I'm trying to create a regex that matches url strings within normal text. I have this:
http[s]?://[^\s]+
This seems to work well with the exception that if the url is at the end of a sentence it will grab the period as well. For example for this string:
I am typing some text with the url http://something.com/something-?args=someargs. This is another sentence.
it matches:
http://something.com/some-thing?args=someargs.
I would like it to match:
http://something.com/some-thing?args=someargs
Obviously I can't exclude periods because they are in the url previously but I can't figure out how to tell it to exclude the last period if there is one. I could potentially use a negative lookahead for end of line or whitespace, but if it's in the middle of the line (without a period after it) that would leave off the last character of the url.
Most of the ones I have seen online have the same issue that they match the ending dot so maybe it's not possible? I know basic regex but certainly not a genius with it so if someone has a solution I would be very grateful :).
Also, I can do some post-process in this case to remove the dot if I need to, just seems like there should be a Regex solution...
Try this one
http[s]?://[^\s]+[^. ]
Related
I've tried a lot to split this string into something i can work with, however my experience isn't enough to reach the goal. Tried first 3 pages on google, which helped but still didn't give me an idea how to properly do this:
I have a string which looks like this:
My Dogs,213,220#Gallery,635,210#Screenshot,219,530#Good Morning,412,408#
The result should be:
MyDogs
213,229
Gallery
635,210
Screenshot
219,530
Good Morning
412,408
Anyone have an idea how to use regex to split the string like shown above?
Given the shared patterns, it seems you're looking for a regex like the following:
[A-Za-z ]+|\d+,\d+
It matches two patterns:
[A-Za-z ]+: any combination of letters and spaces
\d+,\d+: any combination of digits + a comma + any combination of digits
Check the demo here.
If you want a more strict regex, you can include the previous pattern between a lookbehind and a lookahead, so that you're sure that every match is preceeded by either a comma, a # or a start/end of string character.
(?<=^|,|#)([A-Za-z ]+|\d+,\d+)(?=,|#|$)
Check the demo here.
I need to check if a URLs is in a sentence.
Some text. This is good.
https://stackoverflow.com
More text
More text https://stackoverflow.com. More text. This is bad
I can find the URLs after some research, but I'm stuck on finding them in sentences.
https://regex101.com/r/AmuFIX/5
((http|ftp|https):\/\/)?[-a-zA-Z0-9#:%._\+~#=]{2,256}\.[a-z]{2,6}\b([-a-zA-Z0-9#:%_\+.~#?&//=]*)[\r\n]
Based on the comments, it sounds like you're looking for cases where a URL is mixed with other text on a line, not necessarily a sentence. For that, I would use something like this:
.+\b((http|ftp|https):\/\/)[-a-zA-Z0-9#:%._\+~#=]{2,256}\.[a-z]{2,6}\b([-a-zA-Z0-9#:%_\+.~#?&//=]*)\b.+
This changes your query by asserting that there must be some characters, followed by a word boundary, followed by a URL, followed by a word boundary, followed by some other characters. This won't match a URL at the start or end of a line that also has other content; for that you'd likely need to two two separate matches - one for a URL with something before it, one for a URL with something after it.
I have a special task which requires lots of regex and javascript parsing.
My head is almost exploding, so maybe I'm tired and forgot some small thing else I'm not newbie to regex so perhaps someone will point me to good direction here and show me where I did mistake.
So I have this regex code:
((?<=\ffmpg=).+(?=////u0026cs=nt))
to get the value of substring between 2 strings. The first string is called:
ffmpg= from this string it should start and it will end just before the other string start called //u0026cs=nt
The problem is that it is working fine until the html page contains only one parameter with the same name; because the source html has inside like 10's of ffmg and the same end string called cs=nt.
I can not even make regex to count the characters because every time you visit the html page the number of characters are different, sometimes +3 else +10. So the only way is to get this sting from the start of param1 to the end of param2.
This is the string I need to get: 1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012
This is the source html example:
\u0026doc=IcuU5Oy8\u0026pen=V9PXaHoOp1gKD25rgAg\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\u0026cs=nt\u0026token=gHgig8eLY3qsQ0bXa\\u0026doc=IcuU5Oy8\u0026pen=V9PXaHoOp1gKD25rgAg\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\u0026cs=nt\u0026token=gHgig8eLY3qsQ0bXa\\u0026doc=IcuU5Oy8\u0026pen=V9PXaHoOp1gKD25rgAg\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\u0026cs=nt\u0026token=gHgig8eLY3qsQ0bXa\
I have copied 3 times the same just for this purpose because it is very big html source and I doubt I can upload it here.
Thanks for your help.
In your questions, you use (?<=\ffmpg=) where \f will match a form feed character which is not present in the data example. If you meant to use \\f it will match \f which is also not present in the example data.
You could get the match using a capturing group instead of using lookarounds as lookbehinds are not widely supported by all browsers.
If you just want to get a single match, you can omit the /g global flag.
If you use .+ you will match too much as the .+ will match until the end of the string and then backtracks until the first time it can match \\u0026cs=nt
What you could do instead is be specific in what you would allow to match which for the current string is a character class with the following characters [AC0-9%]+
You could broaden the character class with a range to match chars A-Z instead of AC for example and add more chars or ranges as required.
ffmpg=([AC0-9%]+)\\\\u0026cs=nt
Regex demo
For example
const regex = /ffmpg=([AC0-9%]+)\\\\u0026cs=nt/;
const str = `\\\\u0026doc=IcuU5Oy8\\\\u0026pen=V9PXaHoOp1gKD25rgAg\\\\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\\\\u0026cs=nt\\\\u0026token=gHgig8eLY3qsQ0bXa\\\\\\\\u0026doc=IcuU5Oy8\\\\u0026pen=V9PXaHoOp1gKD25rgAg\\\\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\\\\u0026cs=nt\\\\u0026token=gHgig8eLY3qsQ0bXa\\\\\\\\u0026doc=IcuU5Oy8\\\\u0026pen=V9PXaHoOp1gKD25rgAg\\\\u0026ffmpg=1714248%2C23851735%2C23804281%2C23839597%2C23357901%2C3313341%2C3316343%2C23848795%2C3300132%2C26853996%2C3300114%2C3315790%2C23857451%2C23856472%2C23851936%2C3300161%2C3314786%2C23856652%2C23859863%2C23837993%2C23833479%2C23861502%2C23842630%2C23842986%2C23861012\\\\u0026cs=nt\\\\u0026token=gHgig8eLY3qsQ0bXa\\\\`;
console.log(str.match(regex)[1]);
Try this:
(?<=ffmpg=)([A-F0-9%]+)
Explanation
Since your string only consists of url-encoded characters, you can use [A-F0-9%]+character class to capture it. It will stop when next string starts because there will be a backslash.
See online demo here.
I have to match an exact string at the end of a url, but not match all other urls that have more characters after that string
I can better explain with example.
I need to match the url having the string 'white' at its end: http//mysite.com/white
But I also need to not match urls having one or more characters postponed to it, like http//mysite.com/white__blue or http//mysite.com/white/yellow or http//mysite.com/white/
How to do that?
Thanks
Regex to match any url*
^(https?:\/\/)?([\da-z\.-]+\.[a-z\.]{2,6}|[\d\.]+)([\/:?=&#]{1}[\da-z\.-]+)*[\/\?]?$
Regex to match a url containing white in the end
^(https?:\/\/)?([\da-z\.-]+\.[a-z\.]{2,6}|[\d\.]+)([\/:?=&#]{1}[\da-z\.-]+)*[\/\?]?white$
You can check the regex here
From regexr.com
It does not match urls(which are not valid anyway) like
httpabrakadabra.co//
http:google.com
http://no-tld-here-folks.a
http://potato.54.211.192.240/
Based on your limited sample inputs, I'd say you could get away with this very minimal pattern:
^http[^\s]+white$
However, depending on what you are truly trying to achieve, what language/function you are implementing this pattern with, and what the full input string looks like, this pattern may need to be refined.
It would be best if you would improve your question to include all of the above relevant information.
I am an absolute regex noob and have been banging my head against the wall trying to write a regex to remove email signatures from a string that look like this:
Hi There, this is an email.
Warm Regards,
Joe Bloggs
Thus far, I’ve tried variations on:
/^[\w |][R|r]egards,/
The regex should:
look at the beginning of the line (what I was aiming for with the ^,
cover variations like “Warm Regards”, “Kind Regards”, “Best Regards”, and plain old “Regards” (which I was hoping to accomplish with the [\w |] to match any word or blank and the [R|r] to cover Regards/regards),
be OK with mixed case like “warm regards” or “Warm Regards”, and
only pickup lines that are [word] Regards or just regards, so that we don’t grab email body that has the word “regards” somewhere in it.
This seems elementary, but I just can’t nail it, and I seem to err on broadening my regex too much such that any line that contains “regards” gets picked up. I’m doing this in Node.js combined with the string.search function if that matters.
This seems to fit all your requirements:
^(\w*\s)?[r|R]egards,?
Has to start on a new line, then can have any word followed by a space, and the word regards, or just the word regards, with the comma also being optional.
If you want to wipe out everything after the regards line as well you can add in \s*.*
^(\w*\s)?[r|R]egards,?\s*.*
If you are trying to remove everything from the Warm Regards line on, this should do it
^[^<]*?(?=(.*)[R|r]egards)
Try the following regular expression
^\w* ?regards,?
with the case insensitive & global flag specified.
You can see the regular expression explanation and what it matches here: http://regex101.com/r/vR3zG5
The regular expression that matches signatures defined in #1-#4 is following:
/^(\w+ +)?regards,? *$/im
How it works:
"^" in the beginning means new line
"(\w+ +)?" means optional segment that contains exactly one word followed by at least one space
"regards" is just a simple match
",?" optional comma at the end
" *" - the line may contain trailing spaces (it may be useful to put the same match after ^)
"$" - end of line
/.../i - means that the expression is case-insensitive
/.../m - means that ^ and $ match at line breaks