">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="ids"
select="document('instructions.xml')"/>
<xsl:key name="id" match="row" use="tokenize(normalize-space(elem[#name='Instruction']), ' ')"/>
<!-- identity transform -->
<xsl:template match="#* | node() | text() | *">
<xsl:copy>
<xsl:apply-templates select="#* | node() | text() | *"/>
</xsl:copy>
</xsl:template>
<xsl:template match="instruction">
<xsl:for-each select=".[contains(.,key('id', ., .))]">
<xsl:copy>
<xsl:attribute name="norm">
<xsl:value-of select="normalize-space(key('id', normalize-space(.), $ids)/elem[#name='Norm'])"/>
</xsl:attribute>
<xsl:apply-templates select="#* | node() | text() | *"/>
</xsl:copy>
</xsl:for-each>
</xsl:template>
Input (External File):
<row>
<elem name="instruction">pour out</elem>
<elem name="norm">p1</elem>
</row>
Input (File to annotate):
<ab type="recipe">
Bla bla
<instruction>pour the milk out</instruction> bla
</ab>
Desired Output:
<ab type="recipe">
Bla bla
<instruction norm="p1">pour the milk out</instruction> bla
</ab>
In order words: Both of the tokens in the external XML file within the element <elem name="instruction"> "pour" AND "out" need to be contained within the <instruction>element in my XML file. If they are I want to set the norm attribute to the value of <elem name="norm"> in the external file.
Any help much appreciated!

Answer 1

I couldn't work out how to do it with a key, but I did come up with an alternate approach....
<xsl:template match="instruction">
<xsl:variable name="words" select="tokenize(normalize-space(.), ' ')" />
<xsl:variable name="row" select="$ids//row[every $i in tokenize(normalize-space(elem[#name='instruction']), ' ') satisfies $i = $words]" />
<xsl:copy>
<xsl:if test="$row">
<xsl:attribute name="norm" select="$row/elem[#name='norm']" />
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
EDIT: In response to your comment, if you can have multiple rows matching, then to get the one with the most matching words, do this....
<xsl:template match="instruction">
<xsl:variable name="words" select="tokenize(normalize-space(.), ' ')" />
<xsl:variable name="row" as="element()*">
<xsl:perform-sort select="$ids//row[every $i in tokenize(normalize-space(elem[#name='instruction']), ' ') satisfies $i = $words]">
<xsl:sort select="count(tokenize(normalize-space(elem[#name='instruction']), ' '))" order="descending" />
</xsl:perform-sort>
</xsl:variable>
<xsl:copy>
<xsl:if test="$row">
<xsl:attribute name="norm" select="$row[1]/elem[#name='norm']" />
</xsl:if>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>