Password error when customizing Django authentication - django

Question

I'm trying to customize the authentication that comes by default in Django with a table of Mysql already made (collaborators).
When I want to register a user (with the command python manage.py createsuperuser) I get the following error:
django.db.utils.OperationalError: (1054, "Unknown column 'collaborators.password' in 'field list'").
That error mentions that the password column does not exist, and indeed I do not have it in the table, is there any way to indicate that the password is obtained from a column called contrasena_general?
I attach my code.
models.py
class MyUserManager(BaseUserManager):
use_in_migrations = True
def create_superuser(self, no_colaborador, nombres_colaborador, apellido_paterno_colaborador, apellido_materno_colaborador,
id_plantel, id_area_colaborador, no_empleado_sup, contrasena_general, empleado_interno):
user = self.model(no_colaborador = no_colaborador, nombres_colaborador = nombres_colaborador,
apellido_paterno_colaborador = apellido_paterno_colaborador, apellido_materno_colaborador = apellido_materno_colaborador,
id_plantel = id_plantel, id_area_colaborador = id_area_colaborador, no_empleado_sup = no_empleado_sup,
contrasena_general = contrasena_general, empleado_interno = empleado_interno,)
user.set_password(contrasena_general)
user.save(using=self._db)
return user
class Colaboradores(AbstractBaseUser):
no_colaborador = models.IntegerField(primary_key=True)
nombres_colaborador = models.CharField(max_length=150)
apellido_paterno_colaborador = models.CharField(max_length=150)
apellido_materno_colaborador = models.CharField(max_length=150)
id_plantel = models.IntegerField()
id_area_colaborador = models.IntegerField()
id_centro_costos = models.IntegerField()
no_empleado_sup = models.IntegerField()
contrasena_general = models.CharField(max_length=100)
empleado_interno = models.CharField(max_length=10)
objects = MyUserManager()
USERNAME_FIELD = "no_colaborador"
class Meta:
managed = False
db_table = 'collaborators'
app_label = "journal"
def __str__ (self):
return self.email
def def_full_name (self):
return self.nombres_colaborador
def has_perm(self, perm, obj=None):
return self.no_colaborador
def has_module_perms(self, app_label):
return self.no_colaborador
# backends.py
class MyAuthBackend(object):
def authenticate(self, no_colaborador, contrasena_general):
try:
user = Colaboradores.objects.get(no_colaborador=no_colaborador)
if user.check_password(contrasena_general):
return user
else:
return None
except Colaboradores.DoesNotExist:
logging.getLogger("error_logger").error("user with login %s does not exists " % login)
return None
except Exception as e:
logging.getLogger("error_logger").error(repr(e))
return None
def get_user(self, no_colaborador):
try:
user = Colaboradores.objects.get(no_colaborador=no_colaborador)
if user.is_active:
return user
return None
except Colaboradores.DoesNotExist:
logging.getLogger("error_logger").error("user with %(no_colaborador)d not found")
return None
# setting.py
...
AUTH_USER_MODEL = 'journal.Colaboradores'
AUTHENTICATION_BACKENDS = ('clientes.backends.MyAuthBackend', 'django.contrib.auth.backends.ModelBackend',)
How could you indicate that the password is obtained from a column in the table that is not called a password?

Answer 1

I think creating your own createsuperuser command would solve this issue.
Ref: Is it possible to make my own createsuperuser command in django?
You can make your based on the the original source code for Django's createsuperuser that can be found on Github.
As you can see from there, there is a constant on line 20 that says:
PASSWORD_FIELD = 'password'
So I guess that since you changed it in the model to contrasena_general, you need to make your own custom command.