I have a string with a version as .v_september (every month it will vary). In this i wanted to take the value after underscore, which means "sep" (First 3 letters alone).
By using the regex .v_(.*) i am able to take the complete month and not able to get the first 3 letters alone.
Can someone help me out how can I achieve this in Apache ANT.
Thanks !
Regex functions on properties are a bit awkward in native Ant (as opposed to working with text within files). Ant-contrib has the replaceregexp task, but I try to avoid ant-contrib whenever possible.
Instead, it can be accomplished with the loadfile task and a nested filter:
<property name="version" value=".v_september" />
<loadfile property="version.month.short">
<propertyresource name="version" />
<filterchain>
<tokenfilter>
<replaceregex pattern="\.v_(.{3}).*" replace="\1" />
</tokenfilter>
</filterchain>
</loadfile>
<echo message="${version.month.short}" />
Regarding the regex pattern, note how it needs to end with .*. This is because Ant doesn't have a "match" function that simply returns the content of a capture group. It's just running a replacement, so we need to replace everything in the string that isn't part of the group.
.* will capture everything and for limiting to capturing only three characters you need to write {3} instead of *. Also you should escape the . in the beginning of your regex to only match a literal dot. You can use this regex and capture from group1,
\.v_(.{3})
Demo
Related
I am trying to search and replace in VSCode in all the xml files. I am interested in the below line in all the files which has name "somekey"
<setting name="somekey" value="abc-def.google.xyz.com" />
<setting name="somekey" value="abc-xyz.google.xyz.com" />
I am trying to convert this line to
<setting name="somekey" value="abc-def-ghi.google.xyz.com" />
<setting name="somekey" value="abc-xyz-ghi.google.xyz.com" />
so far I have this
(<setting name="somekey" value="abc-)((.|n)*?.google.xyz.com). How do I make it so the group 1 includes everything until the first ".". Any pointers?
https://regex101.com/r/WeEkgQ/1
You can move the part matching until .google.xyz.com to the first group, and in the replacement use the 2 capture groups $1.ghi$2
To match the dot literally you have to escape it \. and note that the current pattern is not matching the closing />
(<setting name="somekey" value="abc-.*?)(\.google\.xyz\.com")
Regex demo
Note that this part (.|n) matches either any char or a n char. If you meant to use (.|\n) you could use [\s\S\r]+? instead of using the alternation to match over multiple lines making it a bit more efficient.
I am trying to replace the string with the below regex pattern but it is not getting replaced. I tried different combinations also but nothing worked. Any Idea?
<regex pattern="jre64\/1\.6\.0"
replacement="jre64/1.7.0" />
I have regex that accepts all the mobile user agents. But I want to negate this regex so that it accepts all possible desktop browsers.
<add input="{HTTP_USER_AGENT}" pattern="(android|bb\d+|meego).+mobile|avantgo|bada\/|blackberry|blazer|compal|elaine|fennec|hiptop|iemobile|ip(hone|od)|iris|kindle|lge |maemo|midp|mmp|mobile.+firefox|netfront|opera m(ob|in)i|palm( os)?|phone|p(ixi|re)\/|plucker|pocket|psp|series(4|6)0|symbian|treo|up\.(browser|link)|vodafone|wap|windows ce|xda|xiino" />
<add input="{HTTP_USER_AGENT}" pattern="^(1207|6310|6590|3gso|4thp|50[1-6]i|770s|802s|a wa|abac|ac(er|oo|s\-)|ai(ko|rn)|al(av|ca|co)|amoi|an(ex|ny|yw)|aptu|ar(ch|go)|as(te|us)|attw|au(di|\-m|r |s )|avan|be(ck|ll|nq)|bi(lb|rd)|bl(ac|az)|br(e|v)w|bumb|bw\-(n|u)|c55\/|capi|ccwa|cdm\-|cell|chtm|cldc|cmd\-|co(mp|nd)|craw|da(it|ll|ng)|dbte|dc\-s|devi|dica|dmob|do(c|p)o|ds(12|\-d)|el(49|ai)|em(l2|ul)|er(ic|k0)|esl8|ez([4-7]0|os|wa|ze)|fetc|fly(\-|_)|g1 u|g560|gene|gf\-5|g\-mo|go(\.w|od)|gr(ad|un)|haie|hcit|hd\-(m|p|t)|hei\-|hi(pt|ta)|hp( i|ip)|hs\-c|ht(c(\-| |_|a|g|p|s|t)|tp)|hu(aw|tc)|i\-(20|go|ma)|i230|iac( |\-|\/)|ibro|idea|ig01|ikom|im1k|inno|ipaq|iris|ja(t|v)a|jbro|jemu|jigs|kddi|keji|kgt( |\/)|klon|kpt |kwc\-|kyo(c|k)|le(no|xi)|lg( g|\/(k|l|u)|50|54|\-[a-w])|libw|lynx|m1\-w|m3ga|m50\/|ma(te|ui|xo)|mc(01|21|ca)|m\-cr|me(rc|ri)|mi(o8|oa|ts)|mmef|mo(01|02|bi|de|do|t(\-| |o|v)|zz)|mt(50|p1|v )|mwbp|mywa|n10[0-2]|n20[2-3]|n30(0|2)|n50(0|2|5)|n7(0(0|1)|10)|ne((c|m)\-|on|tf|wf|wg|wt)|nok(6|i)|nzph|o2im|op(ti|wv)|oran|owg1|p800|pan(a|d|t)|pdxg|pg(13|\-([1-8]|c))|phil|pire|pl(ay|uc)|pn\-2|po(ck|rt|se)|prox|psio|pt\-g|qa\-a|qc(07|12|21|32|60|\-[2-7]|i\-)|qtek|r380|r600|raks|rim9|ro(ve|zo)|s55\/|sa(ge|ma|mm|ms|ny|va)|sc(01|h\-|oo|p\-)|sdk\/|se(c(\-|0|1)|47|mc|nd|ri)|sgh\-|shar|sie(\-|m)|sk\-0|sl(45|id)|sm(al|ar|b3|it|t5)|so(ft|ny)|sp(01|h\-|v\-|v )|sy(01|mb)|t2(18|50)|t6(00|10|18)|ta(gt|lk)|tcl\-|tdg\-|tel(i|m)|tim\-|t\-mo|to(pl|sh)|ts(70|m\-|m3|m5)|tx\-9|up(\.b|g1|si)|utst|v400|v750|veri|vi(rg|te)|vk(40|5[0-3]|\-v)|vm40|voda|vulc|vx(52|53|60|61|70|80|81|83|85|98)|w3c(\-| )|webc|whit|wi(g |nc|nw)|wmlb|wonu|x700|yas\-|your|zeto|zte\-)" />
Can anybody provide the solution for the same ?
Some (few) regex flavors allow to use variable length lookaheads (.net for example).
If you have such one, you can use
^(?!.*(?:pattern)).*$
for your first pattern (it tests for occurences anywhere in the string), and
^(?!pattern)
for the second one (you can remove ^ from pattern there).
Your second pattern does not contain any variable length content - thus it should work in every regex flavor allowing to use negative lookaheads (?!...)
I need to replace different values of receiveTimeOut attribute with a receiveTimeOut="59:59:59"
Can wild card search be used to achieve this task, in Visual Studio?
<endpoint receiveTimeOut="10:10:20" someOtherProperty="x1" yetAnotherProperty="y1" />
<endpoint receiveTimeOut="10:50:20" someOtherProperty="x2" yetAnotherProperty="y2" />
...
<endpoint receiveTimeOut="30:50:20" someOtherProperty="x3" yetAnotherProperty="y3" />
I tried: using wildcard option in Find & Replace dialog, receiveTimeOut="*" but this selects complete line, receiveTimeOut="10:10:20" someOtherProperty="x1" yetAnotherProperty="y1" />
As you might have guessed, I am editing WCF service web.config and have to do this task manually & repeatedly.
Using the regex option...
Find: <endpoint receiveTimeOut="[^"]+"
Then...
Replace: <endpoint receiveTimeOut="59:59:59"
The [^"]+ part uses a negative character class that matches any character except for a double quote. The + will match it one or more times.
It turns out that this is actually quite simple to do with a regular expression.
Just use .* for your wildcard and check Use regular expressions.
For example, I have some grids and I want to find columns with an attribute of Visible="False" so a string might be:
telerik:GridBoundColumn name="name" Visible="False"
My search string would be: "GridBoundColumn.*Visible="False""
Done.
Ahmad's is the way to go. But as a naive and bit different alternative, one could search:
receiveTimeOut="[0-9]*\:[0-9]*\:[0-9]*"
This requires the data between the double quotes of the receiveTimeOut value has two colons (which are escaped) with any number of digits about them.
From ant, we want to extract a line from an old /etc/shadow file, capturing the line for a specific user name, such as "manager". This is part of a backup/restore operation. What we used previously was not specific enough, so it would match users like "mymanager", so we tried to tighten it down by anchoring the start of the string to beginning of the line (typically "^"). This definitely did not work as we expected.
How can we anchor so that we get an exact match for a username? -- answered below.
First attempt, which gave the wrong result if we had a user of "mymanager" in the /etc/shadow file copy:
<loadfile property="oldPasswords" srcFile="${backup.dir}/shadow"/>
<propertyregex property="manager.backup" input="${oldPasswords}"
regexp="(manager\:.*)" select="\1" casesensitive="true" />
Second attempt, which failed because "^" is not interpreted in the normal regular expression way by default:
<loadfile property="oldPasswords" srcFile="${backup.dir}/shadow"/>
<propertyregex property="manager.backup" input="${oldPasswords}"
regexp="^(manager\:.*)" select="\1" casesensitive="true" />
Kobi suggested adding -> flags="m" <- which sounded good but ant reported that the flags option is not supported by propertyregex.
The final, successful, approach required inserting "(?m)" at the beginning of the regexp: That was the essential change.
<propertyregex property="manager.backup" input="${oldPasswords}"
regexp="(?m)^manager:.*$" select="\0" casesensitive="true" />
The regexp with propertyregex appears to follow the rules in this documentation of regular expressions in Java (search for "multiline" for example): http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html
Check the above document if you have similar questions about how to make propertyregex and regexp do what you want them to do!
THANKS! Solved.
Alan Carwile
I think the m(ultiline) flag is what you want to use and will give the start-of-line anchor the right behavior. It's possible to change flags within the regular expression with the syntax (?<flagstoturnon>-<flagstoturnoff>). So in your case, adding (?m) to the start of the regular expression (before the caret) should work.