I have a simple query with filter and exclude. Exclude for Q & Q not working.
Below is the query that I am using.
start_date = (datetime(time.localtime().tm_year, time.localtime().tm_mon, 1) - timedelta(1)).replace(day=1)
data = models.Test.objects.filter(
is_deleted=False).exclude(Q(status__in=[1,2,3]) & Q(modified_at__lt=start_date))\
.select_related('created_by')\
.prefetch_related('name')
I want the exclude to work. If I use exclude twice, I'm getting the result.
From the doc
exclude(**kwargs)
Returns a new QuerySet containing objects that do not match the given lookup parameters.
The lookup parameters (**kwargs) should be in the format described in Field lookups below. Multiple parameters are joined via AND in the underlying SQL statement, and the whole thing is enclosed in a NOT().
So, just use Q() objects with comma seperation,
.exclude(Q(status__in=[1,2,3],Q(modified_at__lt=start_date))
Related
I have a queryset like this:
predicts = Prediction.objects.select_related('match').filter(match_id=pk)
I need to annotate this with a new field is_correct. I need to compare two string fields and the result should be annotated in this new field. the fields that I want to compare are:
predict from Prediction table
result from Match table (that has been joined through select_related)
I need to know what expression should I put inside my annotate function; below I have my current code which throughs a TypeError exception:
predicts = predicts.annotate(is_correct=(F('predict') == F('result')))
all help will be greatly appreciated.
UPDATE:
I found an alternative solution that does the job for me (filtering the Prediction based on Match result using filter and exclude), but I still like to know how to address this specific case where the new annotated field is the result of the comparison between two other fields of the queryset. For those who may need it, in Django 2.2 and later the Nullif database function does a comparison between two fields.
You can use the extra function, a hook for injecting specific clauses into the SQL.
First of all, we must know the names of the apps and the models, or the name of the tables in the database.
Assuming that in your case, the two tables are called "app_prediction" and "app_match".
The sentence would be as follows:
Prediction.objects.select_related('match').extra(
select={'is_correct': "app_prediction.predict = app_match.result"}
)
This will add a field called is_correct in your result,
in the database, the fields and tables must be called in the same way.
It would be best to see the models.
With the following Django model:
class Item(models.Model):
name = CharField(max_len=256)
description = TextField()
I need to formulate a filter method that takes a list of n words (word_list) and returns the queryset of Items where each word in word_list can be found, either in the name or the description.
To do this with a single field is straightforward enough. Using the reduce technique described here (this could also be done with a for loop), this looks like:
q = reduce(operator.and_, (Q(description__contains=word) for word in word_list))
Item.objects.filter(q)
I want to do the same thing but take into account that each word can appear either in the name or the description. I basically want to query the concatenation of the two fields, for each word. Can this be done?
I have read that there is a concatenation operator in Postgresql, || but I am not sure if this can be utilized somehow in django to achieve this end.
As a last resort, I can create a third column that contains the combination of the two fields and maintain it via post_save signal handlers and/or save method overrides, but I'm wondering whether I can do this on the fly without maintaining this type of "search index" type of column.
The most straightforward way would be to use Q to do an OR:
lookups = [Q(name__contains=word) | Q(description__contains=word)
for word in words]
Item.objects.filter(*lookups) # the same as and'ing them together
I can't speak to the performance of this solution as compared to your other two options (raw SQL concatenation or denormalization), but it's definitely simpler.
I have a Result object that is tagged with "one" and "two". When I try to query for objects tagged "one" and "two", I get nothing back:
q = Result.objects.filter(Q(tags__name="one") & Q(tags__name="two"))
print len(q)
# prints zero, was expecting 1
Why does it not work with Q? How can I make it work?
The way django-taggit implements tagging is essentially through a ManytoMany relationship. In such cases there is a separate table in the database that holds these relations. It is usually called a "through" or intermediate model as it connects the two models. In the case of django-taggit this is called TaggedItem. So you have the Result model which is your model and you have two models Tag and TaggedItem provided by django-taggit.
When you make a query such as Result.objects.filter(Q(tags__name="one")) it translates to looking up rows in the Result table that have a corresponding row in the TaggedItem table that has a corresponding row in the Tag table that has the name="one".
Trying to match for two tag names would translate to looking up up rows in the Result table that have a corresponding row in the TaggedItem table that has a corresponding row in the Tag table that has both name="one" AND name="two". You obviously never have that as you only have one value in a row, it's either "one" or "two".
These details are hidden away from you in the django-taggit implementation, but this is what happens whenever you have a ManytoMany relationship between objects.
To resolve this you can:
Option 1
Query tag after tag evaluating the results each time, as it is suggested in the answers from others. This might be okay for two tags, but will not be good when you need to look for objects that have 10 tags set on them. Here would be one way to do this that would result in two queries and get you the result:
# get the IDs of the Result objects tagged with "one"
query_1 = Result.objects.filter(tags__name="one").values('id')
# use this in a second query to filter the ID and look for the second tag.
results = Result.objects.filter(pk__in=query_1, tags__name="two")
You could achieve this with a single query so you only have one trip from the app to the database, which would look like this:
# create django subquery - this is not evaluated, but used to construct the final query
subquery = Result.objects.filter(pk=OuterRef('pk'), tags__name="one").values('id')
# perform a combined query using a subquery against the database
results = Result.objects.filter(Exists(subquery), tags__name="two")
This would only make one trip to the database. (Note: filtering on sub-queries requires django 3.0).
But you are still limited to two tags. If you need to check for 10 tags or more, the above is not really workable...
Option 2
Query the relationship table instead directly and aggregate the results in a way that give you the object IDs.
# django-taggit uses Content Types so we need to pick up the content type from cache
result_content_type = ContentType.objects.get_for_model(Result)
tag_names = ["one", "two"]
tagged_results = (
TaggedItem.objects.filter(tag__name__in=tag_names, content_type=result_content_type)
.values('object_id')
.annotate(occurence=Count('object_id'))
.filter(occurence=len(tag_names))
.values_list('object_id', flat=True)
)
TaggedItem is the hidden table in the django-taggit implementation that contains the relationships. The above will query that table and aggregate all the rows that refer either to the "one" or "two" tags, group the results by the ID of the objects and then pick those where the object ID had the number of tags you are looking for.
This is a single query and at the end gets you the IDs of all the objects that have been tagged with both tags. It is also the exact same query regardless if you need 2 tags or 200.
Please review this and let me know if anything needs clarification.
first of all, this three are same:
Result.objects.filter(tags__name="one", tags__name="two")
Result.objects.filter(Q(tags__name="one") & Q(tags__name="two"))
Result.objects.filter(tags__name_in=["one"]).filter(tags__name_in=["two"])
i think the name field is CharField and no record could be equal to "one" and "two" at same time.
in python code the query looks like this(always false, and why you are geting no result):
from random import choice
name = choice(["abtin", "shino"])
if name == "abtin" and name == "shino":
we use Q object for implement OR or complex queries
Into the example that works you do an end on two python objects (query sets). That gets applied to any record not necessarily to the same record that has one AND two as tag.
ps: Why do you use the in filter ?
q = Result.objects.filter(tags_name_in=["one"]).filter(tags_name_in=["two"])
add .distinct() to remove duplicates if expecting more than one unique object
I want to retrieve a sum of two fields (which are aggregations themselves) for each object in a table.
The following may describe a bit better what I'm after but results in an Unknown column in field list-Error:
items = MyModel.objects.annotate(
field1=Sum("relatedModel__someField"),
field2=Sum("relatedModel__someField")).extra(
select={"sum_field1_field2": "field1 + field2"})
I also tried using F() for the field lookups but that gives me an invalid sql statement.
Any ideas on how to solve this are much appreciated.
it this what you want?
items = MyModel.objects.extra(
select = {'sum_field1_field2': 'SUM(relatedModel__someField) + SUM(relatedModel__someField)'},
)
To make it work for many to many or for many to one (reverse) relations, you may use the following:
items = MyModel.objects.extra(
select = {'sum_field1_field2': 'SUM("relatedModel"."someField") + SUM("relatedModel"."someField")'},
)
But this will break also if you need another annotate, like for a count, because extra will add the statement to the GROUP BY clause, whereas aggregate functions are not allowed in there.
I have first_name, last_name & alias (optional) which I need to search for. So, I need a query to give me all the names that have an alias set.
Only if I could do:
Name.objects.filter(alias!="")
So, what is the equivalent to the above?
You could do this:
Name.objects.exclude(alias__isnull=True)
If you need to exclude null values and empty strings, the preferred way to do so is to chain together the conditions like so:
Name.objects.exclude(alias__isnull=True).exclude(alias__exact='')
Chaining these methods together basically checks each condition independently: in the above example, we exclude rows where alias is either null or an empty string, so you get all Name objects that have a not-null, not-empty alias field. The generated SQL would look something like:
SELECT * FROM Name WHERE alias IS NOT NULL AND alias != ""
You can also pass multiple arguments to a single call to exclude, which would ensure that only objects that meet every condition get excluded:
Name.objects.exclude(some_field=True, other_field=True)
Here, rows in which some_field and other_field are true get excluded, so we get all rows where both fields are not true. The generated SQL code would look a little like this:
SELECT * FROM Name WHERE NOT (some_field = TRUE AND other_field = TRUE)
Alternatively, if your logic is more complex than that, you could use Django's Q objects:
from django.db.models import Q
Name.objects.exclude(Q(alias__isnull=True) | Q(alias__exact=''))
For more info see this page and this page in the Django docs.
As an aside: My SQL examples are just an analogy--the actual generated SQL code will probably look different. You'll get a deeper understanding of how Django queries work by actually looking at the SQL they generate.
Name.objects.filter(alias__gt='',alias__isnull=False)
Firstly, the Django docs strongly recommend not using NULL values for string-based fields such as CharField or TextField. Read the documentation for the explanation:
https://docs.djangoproject.com/en/dev/ref/models/fields/#null
Solution:
You can also chain together methods on QuerySets, I think. Try this:
Name.objects.exclude(alias__isnull=True).exclude(alias="")
That should give you the set you're looking for.
1. When using exclude, keep the following in mind to avoid common mistakes:
Should not add multiple conditions into an exclude() block like filter(). To exclude multiple conditions, you should use multiple exclude().
Example: (NOT a AND NOT b)
Entry.objects.exclude(title='').exclude(headline='')
equal to
SELECT... WHERE NOT title = '' AND NOT headline = ''
======================================================
2. Only use multiple when you really know about it:
Example: NOT (a AND b)
Entry.objects.exclude(title='', headline='')
equal to
SELECT.. WHERE NOT (title = '' AND headline = '')
If you want to exclude null (None), empty string (""), as well as a string containing white spaces (" "), you can use the __regex along with __isnull filter option
Name.objects.filter(
alias__isnull = False,
alias__regex = r"\S+"
)
alias__isnull=False excludes all the columns null columns
aliax__regex = r"\S+" makes sure that the column value contains at least one or more non whitespace characters.
From Django 1.8,
from django.db.models.functions import Length
Name.objects.annotate(alias_length=Length('alias')).filter(alias_length__gt=0)
You can simply do this:
Name.objects.exclude(alias="").exclude(alias=None)
It's really just that simple. filter is used to match and exclude is to match everything but what it specifies. This would evaluate into SQL as NOT alias='' AND alias IS NOT NULL.
Another approach using a generic isempty lookup, that can be used with any field.
It can also be used by django rest_framework or other apps that use django lookups:
from distutils.util import strtobool
from django.db.models import Field
from django.db.models.lookups import BuiltinLookup
#Field.register_lookup
class IsEmpty(BuiltinLookup):
lookup_name = 'isempty'
prepare_rhs = False
def as_sql(self, compiler, connection):
sql, params = compiler.compile(self.lhs)
condition = self.rhs if isinstance(self.rhs, bool) else bool(strtobool(self.rhs))
if condition:
return "%s IS NULL or %s = ''" % (sql, sql), params
else:
return "%s <> ''" % sql, params
You can then use it like this:
Name.objects.filter(alias__isempty=False)
this is another simple way to do it .
Name.objects.exclude(alias=None)