How to count items' occurence in a List - list

Question

I am new to Dart. Currently I have a List of duplicate items, and I would like to count the occurence of them and store it in a Map.
var elements = ["a", "b", "c", "d", "e", "a", "b", "c", "f", "g", "h", "h", "h", "e", "a"];
I want to have a result like:
{
"a": 3,
"b": 2,
"c": 2,
"d": 2,
"e": 2,
"f": 1,
"g": 1,
"h": 3
}
I did some research and found a JavaScript solution, but I don't know how to translate it to Dart.
var counts = {};
your_array.forEach(function(x) { counts[x] = (counts[x] || 0)+1; });

Answer 1

Play around with this:
var elements = ["a", "b", "c", "d", "e", "a", "b", "c", "f", "g", "h", "h", "h", "e"];
var map = Map();
elements.forEach((element) {
if(!map.containsKey(element)) {
map[element] = 1;
} else {
map[element] += 1;
}
});
print(map);
What this does is:
loops through list elements
if your map does not have list element set as a key, then creates that element with a value of 1
else, if element already exists, then adds 1 to the existing key value
Or if you like syntactic sugar and one liners try this one:
var elements = ["a", "b", "c", "d", "e", "a", "b", "c", "f", "g", "h", "h", "h", "e"];
var map = Map();
elements.forEach((x) => map[x] = !map.containsKey(x) ? (1) : (map[x] + 1));
print(map);
There are many ways to achieve this in all programming languages!

Answer 2

The shorter way to count items' occurrence in a List
List of items. Count items equal 1.
List<int> lst = [0,1,1,1,0,8,8,9,1,0];
int res = lst.map((element) => element == 1 ? 1 : 0).reduce((value, element) => value + element);
List of objects. Count objects, which property age equals 1.
class Person {
int age;
Person(this.age);
}
List<Person> lst2 = [Person(1), Person(0), Person(1), Person(0)];
int res2 = lst2.map((element) => element.age == 1 ? 1 : 0).reduce((value, element) => value + element);

Answer 3

Use fold with a map:
final elements = ["a", "b", "c", "d", "e", "a", "b", "c", "f", "g", "h", "h", "h", "e", "a"];
var counts = elements.fold<Map<String, int>>({}, (map, element) {
map[element] = (map[element] ?? 0) + 1;
return map;
});
print(counts);
Out: {a: 3, b: 2, c: 2, d: 1, e: 2, f: 1, g: 1, h: 3}