Directory iterator value as variable - c++

I am trying to transfer output of std:filesystem directory_iterator to vector or variable. Keep getting error: no operator "=" matches these operands -- operand types are: std::string = const std::filesystem
I am realively new to C++ and hit the wall at this point. Previously I have been using system commands but would like to avoid it in the future.
#include <string>
#include <iostream>
#include <filesystem>
#include <vector>
namespace fs = std::filesystem;
using namespace std;
int main()
{
string objectInDirectory = "Jabberwocky";
string dirlisted = "";
for (const auto & entry : fs::directory_iterator(dirlisted)) {
cout << "Next directory entry: " << entry.path() << endl;
objectInDirectory = entry.path();
}
getchar();
}

entry.path() returns a const std::filesystem::path&. This is not implicitly convertible to std::string, so you need to call its string function:
objectInDirectory = entry.path().string();
Conversion to string is not necessary; you could assign it to a std::filesystem::path instead without needing a conversion. This can be more ideal because there are better built-in path-manipulation tools for std::filesystem::path than std::string

Related

Use of sstream causing a deleted copy constructor

So I am a CS student working on a project for exception handling (Try/catch). My teacher told us to implement the sstream library so we could use it in a class that outputs a message that includes a passed parameter of type int. For some reason unknown to me, when I use it, or even when I declare a variable of type stringstream, it causes a compile error with error message:
"copy constructor of 'tornadoException' is implicitly deleted because field 'ss' has a deleted copy constructor"
Here is my code. I am at a loss.
main.cpp
#include <iostream>
#include <string>
#include <sstream>
#include "tornadoException.h"
using namespace std;
int main()
{
try{
int tornado = 0;
cout << "Enter distance of tornado: ";
cin >> tornado;
if(tornado > 2){
throw tornadoException(tornado);
}
else{
throw tornadoException();
}
}
catch(tornadoException tornadoObj){
cout << tornadoObj.what();
}
}
tornadoException.cpp
#include <iostream>
#include <string>
#include <sstream>
#include "tornadoException.h"
using namespace std;
tornadoException::tornadoException(){
message = "Tornado: Take cover immediately!";
}
tornadoException::tornadoException(int m){
ss << "Tornado: " << m << "miles away!; and approaching!";
message = ss.str();
}
string tornadoException::what(){
return message;
}
tornadoException.h
#ifndef tornadoException_h
#define tornadoException_h
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
class tornadoException{
public:
tornadoException();
tornadoException(int m);
string what();
private:
stringstream ss;
string message;
};
#endif
Alright, figured out the error but I'll leave up this post since I couldn't find the answer anywhere else. The problem was that I declared the stringstream buffer as a private variable in the class. The buffer needs to be declared locally within the function declaration it is being used in, in this case right before the loading of the buffer in the implementation file:
tornadoException::tornadoException(int m){
stringstream ss;
ss << "Tornado: " << m << " miles away!; and approaching!";
message = ss.str();
}
stringstream has a deleted copy constructor, which means that a stringstream object cannot be copied.
Since your tornadoException class has a stringstream variable, this means that your class cannot be copied either.
In your main function, you capture the exception by value, which means that you are copying it into the tornadoObj variable - which is not allowed.
Try changing the line
catch(tornadoException tornadoObj) to catch(tornadoException& tornadoObj) so that you're getting a reference to the exception instead of a copy of it.
This is actually a general rule: An exception shall always be caught by reference, not by copy: Core Guidelines E.15

I can't define a string in my C++ code in qt

My code is as follows.
#include "test.h"
#include "string"
#include "iostream"
using namespace std::string::find;
test::test(){
string str ("ffs test ffs");
string str2 ("test");
if (str.find(str2) != std::string::npos) {
std::cout << "found" << "\n";
} else {
std::cout << "not found" << "\n";
}
}
the issue I'm having is this, when trying to define a string in the C++ file qt states "unknown type name 'string'". Also on line 4 my 'import' highlights string as if it doesn't exist, despite it being an option the editor suggests to me while I'm typing it. What am I doing wrong here? Everything I find is to try and fix issues passing stuff to QStrings and nothing related to my issue as far as I can tell. I've tried both types of importing #include <thing> and #include "thing" on all the imports it doesn't seem to make a difference.
Use std::string instead of string.
#include "test.h"
#include <string>
#include <iostream>
test::test(){
std::string str ("ffs test ffs");
std::string str2 ("test");
if (str.find(str2) != std::string::npos) {
std::cout << "found" << "\n";
} else {
str::cout << "not found" << "\n";
}
}
Don't use using namespace (of course in your case, it wasn't a namespace, so that's another error), use <> for system headers.
After inclusion of the appropriate headers iostream, string etc, you can write:
using std::string;
This will bring in only string from the namespace std into your program.
And you can do this if you want to avoid typing std::string everywhere. You can do this for stream objects like cout, cin as well.
using std::cout;
using std::cin;
Use Scope operator :: in Your Code and Access manually to std class
std::string
it will help you !

How to parse UTF-8 Chinese string

I am trying to parse a std::string that might contain Chinese characters. For example for a string contains
哈囉hi你好hello
I want to separate them into 6 strings:哈, 囉, hi, 你, 好, hello. Right now the string is obtained by using getline() from a text file. Referencing this post How to use boost::spirit to parse UTF-8?, here's my current code:
#include <boost/regex/pending/unicode_iterator.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/range.hpp>
#include <iterator>
#include <iostream>
#include <ostream>
#include <cstdint>
#include <string>
using namespace boost;
using namespace std;
using namespace std::string_literals;
int main()
{
string str = u8"哈囉hi你好hello"; //actually got from getline()
auto &&utf8_text = str;
u8_to_u32_iterator<const char*>
tbegin(begin(utf8_text)), tend(end(utf8_text));
vector<uint32_t> result;
spirit::qi::parse(tbegin, tend, *spirit::standard_wide::char_, result);
for(auto &&code_point : result) {
cout << code_point << ";";
}
}
But got the error: call to 'begin' and 'end' is ambiguous.
It works when I directly declare auto &&utf8_text = u8"哈囉hi你好hello", but I cannot write in this way because the content of string is determined by getline().
I also tried this:
auto str = u8"你好,世界!";
auto &&utf8_text = str;
but still got error: no matching function for call to 'begin' and 'end'.
auto with string literals results in a char pointer. If you want std::string, you have to write it out.

c++ iterate through a vector of strings

So I recently discovered the use of map and vectors, however, I'm having trouble of trying to figure a way to loop through a vector containing strings.
Here's what I've tried:
#include <string>
#include <vector>
#include <stdio>
using namespace std;
void main() {
vector<string> data={"Hello World!","Goodbye World!"};
for (vector<string>::iterator t=data.begin(); t!=data.end(); ++t) {
cout<<*t<<endl;
}
}
and when I try to compile it, I get this error:
cd C:\Users\Jason\Desktop\EXB\Win32
wmake -f C:\Users\Jason\Desktop\EXB\Win32\exbint.mk -h -e
wpp386 ..\Source\exbint.cpp -i="C:\WATCOM/h;C:\WATCOM/h/nt" -w4 -e25 -zq -od -d2 -6r -bt=nt -fo=.obj -mf -xs -xr
..\Source\exbint.cpp(59): Error! E157: col(21) left expression must be integral
..\Source\exbint.cpp(59): Note! N717: col(21) left operand type is 'std::ostream watcall (lvalue)'
..\Source\exbint.cpp(59): Note! N718: col(21) right operand type is 'std::basic_string<char,std::char_traits<char>,std::allocator<char>> (lvalue)'
Error(E42): Last command making (C:\Users\Jason\Desktop\EXB\Win32\exbint.obj) returned a bad status
Error(E02): Make execution terminated
Execution complete
I tried the same method using map and it worked. The only difference was I changed the cout line to:
cout<<t->first<<" => "<<t->last<<endl;
Add iostream header file and change stdio to cstdio.
#include <iostream>
#include <string>
#include <vector>
#include <cstdio>
using namespace std;
int main()
{
vector<string> data={"Hello World!","Goodbye World!"};
for (vector<string>::iterator t=data.begin(); t!=data.end(); ++t)
{
cout<<*t<<endl;
}
return 0;
}
#include <iostream>
#include <vector>
#include <string>
int main()
{
std::vector<std::string> data = {"Hello World!", "Goodbye World!"};
for (std::vector<std::string>::iterator t = data.begin(); t != data.end(); t++) {
std::cout << *t << std::endl;
}
return 0;
}
Or with C++11 (or higher):
#include <iostream>
#include <vector>
#include <string>
typedef std::vector<std::string> STRVEC;
int main()
{
STRVEC data = {"Hello World!", "Goodbye World!"};
for (auto &s: data) {
std::cout << s << std::endl;
}
return 0;
}
From the Open Watcom V2 Fork-Wiki on the C++ Library Status page:
<string>
Mostly complete. Although there are no I/O operators, all other member functions and string operations are available.
A workaround (besides implementing the << operator) would be asking the string instances for the C string:
for (vector<string>::iterator t = data.begin(); t != data.end(); ++t) {
cout << t->c_str() << endl;
}
This of course only works as long as the strings don't contain zero byte values.
When I compile your code, I get:
40234801.cpp:3:17: fatal error: stdio: No such file or directory
#include <stdio>
^
You clearly have a header called "stdio" in your include path that you haven't shown us.
If you change that line to the standard #include <iostream>, then the only reported error is that you wrote void main() instead of int main(). Fix that, and it will build and run.
In passing, note also that using namespace should be avoided.
I found a solution to my own issue. Instead of using a c_str, I used std::string and switched to using the G++ compiler instead of Open Watcom
Instead of having:
char *someString="Blah blah blah";
I instead replaced it with:
string someString="Blah blah blah";
This way is much more efficient and easier.

C++ String - Out of scope error

I was trying to play around with Strings in a Hangman program that I'm writing and couldn't get them to work so tried working with them on a simpler basis and I'm still having no luck.
As far as I've read online in the references and what other people have said this code should work:
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
int main (int argc, char** argv){
string word = {"Hello"};
int length = strlen(word);
}
But I get this compiler error:
'string' was not declared in this scope
and consequently, 'word' is also not declared in scope.
Can anyone see what I'm doing wrong? I'm using the g++ compiler on Ubuntu if that makes a difference, no idea which version though.
You are confusing C and C++.
You included only C libraries, whereas std::string comes from the C++ header string. You'd have to write:
#include <string>
to use it. However, you'd then have to make other changes, such as not using strlen.
You should learn from your C++ book, not random posts on the internet (#lolirony)
C version
#include <string.h>
int main(void)
{
const char* word = "Hello";
const size_t length = strlen(word); // `size_t` is more appropriate than `int`
return 0;
}
C-like C++ version
#include <cstring>
using namespace std;
int main()
{
const char* word = "Hello";
const size_t length = strlen(word);
}
Idiomatic C++ version (recommended)
#include <string>
int main()
{
const std::string word = "Hello";
const std::size_t length = word.size();
}
'string' was not declared in this scope
You need to include the header <string> and refer to it as std::string. Also, strlen does not understand std::string or any user defined types, but you can use the size() method instead:
#include <string>
int main()
{
std::string word = "Hello";
size_t length = word.size();
}
<cstring> is the header for C++ support of C-style null-terminated strings. You should include <string>.
You haven't included the C++ string header in your project.
#include <string>
The libraries that you've included are all plain-C headers.
Additionally, strlen() doesn't work with a c++ string; you should use word.size() instead.
string is a specialization of standard class std::basic_string . It is declared in header <string>
So if you want "to play around with standard class std::string:" you need to include directive
#include <string>
Header <cstring> is not the same as header <string> and contains declarations of standard C functions such as strlen.
However there is no any sense to apply function strlen to an object of type std::string The compiler in this case will issue an error.
I advice you to play with the following code that to see the difference
#include <iostream>
#include <string>
#include <cstring>
int main (int argc, char** argv)
{
std::string word = "Hello";
std::string::size_type length = word.length();
std::cout << "Object word of type std::string has value "
<< word << " with length of " << length
<< std::endl;
std::cout << "The size of the object itself is " << sizeof( word ) << std::endl;
char another_word[] = "Hello";
size_t another_length = std::strlen( another_word );
std::cout << "Object another_word of type char [6] has value "
<< another_word << " with length of " << another_length
<< std::endl;
std::cout << "The size of the object itself is " << sizeof( another_word ) << std::endl;
}