Append new xml node under existing xml nodes using xslt - xslt

Question

I am trying to append a new XML node under existing XML node but i wasn't able to achieve the desired result.
Please find my below XML,
<Root>
<Row>
<A1>0</A1>
<A2>1</A2>
<Preferred_First_Name>aaaa</Preferred_First_Name>
<Preferred_Last_Name>yyyy</Preferred_Last_Name>
<location>xxxx</location>
<ID>12345</ID>
</Row>
</Root>
I want to modify the above XML in such a way that Preferred_First_Name, Preferred_Last_Name and location node need to be under a new XML tag "Data".
The desired output should be like below,
<Root>
<Row>
<A1>0</A1>
<A2>1</A2>
<Data>
<Preferred_First_Name>aaaa</Preferred_First_Name>
<Preferred_Last_Name>yyyy</Preferred_Last_Name>
<location Descriptor="xxxx">
<ID type="ID">xxxx</ID>
<ID type="LocationID">xxxx</ID>
</location>
</Data>
<ID>12345</ID>
</Row>
</Root>
Can someone please help?

Answer 1

you can use below
<?xml version="1.0" encoding="utf-16"?>
<xsl:stylesheet xmlns:xalan="http://xml.apache.org/xalan" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
<xsl:template match="Root">
<xsl:element name="Root">
<xsl:call-template name="Row" />
</xsl:element>
</xsl:template>
<xsl:template name="Row">
<xsl:element name="Row">
<xsl:copy-of select="Row/A1"/>
<xsl:copy-of select="Row/A2"/>
<xsl:element name="Data">
<xsl:copy-of select="Row/Preferred_First_Name"/>
<xsl:copy-of select="Row/Preferred_Last_Name"/>
<xsl:element name="location">
<xsl:attribute name="Descriptor">
<xsl:value-of select="Row/location"/>
</xsl:attribute>
<xsl:element name="ID">
<xsl:attribute name="type">
<xsl:value-of select="'ID'"/>
</xsl:attribute>
<xsl:value-of select="Row/location"/>
</xsl:element>
<xsl:element name="ID">
<xsl:attribute name="type">
<xsl:value-of select="'LocationID'"/>
</xsl:attribute>
<xsl:value-of select="Row/location"/>
</xsl:element>
</xsl:element>
<xsl:copy-of select="Row/ID"/>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Please let me know this helps you

Answer 2

If it is okay to put <ID> after <Data> mentioned by Tim C, then the optimized solution can be:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Row">
<Row>
<xsl:apply-templates select="child::node()[not(self::Preferred_First_Name or self::Preferred_Last_Name
or self::location)]" />
<Data>
<xsl:apply-templates select="child::node()[self::Preferred_First_Name or self::Preferred_Last_Name
or self::location]"/>
</Data>
</Row>
</xsl:template>
</xsl:stylesheet>