RegEx for removing everything before and after a delimiter - regex

Question

I am trying to remove everything before and after two | delimiters using regex.
An example being:
EM|CX-001|Test Campaign Name
and grabbing everything except CX-001. I cannot use a substring as the number of characters before and after the pipes may change.
I tried using the regex (?<=\|)(.*?)(?=\-), but while this selects CX-001, I need to select everything else but this.
How do I solve this problem?

Answer 1

You can try the following regular expression:
(^[^|]*\|)|(\|[^|]*$)
String input = "EM|CX-001|Test Campaign Name";
System.out.println(
input.replaceAll("(^[^|]*\\|)|(\\|[^|]*$)", "")
); // prints "CX-001"
Explanation of the regular expression:
NODE EXPLANATION
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
[^|]* any character except: '|' (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
\| '|'
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\| '|'
--------------------------------------------------------------------------------
[^|]* any character except: '|' (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
$ before an optional \n, and the end of
the string
--------------------------------------------------------------------------------
) end of \2

Answer 2

If you have only 2 pipes in you string, you could either match upon the first pipe or match from the last one until the end of the string:
^.*?\||\|.*$
Explanation
^.*?\| Match from start of string non greedy until the first pipe
| Or
\|.*$ Match from last pipe until end of string
Regex demo
Or you might also use a negated character class [^|]* without the need of capturing groups:
^[^|]*\||\|[^|]*$
Regex demo
Note
In your pattern (?<=\|)(.*?)(?=\-) I think you meant that the last positive lookahead should be (?=\|) instead of the - if you want to select between 2 pipes.

Answer 3

Find: ^[^|]*\|([^|]+).+$
Replace: $1