I need the regular expression pattern which should not allow to put any of following characters into input in HTML
,;:|
You may get some idea from this.
[^,;:|]+
DEMO::: https://rubular.com/r/dKQzC1HrnMG88X
Related
I have a requirement to parse part of url with multiple expressions using regex, expressions are like /abc/def (or) /z/a (or) /v/g. I have a regex that satisfies single expression, but not sure how to do for multiple expression.
(?<volga>.+?\/abc\/def.+?)
volga is a named capturing group.
Above regular expression satisfies anything before /abc and anything after /def, the same way url also has /z/a and /v/g. This is kind of either /abc/def/ or /z/a or /v/g can exist in url. How to write a regular expression that checks for all of above expressions.
Examples of url:
/api/com/abc/def/710660716/847170/
/api/com/z/a/
Maybe this:
(?<volga>.+?\/((abc\/def)|(z\/a)|(v\/g)).*)
Matches any string containing
abc/def
or z/a
or v/g
Regex101
I am pretty new in Regular Expression.
Input
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
/shop/necklaces
/shop/yellow-gold-necklaces
/shop/white-gold-necklaces
/shop/rose-gold-necklaces
/shop/best-buy-earrings
Regular Expression I used
\/shop\/[a-z-]*-?earrings
Desired Result
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
Actual Result
/shop/earrings
/shop/yellow-gold-earrings
/shop/white-gold-earrings
/shop/rose-gold-earrings
/shop/best-buy-earrings
I do not want /shop/best-buy-earrings to be in the result. Please help me to fix the Regular Expression. Thank you.
Simply add gold to the regex before the - and surround with parenthesis:
\/shop\/([a-z-]*gold-)?earrings
Assuming PCRE flavour, you can use:
\/shop\/(?!best-buy)(?:\w+-)*earrings
Or, if you can use other delimiter than slash:
/shop/(?!best-buy)(?:\w+-)*earrings
Demo
I am trying to use regular expression in Jmeter where in I need to unmatch a particular string. Here is my input test string : <activationCode>insvn</activationCode>
I need to extract the code insvn from it. I tried using the expression :
[^/<activationCode>]\w+, but does not yield the required code. I am a newbie to regular expression and i need help with this.
Can you use look-behind assertion in jmeter? If so, you can use thatr regex which will give you a word that follows <activationCode>
(?<=\<activationCode\>)\w+
If your input string is encoded (e.g for HTML), use:
(?<=\<activationCode\>)\w+
When designing a regular expression in any language for something like this you can match your input string as three groups: (the opening tag, the content, and the closing tag) then select the content from the second group.
I want to format html document and it has full of inline css. I use notpad++ and try regular expression to format it.
I want to replace style='font-family:"Arial","sans-serif"....... etc ' with style=''
How to do this with regular expressions?
I am new to regular expressions.
Replace :
style='[^']+'
with:
style=''
[^']+ matches one or more characters that is not quote(')
I am using Regular Expression in Jquery to validate names.I am having this issue that i need a pattern which will allow an apostrophe in the name.That means it can have alphabets and a single apostrophe.
Valid: D'souza,Danny
Invalid: D''souza
Can anybody help me out with this.Currently I am using this pattern
var rxPattern = /^([a-zA-Z]+)$/;
Thanks
You probably need something like that:
[a-zA-Z]+('[a-zA-Z])?[a-zA-Z]*