Regex pattern to match valid version numbers - regex

Question

I'm looking for a regex pattern that would match a version number.
The solutions I found here don't really match what I need.
I need the pattern to be valid for single numbers and also for numbers followed by .
The valid numbers are
1
1.23
1.2.53.4
Invalid numbers are
01
1.02.3
.1.2
1.2.
-1

Answer 1

Consider:
^[1-9]\d*(\.[1-9]\d*)*$
Breaking that down:
^ - Start at the beginning of the string.
[1-9] - Exactly one of the characters 1 thru 9.
\d* - More digits.
( - Beginning of some optional extra stuff
\. - A literal dot.
[1-9] - Exactly one of the characters 1 thru 9.
\d* - More digits.
) - End of the optional extra stuff.
* - There can be any number of those optional extra stuffs.
$ - And end at the end of the string.
Beware
Some of this syntax differs depending what regex engine you are using. For example, are you using the one from Perl, PHP, Javascript, C#, MySQL...?
In my experience, version numbers do not fit the neat format you described.
Specifically, you get values like 0.3RC5, 12.0-beta6, 2019.04.15-alpha4.5, 3.1stable, V6.8pl7 and more.
If you are validating existing data, make sure that your criteria fit the conditions you've described. In particular, if you are following "Semantic Versioning", be aware that versions which are zeros are legal, so 1.0.1, that "Additional labels for pre-release and build metadata are available as extensions to the MAJOR.MINOR.PATCH format.", and that "1" is not a legal version number.
Be warned that the above will also match stupidly long version numbers like 1.2.3.4.5.6.7.8.9.10.11.12.13.14. To prevent this, you can restrict it, like so:
^[1-9]\d*(\.[1-9]\d*){0,3}$
This changes the * for "any number of optional extra dots and numbers" to a range from zero to three. So it'd accept 1, 1.2, 1.2.3, and 1.2.3.4, but not 1.2.3.4.5.
Also, if you want zeros to be legal but only if there are no other numbers (so 0.3, 1.0.1), then it gets a little more complex:
^(0|[1-9]\d*)(\.(0|[1-9]\d*)){0,3}$
This question may also be a duplicate: A regex for version number parsing

Answer 2

Major.Minor.Patch - npm version like 0.1.2:
^([1-9]\d*|0)(\.(([1-9]\d*)|0)){2}$
More or optional minor groups like 1.1.5.0 or just 1.2:
^([1-9]\d*|0)(\.(([1-9]\d*)|0)){0,3}$
Avoid leading zero - no |0 in first group:
^([1-9]\d*)(\.(([1-9]\d*)|0)){0,3}$
Semantic Version String like 1.0.0-beta
^(0|[1-9]\d*)\.(0|[1-9]\d*)\.(0|[1-9]\d*)(?:-((?:0|[1-9]\d*|\d*[a-zA-Z-][0-9a-zA-Z-]*)(?:\.(?:0|[1-9]\d*|\d*[a-zA-Z-][0-9a-zA-Z-]*))*))?(?:\+([0-9a-zA-Z-]+(?:\.[0-9a-zA-Z-]+)*))?$
Break down:
^: match the line start
$: match the line end
( and ): make a group
([1-9]\d*|0): match version number
[1-9]\d*: starting with 1~9, following any number of digit
|: logical or
0: literal zero
\.: literal (escaped) dot
{2}: exact 2 matches
{0,3}: 0~3 matches
Test cases (regex101 JavaScript):
Match:
0.0.0
0.0.1
0.1.0
1.0.0
1.0.1
1.1.0
1.1.1
0.0.10
0.10.0
10.0.0
0.1.10
1.0.10
1.0.100
0.100.1
100.0.0
1.20.0
Not match:
0.0.00
0.00.0
00.00.0
0.0.01
0.01.0
01.0.0
0.01.0
01.0.0
00.0.01

Answer 3

This regex should help:
^(([1-9]+\d*\.)+[1-9]+\d*)|[1-9]+\d*$
Below is the explanation.
[1-9]+\d* means a sequence which begins with a non-zero number, followed by zero or more numbers
The first part (([1-9]+\d*\.)+[1-9]+\d*) catches all of your correct examples, except of 1. So, we have a | (or), followed by a [1-9]+\d* sequence.

Answer 4

([\*,\^])([\-,\*,\w]+[\.])+(\w)*
for npm package fro example
"cross-env": "^5.2.0",